/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 117 Prove that $$ \lim _{n \righ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Prove that $$ \lim _{n \rightarrow \infty} \sqrt[n]{n}=1 $$

Short Answer

Expert verified
The limit is 1 because \( \frac{1}{n} \ln(n) \to 0 \) as \( n \to \infty \), making \( \sqrt[n]{n} \to 1 \).

Step by step solution

01

Understand the Limit Definition

The problem asks us to find \( \lim_{n \to \infty} \sqrt[n]{n} \). We want to show that as \( n \) becomes very large, the \( n \)-th root of \( n \) approaches 1. This means demonstrating that for any small positive number \( \epsilon \), there exists a large number \( N \) such that for all \( n > N \), \(|\sqrt[n]{n} - 1| < \epsilon \).
02

Consider the Natural Logarithm

To simplify the process, take the natural logarithm of \( \sqrt[n]{n} \). We know that \( \sqrt[n]{n} = n^{1/n} \). Thus, we have \( \ln(\sqrt[n]{n}) = \ln(n^{1/n}) = \frac{1}{n} \ln(n) \).
03

Analyze the Limit of the Logarithm

Now examine the limit \( \lim_{n \to \infty} \frac{1}{n} \ln(n) \). As \( n \) approaches infinity, the numerator \( \ln(n) \) grows but much slower than the linear term in the denominator \( n \). Thus, \( \frac{\ln(n)}{n} \to 0 \).
04

Exponential Function and the Original Expression

Since \( \ln(\sqrt[n]{n}) \to 0 \) as \( n \to \infty \), this implies that \( \sqrt[n]{n} = e^{\ln(\sqrt[n]{n})} = e^0 = 1 \) in the limit. Hence, \( \lim_{n \to \infty} \sqrt[n]{n} = 1 \).
05

Justify with the \(\epsilon\)-\(\delta\) Definition

For any \( \epsilon > 0 \), since \( \frac{1}{n} \ln(n) \to 0 \), there exists an \( N \) such that for all \( n > N \), \( \left| \frac{1}{n} \ln(n) \right| < \epsilon \). Therefore, \(|e^{\frac{1}{n} \ln(n)} - 1| < \epsilon\), satisfying the definition of the limit.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Function
The exponential function is a mathematical function denoted as \( e^x \), where \( e \) is approximately 2.71828, known as Euler's number. It is a key player in calculus and analysis due to its unique properties. One important feature of the exponential function is that its derivative is equal to itself, making it highly useful for solving differential equations.
  • The exponential function grows rapidly and, for positive exponents, is always increasing.
  • It can transform logarithmic expressions back to their original numbers, thanks to the property \( e^{ ext{ln}(x)} = x \).
  • In limits and growth processes, exponential functions describe natural growth phenomena, such as population growth or decay.
In context of the given exercise, the exponential function is used to revert the logarithmic transformation. When \( \ln(\sqrt[n]{n}) \to 0 \), the exponential of 0 is \( e^0 = 1 \). This shows that \( \sqrt[n]{n} = e^{\ln(\sqrt[n]{n})} \to 1 \) as \( n \to \infty \).
Natural Logarithm
The natural logarithm, denoted as \( \ln(x) \), is a logarithm to the base \( e\). This means it is determined by finding the power to which \( e \) must be raised to produce that number \( x \).
  • It's inversely related to the exponential function, thus \( \ln(e^x) = x \) and \( e^{\ln(x)} = x \).
  • The natural logarithm is used extensively in calculus because its derivative is a simple form, \( \frac{1}{x} \).
  • Logarithms, including natural logs, convert multiplications into additions, making complex calculations simpler.
In the exercise, we use the natural logarithm to simplify the expression \( \sqrt[n]{n} = n^{1/n} \). Taking natural logarithms gives \( \ln(n^{1/n}) = \frac{1}{n} \ln(n) \). This approach allows us to analyze a simpler, linear-in-\( n \) function, which helps in taking the limit as \( n \to \infty \).
Epsilon-Delta Definition
The epsilon-delta definition is a formal mathematical way to define the limit of a function. It states that for every small number \( \epsilon > 0 \), there exists a \( \delta > 0 \) such that whenever the distance from the point \( x \) to the point of interest \( c \) is less than \( \delta \) (but not zero), the distance from \( f(x) \) to \( L \) is less than \( \epsilon \). In simpler terms, it ensures the values of the function get as close as needed to the limit as \( x \) approaches \( c \).
  • This definition provides a precise framework to verify the limits of sequences and functions.
  • "Epsilon" represents any small positive number, while "delta" corresponds to a value ensuring the function stays close to the limit.
  • The concept is foundational for understanding continuity and the behavior of functions as they approach a given point.
In the context of proving \( \lim _{n \rightarrow \infty} \sqrt[n]{n}=1 \), the \( \epsilon-\delta \) definition is used to show that \( \sqrt[n]{n} \) can be made arbitrarily close to 1 for sufficiently large \( n \). By demonstrating that \( \left|e^{\frac{1}{n} \ln(n)} - 1\right| < \epsilon \) for large \( n \), we confirm the sequence converges to the limit of 1.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that \begin{equation} \quad \text { a. } \cosh i \theta=\cos \theta, \quad \text { b. } \sinh i \theta=i \sin \theta\end{equation}

