/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Use the substitution \(u=x^{4}+1... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the substitution \(u=x^{4}+1\) to evaluate the integral $$ \int x^{7} \sqrt{x^{4}+1} d x $$

Short Answer

Expert verified
The integral is \( \frac{1}{10}(x^4 + 1)^{\frac{5}{2}} - \frac{1}{6}(x^4 + 1)^{\frac{3}{2}} + C \).

Step by step solution

01

Identify the Substitution

We are given the substitution \(u = x^4 + 1\). Our goal is to rewrite the integral in terms of \(u\).
02

Differentiate the Substitution

To use the substitution, differentiate \(u = x^4 + 1\) with respect to \(x\): \(du = 4x^3 dx\) or equivalently, \(dx = \frac{du}{4x^3}\).
03

Substitute into the Integral

Rewrite the original integral \(\int x^7 \sqrt{x^4+1} \, dx\) using \(u\) and \(du\):Since \(u = x^4 + 1\), we have \(\sqrt{x^4+1} = \sqrt{u}\). Also, notice \(x^7 = x^4 \cdot x^3 = (u-1)x^3\).The integral becomes \((u-1)x^3 \sqrt{u} \frac{du}{4x^3}\), then simplify to \(\frac{1}{4}\int (u-1)\sqrt{u} \, du\).
04

Simplify and Integrate

Distribute the integral: \(\frac{1}{4}\int (u^{\frac{3}{2}} - u^{\frac{1}{2}}) \, du\).This separates to: \(\frac{1}{4}\left(\int u^{\frac{3}{2}} \, du - \int u^{\frac{1}{2}} \, du\right)\).Integrate each term: \(\int u^{\frac{3}{2}} \, du = \frac{u^{\frac{5}{2}}}{\frac{5}{2}} = \frac{2}{5}u^{\frac{5}{2}}\)and \(\int u^{\frac{1}{2}} \, du = \frac{u^{\frac{3}{2}}}{\frac{3}{2}} = \frac{2}{3}u^{\frac{3}{2}}\).So the integral is \(\frac{1}{4}\left(\frac{2}{5}u^{\frac{5}{2}} - \frac{2}{3}u^{\frac{3}{2}}\right)\).
05

Simplify the Result

Calculate: \(\frac{1}{4}\left(\frac{2}{5}u^{\frac{5}{2}} - \frac{2}{3}u^{\frac{3}{2}}\right) = \frac{1}{10}u^{\frac{5}{2}} - \frac{1}{6}u^{\frac{3}{2}}\).Substitute back \(u = x^4 + 1\):The final answer is \(\frac{1}{10}(x^4 + 1)^{\frac{5}{2}} - \frac{1}{6}(x^4 + 1)^{\frac{3}{2}} + C\), where \(C\) is the constant of integration.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integrals
Definite integrals play a fundamental role in calculus, allowing us to compute the value of a function over a specific interval. Unlike indefinite integrals, which give us a family of functions through anti-derivatives, definite integrals provide a numerical value representing the area under the curve of a function between two bounds. The notation often includes integration limits written as:
  • \(\int_{a}^{b} f(x) \, dx\)
Here, \(a\) and \(b\) represent the lower and upper limits of integration, respectively. By solving a definite integral, we determine the accumulated quantity, such as the total distance traveled, area under a curve, or volume.

In our exercise, although we have not been provided with bounds, understanding definite integrals is crucial as the process involves defining integration limits when applicable. This knowledge is useful when transforming functions, especially when substituting variables, whereby a new function is integrated over a defined interval. A proper grasp of integration, and particularly definite integrals, enhances our ability to apply calculus to real-world problems.
Integral Calculus
Integral calculus is a major branch of calculus that focuses on accumulation and area determination, primarily dealing with integrals and their inverse operation—differentiation. It enables us to go from rates of change and local behavior (given by derivatives) back to the accumulated quantities and global behavior.

When integrating a function, we essentially find its anti-derivative, giving insight into the original quantity's behavior before differentiation. The indefinite integral of a function \(f(x)\), without bounds, is given by:
  • \(F(x) + C,\)
where \(F(x)\) is any function where its derivative \(F'(x) = f(x)\), and \(C\) is the constant of integration. It represents a general class of functions whose derivative is \(f(x)\).

In our exercise, integral calculus comes into play when we express and simplify the integral using substitution, leading to the integration of a transformed function. Understanding integral calculus involves recognizing the relationship between differentiation and integration, essential for solving complex integral problems effectively.
Change of Variables
The change of variables technique, also known as substitution, is a powerful tool in integral calculus that simplifies integration by transforming a complex integral into a simpler one. This technique is akin to reversing the chain rule from differentiation to help integrate functions that are cumbersome in their original form.

When applying a change of variables, we substitute a new variable \(u\) for a function of the original variable, such as \(u = g(x)\), simplifying the integral. The differential \(du\) then replaces the appropriate part of the original differential, \(dx\), computing as \(du = g'(x) \, dx\). The formula for integration by substitution becomes:
  • \(\int f(g(x))g'(x) \, dx = \int f(u) \, du\)
In our problem, the substitution \(u = x^4 + 1\) transforms the original integral \(\int x^7 \sqrt{x^4+1} \, dx\) into a more manageable form. By successfully converting the original variable \(x\) to \(u\), the integrand simplifies, facilitating easier integration.

Mastering the change of variables is vital for tackling a broad gamut of integration challenges, empowering you to reconfigure and calculate seemingly difficult integrals by neatly fitting them into a solvable structure.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use numerical integration to estimate the value of $$ \pi=4 \int_{0}^{1} \frac{1}{1+x^{2}} d x $$

Cholesterol levels The serum cholesterol levels of children aged 12 to 14 years follows a normal distribution with mean \(\mu=162\) mg/dl and standard deviation \(\sigma=28 \mathrm{mg} / \mathrm{dl} .\) In a population of 1000 of these children, how many would you expect to have serum cholesterol levels between 165 and 193\(?\) between 148 and 167\(?\)

Three people are asked their opinion in a poll about a particular brand of a common product found in grocery stores. They can answer in one of three ways: "Like the product brand" (L), "Dislike the product brand" (D), or "Undecided" (U). For each outcome, the random variable \(X\) assigns the number of L's that appear. $$ \begin{array}{l}{\text { a. Find the set of possible outcomes and the range of } X .} \\ {\text { b. Create a probability bar graph for } X \text { . }} \\\ {\text { c. What is the probability that at least two people like the product }} \\ {\text { brand? }} \\ {\text { d. What is the probability that no more than one person dislikes }} \\ {\text { the product brand? }}\end{array} $$

Use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integrals for convergence. If more than one method applies, use whatever method you prefer. $$\int_{-\infty}^{\infty} \frac{d x}{e^{x}+e^{-x}}$$

Pollinating flowers A biologist models the time in minutes until a bee arrives at a flowering plant with an exponential distribution having a mean of 4 minutes. If 1000 flowers are in a field, how many can be expected to be pollinated within 5 minutes?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.