/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Evaluate the integrals by making... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the integrals by making a substitution (possibly trigonometric) and then applying a reduction formula. \(\int_{0}^{\sqrt{3 / 2}} \frac{d y}{\left(1-y^{2}\right)^{5 / 2}}\)

Short Answer

Expert verified
Perform a trigonometric substitution and use the reduction formula; then evaluate bounds for substitution result.

Step by step solution

01

Identify the Trigonometric Substitution

For the integral \( \int \frac{d y}{\left(1-y^{2}\right)^{5/2}} \), we observe that the substitution \( y = \sin(\theta) \) could be useful because it simplifies the form \( 1-y^2 \) to \( \cos^2(\theta) \).
02

Substitute and Simplify the Integral

With \( y = \sin(\theta) \), \( dy = \cos(\theta) d\theta \). Then \( 1 - y^2 = \cos^2(\theta) \). The integral becomes:\[\int \frac{\cos(\theta) d\theta}{\cos^5(\theta)} = \int \sec^4(\theta) d\theta.\]
03

Use a Reduction Formula for \( \sec^n(\theta) \)

A known reduction formula for \( \sec^n(\theta) \) is:\[\int \sec^n(\theta) d\theta = \frac{\sec^{n-2}(\theta) \tan(\theta)}{n-1} + \frac{n-2}{n-1} \int \sec^{n-2}(\theta) d\theta.\]Applying this, we get:\[\int \sec^4(\theta) d\theta = \frac{\sec^2(\theta) \tan(\theta)}{3} + \frac{2}{3} \int \sec^2(\theta) d\theta.\]
04

Integrate \( \sec^2(\theta) \)

Since \( \int \sec^2(\theta) d\theta = \tan(\theta) + C \), the remaining term becomes \( \frac{2}{3} \tan(\theta) \).
05

Combine Terms and Back-Substitute \( y \)

Combine the results:\[\frac{\sec^2(\theta) \tan(\theta)}{3} + \frac{2}{3} \tan(\theta) = \frac{\tan(\theta) \sec^2(\theta) + 2\tan(\theta)}{3} = \frac{\tan(\theta)(\sec^2(\theta) + 2)}{3}.\]Substitute back \( \theta \) using \( y = \sin(\theta) \) so \( \theta = \arcsin(y) \). Then, \( \tan(\theta) = \frac{y}{\sqrt{1-y^2}} \) and \( \sec(\theta) = \frac{1}{\sqrt{1-y^2}} \).
06

Evaluate Definite Integral with Limits

Substitute the limits of integration:- When \( y = 0 \), \( \theta = 0 \); thus the expression evaluates to 0.- When \( y = \sqrt{3/2} \), \( \theta = \arcsin(\sqrt{3/2}) \); evaluate the expression.Thus, the integral evaluates, after simplifications, into a specific numerical value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reduction Formula
Reduction formulas are extremely helpful when dealing with integrals of powers of trigonometric functions. These formulas allow us to reduce the power of a trigonometric function in an integral, making it easier to evaluate.
For instance, in the problem where we need to integrate \( \sec^4(\theta) \), the reduction formula used was: \[\int \sec^n(\theta) \, d\theta = \frac{\sec^{n-2}(\theta) \tan(\theta)}{n-1} + \frac{n-2}{n-1} \int \sec^{n-2}(\theta) \, d\theta.\]
  • Reduction formulas break down complex integrals into simpler parts that can be tackled with ease.
  • They are crucial for integrals involving repeated trigonometric functions, as seen in reductions such as \( \sec^4(\theta) \) to \( \sec^2(\theta) \).
Recognizing when to use a reduction formula will take practice, but focusing on powers of trigonometric functions is a good indicator that one might be necessary. Keeping a reference of common reduction formulas handy can be incredibly useful during evaluations.
Definite Integrals
Definite integrals provide the value of an integral on a specific interval, giving us a numerical result rather than a general form. When evaluating definite integrals, we perform the integration process and then apply the given limits to find the specific numerical value.
In the exercise, after finding the antiderivative, limits were substituted:
  • The lower limit \( y = 0 \) resulted in a simpler evaluation as it usually does in trigonometric substitutions, simplifying to zero.
  • The upper limit \( y = \sqrt{3/2} \) provided a more complex evaluation due to the nature of the substituting function.
It’s crucial to translate the limits appropriately when a substitution changes the original variable, as was done through the transformation \( y = \sin(\theta) \). Trigonometric relationships and inversions, like using \( \arcsin \), are often necessary to connect the original and the substituted variable ranges.
Trigonometric Identities
Trigonometric identities are fundamental tools in calculus, especially when evaluating integrals. They simplify complicated expressions and allow the use of trigonometric substitution effectively.
For example, the identity \( 1 - \sin^2(\theta) = \cos^2(\theta) \) was vital for the initial substitution, reformulating the integral into a manageable form.
  • Basic identities like \( \sin^2(\theta) + \cos^2(\theta) = 1 \) are frequently used to alter integrals into simpler terms.
  • For derivatives or integrals involving \( \sec \theta \) and \( \tan \theta \), identities like \( \sec^2(\theta) = 1 + \tan^2(\theta) \) are indispensable.
These identities are not only shortcuts but also necessary transitions that help in applications beyond integration, such as solving equations or finding limits. Mastery of these identities thus facilitates smoother progression through calculus problems.

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