Estimating Pi About how many terms of the Taylor series for \(\tan ^{-1} x\) would you have to use to evaluate each term on the right- hand side of the equation \begin{equation} \pi=48 \tan ^{-1} \frac{1}{18}+32 \tan ^{-1} \frac{1}{57}-20 \tan ^{-1} \frac{1}{239} \end{equation} with an error of magnitude less than \(10^{-6}\) ? In contrast, the convergence of \(\sum_{n=1}^{\infty}\left(1 / n^{2}\right)\) to \(\pi^{2} / 6\) is so slow that even 50 terms will not yield two-place accuracy.

The estimate \(\sqrt{1+x}=1+(x / 2)\) is used when \(x\) is small. Estimate the error when \(|x|<0.01\)

How many terms of the convergent series \(\sum_{n=4}^{\infty} 1 /\left(n(\ln n)^{3}\right)\) should be used to estimate its value with error at most 0.01\(?\)

\begin{equation} \begin{array}{l}{\text { Using a CAS, perform the following steps to aid in answering }} \\ {\text { questions (a) and (b) for the functions and intervals in Exercises }} \\ {57-62 .}\\\\{\text { Step } I : \text { Plot the function over the specified interval. }} \\ {\text { Step } 2 : \text { Find the Taylor polynomials } P_{1}(x), P_{2}(x), \text { and } P_{3}(x) \text { at }} \\ {x=0}\\\\{\text { Step } 3 : \text { Calculate the }(n+1) \text { st derivative } \int^{(n+1)}(c) \text { associat- }} \\ {\text { ed with the remainder term for each Taylor polynomial. Plot }} \\ {\text { the derivative as a function of } c \text { over the specified interval }} \\ {\text { and estimate its maximum absolute value, } M .}\\\\{\text { Step } 4 : \text { Calculate the remainder } R_{n}(x) \text { for each polynomial. }} \\ {\text { Using the estimate } M \text { from Step } 3 \text { in place of } f^{(n+1)}(c), \text { plot }} \\ {R_{n}(x) \text { over the specified interval. Then estimate the values of }} \\ {x \text { that answer question (a). }}\\\\{\text { Step } 5 : \text { Compare your estimated error with the actual error }} \\ {E_{n}(x)=\left|f(x)-P_{n}(x)\right| \text { by plotting } E_{n}(x) \text { over the specified }} \\ {\text { interval. This will help answer question (b). }} \\ {\text { Step } 6 : \text { Graph the function and its three Taylor approxima- }} \\ {\text { tions together. Discuss the graphs in relation to the informa- }} \\ {\text { tion discovered in Steps } 4 \text { and } 5 .}\end{array} \end{equation} $$f(x)=\frac{x}{x^{2}+1}, \quad|x| \leq 2$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.