Chapter 10: Problem 102
Assume that each sequence converges and find its limit. $$ a_{1}=-1, \quad a_{n+1}=\frac{a_{n}+6}{a_{n}+2} $$
Short Answer
Expert verified
The limit of the sequence is 2.
Step by step solution
01
Define the Limit
Let's assume that the limit of the sequence \( a_n \) as \( n \to \infty \) is \( L \). Since the sequence converges, both \( a_n \) and \( a_{n+1} \) tend towards \( L \).
02
Set Up the Limit Equation
By the definition of a limit, we set the recursive formula to the limit: \[ L = \frac{L + 6}{L + 2} \]This equation comes from assuming that as \( n \to \infty \), \( a_{n+1} \) tends to \( L \) as \( a_n \) does.
03
Clear the Fraction
To clear the fraction, multiply both sides of the equation by \( L + 2 \):\[ L(L + 2) = L + 6 \]
04
Expand and Simplify
Expand the left side and simplify the equation:\[ L^2 + 2L = L + 6 \]Subtract \( L \) from both sides:\[ L^2 + L = 6 \]
05
Solve the Quadratic Equation
This is a quadratic equation of the form \( L^2 + L - 6 = 0 \). To find \( L \), factor the quadratic equation:\[ (L + 3)(L - 2) = 0 \]Set each factor to zero and solve for \( L \):\[ L + 3 = 0 \quad \Rightarrow \quad L = -3 \]\[ L - 2 = 0 \quad \Rightarrow \quad L = 2 \]
06
Determine the Valid Limit
The limit must make sense in the context of the sequence's starting value \( a_1 = -1 \). Testing both potential limits:- For \( L = -3 \), at \( a_1 = -1 \), the sequence won't reach \( -3 \).- For \( L = 2 \), this is possible given the behavior of the recursive function. Thus, the limit is \( L = 2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Convergence
Convergence is a fundamental concept in mathematics related to sequences and series. When we discuss the convergence of a sequence, we are essentially looking for a number—often called the limit—that the terms of the sequence approach as the number of terms increases. A sequence is said to converge to a limit if, as the sequence progresses, the terms get infinitely close to a certain fixed number. In more technical terms, a sequence \( \{a_n\} \) converges to a limit \( L \) if, for every positive number \( \epsilon \), there exists an integer \( N \) such that for all \( n > N \), \( |a_n - L| < \epsilon \). Converging sequences are important because they allow us to make predictions and understand the long-term behavior of a sequence. In our example exercise, we assume the sequence \( a_n \) converges to a limit \( L \). Thus, starting from the given recursive relation \( a_{n+1} = \frac{a_n + 6}{a_n + 2} \), we are able to calculate \( L \) by solving the equation \( L = \frac{L + 6}{L + 2} \).
Recursive sequences
Recursive sequences are sequences where each term is defined based on the preceding terms. They are like a chain reaction, where one term is used to calculate the next. This is a common way to build sequences in mathematics when direct formulas are not available.A recursive sequence is typically defined by an initial term, such as \( a_1 = -1 \) in our original exercise, and a recursion formula like \( a_{n+1} = \frac{a_n + 6}{a_n + 2} \). This formula tells us "create the next term by plugging the current term into this formula."Understanding recursive sequences involves recognizing that you need a starting point and a rule to follow for subsequent terms. It's akin to programming, where you start with initial conditions and then loop through a process to generate values. Graphs and tables can sometimes help in visualizing how recursive sequences grow or shrink. The key is to find out if these sequences reach a steady state, which circles back to how we determine their convergence.
Quadratic equation solving
Solving quadratic equations is a vital algebra skill that often appears when dealing with sequences and series. A quadratic equation is generally expressed in the form \( ax^2 + bx + c = 0 \). In the context of finding limits of sequences, once we equate the recursive sequence formula to its limit (like in our exercise resulting in \( L^2 + L - 6 = 0 \)), we land on a quadratic equation. Solving these equations can be done by various methods:
- Factoring: If the quadratic can easily be expressed as a product of two binomials, this method is straightforward. In our exercise, \((L + 3)(L - 2) = 0\) is the factored form.
- Quadratic Formula: When factoring is difficult, using the formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) can be a reliable method.
- Completing the Square: This method involves rewriting the equation to make one side a perfect square trinomial, which is useful when other methods are cumbersome.