Chapter 1: Problem 5
In Exercises \(5-30,\) find an appropriate graphing software viewing window for the given function and use it to display its graph. The window should give a picture of the overall behavior of the function. There is more than one choice, but incorrect choices can miss important aspects of the function. $$ f(x)=x^{4}-4 x^{3}+15 $$
Short Answer
Step by step solution
Understanding the Function
Identify Critical Points
Analyze Intervals and End Behavior
Determine Viewing Window
Graph the Function
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Critical Points
For the given function, we start by finding its derivative: \( f'(x) = 4x^3 - 12x^2 \).
Setting the derivative equal to zero helps us find the critical points:
- Factor the equation: \( 4x^2(x - 3) = 0 \)
- This gives critical points at \( x = 0 \) and \( x = 3 \)
- At \( x = 0 \), \( f(0) = 15 \)
- At \( x = 3 \), \( f(3) = -12 \)
End Behavior
For \( f(x) = x^4 - 4x^3 + 15 \), the highest degree term is \( x^4 \). This term determines that:
- The graph will rise continually as \( x \) goes to both positive and negative infinity
- It opens upwards on both ends since \( x^4 \) is positive
Derivative Analysis
For \( f(x) = x^4 - 4x^3 + 15 \), the critical points come from \( f'(x) = 4x^3 - 12x^2 = 0 \). Besides finding the zero points, checking the sign of the derivative in different intervals (derived from these points) will tell us more:
- If \( f'(x) > 0 \), \( f(x) \) is increasing in those intervals
- If \( f'(x) < 0 \), \( f(x) \) is decreasing
- Choose test values around the intervals set by \( x = 0 \) and \( x = 3 \) to identify behavior
Viewing Window Selection
For \( f(x) = x^4 - 4x^3 + 15 \), essential factors include capturing:
- The interval around critical points \( x = 0 \) and \( x = 3 \)
- End behavior showing rising trends on both graph sides
- The y-axis range \([-20, 20]\) helps reveal how the function rises or falls around these points