/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 The instructions for the integra... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The instructions for the integrals in Exercises \(1-10\) have two parts, one for the Trapezoidal Rule and one for Simpson's Rule. I. Using the Trapezoidal Rule a. Estimate the integral with \(n=4\) steps and find an upper bound for \(\left|E_{T}\right| .\) b. Evaluate the integral directly and find \(\left|E_{T}\right|\) c. Use the formula (( true value)) \(\times 100\) to express \(\left|E_{T}\right|\) as \right.\right. a percentage of the integral's true value. II. Using Simpson's Rule a. Estimate the integral with \(n=4\) steps and find an upper bound for \(\left|E_{S}\right| .\) b. Evaluate the integral directly and find \(\left|E_{S}\right|\) c. Use the formula ( \(\left|E_{S}\right| /(\) true value) \() \times 100\) to express \(\left|E_{S}\right|\) as a percentage of the integral's true value. $$ \int_{0}^{2}\left(t^{3}+t\right) d t $$

Short Answer

Expert verified
The integral value is 6; Trapezoidal error is \(|E_T|\approx0.085\); Simpson's error \(|E_S|=0\).

Step by step solution

01

Set up the Trapezoidal Rule

To estimate the integral \( \int_{0}^{2}(t^3 + t) \ dt \) using the Trapezoidal Rule with \( n = 4 \), divide the interval \([0, 2]\) into 4 equal subintervals. Calculate the width of each subinterval, \( h = (2 - 0)/4 = 0.5 \). Find the function values at the points 0, 0.5, 1, 1.5, and 2.
02

Apply the Trapezoidal Formula

The Trapezoidal Rule is given by \( T_n = \frac{h}{2} [f(x_0) + 2f(x_1) + 2f(x_2) + 2f(x_3) + f(x_4)] \). Calculate it: \[ T_4 = \frac{0.5}{2} \left[ (0^3 + 0) + 2(0.5^3 + 0.5) + 2(1^3 + 1) + 2(1.5^3 + 1.5) + (2^3 + 2) \right] \]. Compute each term and sum them.
03

Calculate the Upper Bound for the Trapezoidal Rule Error

The error bound formula for the Trapezoidal Rule is: \[ |E_T| \leq \frac{(b-a)^3}{12n^2} \max_{a \leq t \leq b} |f''(t)| \]. Compute the second derivative: \( f(t) = t^3 + t \Rightarrow f''(t) = 6t \). Evaluate \( |f''(t)| \) over \([0,2]\) and substitute the values.
04

Evaluate the integral directly

Find the antiderivative of \( t^3 + t \), which is \( \frac{t^4}{4} + \frac{t^2}{2} \). Evaluate this from 0 to 2: \[ \left. \left( \frac{t^4}{4} + \frac{t^2}{2} \right) \right|_0^2 = \left( \frac{2^4}{4} + \frac{2^2}{2} \right) - (0 + 0) \]. Calculate to find the exact value of the integral.
05

Find Actual Error for Trapezoidal Rule

Subtract the estimated integral value obtained by the Trapezoidal Rule from the true integral value found in step 4 to find \( |E_T| \).
06

Express Trapezoidal Rule Error as a Percentage

Use the formula \( \left|E_T\right|/(\text{true value}) \times 100\). Substitute \( |E_T| \) from Step 5 and the true integral value obtained in Step 4 to calculate the percentage error.
07

Set up Simpson's Rule

For Simpson's Rule with \( n = 4 \) subintervals, calculate the width \( h = 0.5 \). Use the points 0, 0.5, 1, 1.5, and 2. Apply the formula: \( S_4 = \frac{h}{3} [f(x_0) + 4f(x_1) + 2f(x_2) + 4f(x_3) + f(x_4)] \). Compute the terms.
08

Calculate the Upper Bound for Simpson's Rule Error

Use the error bound for Simpson's Rule: \[ |E_S| \leq \frac{(b-a)^5}{180n^4} \max_{a \leq t \leq b} |f^{(4)}(t)| \]. As \( f(t) = t^3 + t \), note that the fourth derivative \( f^{(4)}(t) = 0 \) which leads to \( |E_S| = 0 \).
09

Find Actual Error for Simpson's Rule

Subtract the Simpson's Rule approximation from the true integral value to find \( |E_S| \). Since the error bound is zero, \( |E_S| \) should also be zero.
10

