/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 Use any method to evaluate the i... [FREE SOLUTION] | 91Ó°ÊÓ

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Use any method to evaluate the integrals in Exercises \(63-68\) $$ \int \frac{\tan ^{2} x}{\csc x} d x $$

Short Answer

Expert verified
\( \sec x + \cos x + C \) is the integral solution.

Step by step solution

01

Simplify the Integral

We begin by rewriting the given integral \( \int \frac{\tan^2 x}{\csc x} \, dx \). Recall that \( \tan x = \frac{\sin x}{\cos x} \) and \( \csc x = \frac{1}{\sin x} \). Thus, \( \frac{\tan^2 x}{\csc x} = \frac{\sin^2 x}{\cos^2 x} \times \sin x = \frac{\sin^3 x}{\cos^2 x} \). So the integral becomes \( \int \frac{\sin^3 x}{\cos^2 x} \, dx \).
02

Rewrite Using Substitution Method

Let's make the substitution \( u = \cos x \), which implies \( du = -\sin x \, dx \) or \( -du = \sin x \, dx \). Substitute in the integral to get \( \int \frac{\sin^2 x \cdot \sin x}{\cos^2 x} \, dx = \int \frac{(1 - \cos^2 x) \cdot \sin x}{\cos^2 x} \, dx \). Then it becomes \( \int \frac{1 - u^2}{u^2} (-du) \).
03

Simplify and Integrate

Now simplify the expression: \( \int \left( \frac{1}{u^2} - 1 \right) (-du) = \int \left( -u^{-2} + 1 \right) \, du \). Integrate term by term: \( \int -u^{-2} \, du = u^{-1} = \frac{1}{u} \) and \( \int 1 \, du = u \). Thus, the integral is \( \frac{1}{u} + u + C \).
04

Back Substitute

Substitute back \( u = \cos x \) into the integrated expression to find the original variable form: \( \frac{1}{\cos x} + \cos x + C = \sec x + \cos x + C \).
05

Verify the Solution

Differentiate the result \( \sec x + \cos x + C \) to verify it equals the original integrand. Differentiating, \( \frac{d}{dx}(\sec x) = \sec x \tan x \) and \( \frac{d}{dx}(\cos x) = -\sin x \). Combine these: \( \sec x \tan x - \sin x \). Substitute \( \text{Original integrand } \left( \frac{\tan^2 x}{\csc x} \right) = \frac{\sin^3 x}{\cos^2 x} \). The derivative validates the integration was performed correctly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Integration
Trigonometric integration involves integrating functions that contain trigonometric identities such as sine, cosine, tangent, and so forth. Knowing trigonometric identities can simplify these integrals significantly. For instance, in the given exercise, we need to evaluate
  • \( \int \frac{\tan^2 x}{\csc x} \, dx \)
By recognizing that \( \tan x \) and \( \csc x \) can be rewritten in terms of \( \sin x \) and \( \cos x \), we can make it more approachable by using
  • \( \tan x = \frac{\sin x}{\cos x} \)
  • \( \csc x = \frac{1}{\sin x} \)
Thus, by substituting these values, the integral can be simplified to \( \int \frac{\sin^3 x}{\cos^2 x} \, dx \), making it much easier to evaluate. This is where the connection to the trigonometric identities becomes vital in the problem-solving process.
Understanding these identities is helpful in converting the integrals into more manageable forms.
Substitution Method
The substitution method is a technique used to simplify integrals by making a substitution for a part of the integrand that makes it easier. Here, the substitution method was employed effectively by letting \( u = \cos x \). This substitution transforms the variables and expressions, making the integration step straightforward.
With this substitution, \( du = -\sin x \, dx \), leading to an expression \( -du = \sin x \, dx \) that replaces the original variable. The integral \( \int \frac{\sin^3 x}{\cos^2 x} \, dx \) becomes \( \int \frac{1 - u^2}{u^2} (-du) \).Integrals involving substitution are particularly handy when dealing with functions that exhibit symmetry or have repetitive patterns. It allows us to focus on a smaller or more consistent part of the function, simplifying the integration process.
After this transformation, the problem becomes simpler, and we can integrate term by term and then substitute back to the original variable.
Definite and Indefinite Integrals
In calculus, integrals are of two kinds: definite and indefinite. The exercise above involved an indefinite integral, where the result includes a constant of integration \( C \). Indefinite integrals, unlike definite integrals, provide a general solution without specific limits.Understanding whether an integral is definite or indefinite helps determine the method and solution format. While definite integrals offer a specific numerical value representing the area under a curve between two points, indefinite integrals represent a family of functions. In this exercise, the solution is given as \( \sec x + \cos x + C \). This suggests that the antiderivative includes an arbitrary constant \( C \), representing an entire family of solutions.
It's crucial to include this constant when solving indefinite integrals to account for all potential solutions that may satisfy the initial function before differentiation.

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Most popular questions from this chapter

Sine-integral function The integral $$\operatorname{Si}(x)=\int_{0}^{x} \frac{\sin t}{t} d t,$$ called the sine-integral function, has important applications in optics. \(\begin{equation} \begin{array}{l}{\text { a. Plot the integrand }(\sin t) / t \text { for } t>0 . \text { Is the sine-integral }} \\ \quad {\text { function everywhere increasing or decreasing? Do you think }} \\ \quad {\text { Si }(x)=0 \text { for } x>0 ? \text { Check your answers by graphing the }} \\ \quad {\text { function Si }(x) \text { for } 0 \leq x \leq 25 .} \\ {\text { b. Explore the convergence of }}\end{array} \end{equation}\) $$\int_{0}^{\infty} \frac{\sin t}{t} d t.$$ If it converges, what is its value?

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Three people are asked their opinion in a poll about a particular brand of a common product found in grocery stores. They can answer in one of three ways: "Like the product brand" (L), "Dislike the product brand" (D), or "Undecided" (U). For each outcome, the random variable \(X\) assigns the number of L's that appear. $$ \begin{array}{l}{\text { a. Find the set of possible outcomes and the range of } X .} \\ {\text { b. Create a probability bar graph for } X \text { . }} \\\ {\text { c. What is the probability that at least two people like the product }} \\ {\text { brand? }} \\ {\text { d. What is the probability that no more than one person dislikes }} \\ {\text { the product brand? }}\end{array} $$

Use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integrals for convergence. If more than one method applies, use whatever method you prefer. $$\int_{0}^{\infty} \frac{d \theta}{1+e^{\theta}}$$

The integrals converge. Evaluate the integrals without using tables. $$\int_{0}^{2} \frac{d x}{\sqrt{|x-1|}}$$

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