Express Simpson's Rule Error as a Percentage

Use the formula \( (|E_S|/(\text{true value}) \times 100) \). Since \( |E_S| = 0 \), the percentage error is 0%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trapezoidal Rule
The Trapezoidal Rule is a straightforward numerical method to estimate the value of a definite integral. It simplifies the area under a curve by breaking it down into a series of trapezoids, which can be easily calculated and summed up. In this exercise, the integral \( \int_{0}^{2} (t^3 + t) \, dt \) is approximated using the Trapezoidal Rule with \( n=4 \) steps.
First, the interval \([0, 2]\) is divided into 4 subintervals, each of width \( h = 0.5 \). Function values are evaluated at these points: \( f(0), f(0.5), f(1), f(1.5) \), and \( f(2) \). The formula applied is:
  • \( T_4 = \frac{0.5}{2} [f(0) + 2f(0.5) + 2f(1) + 2f(1.5) + f(2)] \)
Once the values are substituted and calculated, the summed area approximates the area under the curve.In addition, the upper bound error of the Trapezoidal Rule \( |E_T| \) depends on the second derivative of the function. For \( f(t) = t^3 + t \), the second derivative is \( f''(t) = 6t \). The maximum value of this function over the given interval helps define the potential error range.
Simpson's Rule
Simpson’s Rule offers a more accurate method for numerical integration, especially when the function outline is parabolic between points. Like the Trapezoidal Rule, Simpson’s Rule requires dividing the interval into even segments, but it applies a quadratic polynomial to approximate the function.For the integral \( \int_{0}^{2} (t^3 + t) \, dt \), with \( n=4 \), Simpson's Rule uses the same points as the Trapezoidal Rule but with a different formula:
  • \( S_4 = \frac{0.5}{3} [f(0) + 4f(0.5) + 2f(1) + 4f(1.5) + f(2)] \)
This formula involves alternating coefficients of 4 and 2 to allow for the quadratic interpolation.Simpson's Rule proves to be highly precise because the error bound depends on the fourth derivative of the function. For this specific function, \( f^{(4)}(t) = 0 \), leading to a calculated error bound of zero, demonstrating the method's effectiveness in certain scenarios.
Error Analysis
Error analysis in numerical integration helps understand the accuracy of our approximations and provides insights into improving these methods. For the Trapezoidal Rule, the error analysis uses the formula:
  • \( |E_T| \leq \frac{(b-a)^3}{12n^2} \max_{a \leq t \leq b} |f''(t)| \)
Here, a higher value of \( n \) (more subintervals) or a function with a smaller second derivative curve decreases the error. Calculating \( |E_T| \) directly involves comparing the approximated integral with the true integral.Error for Simpson's Rule is traditionally smaller due to its quadratic approximation technique. The error bound relies on the fourth derivative:
  • \( |E_S| \leq \frac{(b-a)^5}{180n^4} \max_{a \leq t \leq b} |f^{(4)}(t)| \)
In cases such as with \( t^3 + t \), where \( f^{(4)}(t) = 0 \), the theoretical error is non-existent, guaranteeing high precision.Expressing errors as percentages of the true integral values aids in grasping their significance. However, a value close to zero reflects excellent accuracy, making Simpson's Rule particularly valuable for precise calculations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Elliptic integrals The length of the ellipse $$ \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 $$ turns out to be $$Length =4 a \int_{0}^{\pi / 2} \sqrt{1-e^{2} \cos ^{2} t} d t$$ where \(e=\sqrt{a^{2}-b^{2}} / a\) is the ellipse's eccentricity. The integral in this formula, called an elliptic integral, is nonelementary except when \(e=0\) or \(1 .\) a. Use the Trapezoidal Rule with \(n=10\) to estimate the length of the ellipse when \(a=1\) and \(e=1 / 2\) . b. Use the fact that the absolute value of the second derivative of \(f(t)=\sqrt{1-e^{2} \cos ^{2} t}\) is less than 1 to find an upper bound for the error in the estimate you obtained in part (a).

Suppose you toss a fair coin \(n\) times and record the number of heads that land. Assume that \(n\) is large and approximate the discrete random variable \(X\) with a continuous random variable that is normally distributed with \(\mu=n / 2\) and \(\sigma=\sqrt{n} / 2 .\) If \(n=400\) find the given probabilities. $$ \begin{array}{ll}{\text { a. } P(190 \leq X<210)} & {\text { b. } P(X<170)} \\\ {\text { c. } P(X>220)} & {\text { d. } P(X=300)}\end{array} $$

Use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integrals for convergence. If more than one method applies, use whatever method you prefer. $$\int_{2}^{\infty} \frac{1}{\ln x} d x$$

Use numerical integration to estimate the value of $$ \pi=4 \int_{0}^{1} \frac{1}{1+x^{2}} d x $$

Normal probability distribution The function $$f(x)=\frac{1}{\sigma \sqrt{2 \pi}} e^{-\frac{1}{2}\left(\frac{x-\mu}{\sigma}\right)^{2}}$$ is called the normal probability density function with mean \(\mu\) and standard deviation \(\sigma .\) The number \(\mu\) tells where the distribution is centered, and \(\sigma\) measures the "scatter" around the mean. (See Section 8.9. $$\begin{array}{c}{\text { From the theory of probability, it is known that }} \\\ {\int_{-\infty}^{\infty} f(x) d x=1}\end{array}$$ In what follows, let \(\mu=0\) and \(\sigma=1.\) a. Draw the graph of \(f .\) Find the intervals on which \(f\) is increasing, the intervals on which \(f\) is decreasing, and any local extreme values and where they occur. b. Evaluate $$\int_{-n}^{n} f(x) d x$$ for \(n=1,2,\) and 3. c. Give a convincing argument that $$\int_{-\infty}^{\infty} f(x) d x=1.$$ (Hint: Show that \(0 < f(x) < e^{-x / 2}\) for \(x > 1,\) and for \(b >1,\) $$\int_{b}^{\infty} e^{-x / 2} d x \rightarrow 0 \quad \text { as } \quad b \rightarrow \infty_{ .} )$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.