/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 Evaluate the integrals in Exerci... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the integrals in Exercises \(33-50\) $$ \int e^{x} \sec ^{3} e^{x} d x $$

Short Answer

Expert verified
The integral evaluates to \( \sec(e^x) \tan(e^x) + \ln | \sec(e^x) + \tan(e^x) | + C \).

Step by step solution

01

Substitution

First, let's use substitution to simplify the integral. We set \( u = e^x \). Then, \( du = e^x dx \) or \( dx = \frac{du}{u} \). Substituting these into the integral gives us:\[ \int e^x \sec^3(e^x) \, dx = \int u \sec^3(u) \frac{du}{u} = \int \sec^3(u) \, du \]
02

Use Integration by Parts

To evaluate \( \int \sec^3(u) \, du \), we utilize integration by parts. Let \( v = \sec(u) \) and \( dv = \sec(u) \tan(u) \, du \). Also, let \( dw = \sec^2(u) \, du \) and \( w = \tan(u) \):\[ \int \sec^3(u) \, du = \sec(u) \tan(u) - \int \tan(u) \sec(u) \tan(u) \, du \]
03

Simplify the Integral

The integral in steps becomes \( \int \sec^3(u) \, du = \sec(u) \tan(u) - \int \sec(u) \tan^2(u) \, du \). Notice that \( \tan^2(u) = \sec^2(u) - 1 \). Therefore:\[ \int \sec^3(u) \, du = \sec(u) \tan(u) - \int (\sec^3(u) - \sec(u)) \, du \]
04

Solve the Simplified Integral

This simplifies to:\[ \int \sec^3(u) \, du = \sec(u) \tan(u) - \left( \int \sec^3(u) \, du - \int \sec(u) \, du \right) \] This gives:\[ \int \sec^3(u) \, du = \sec(u) \tan(u) + \int \sec(u) \, du \]
05

Calculate \( \int \sec(u) \, du \)

We need to calculate \( \int \sec(u) \, du \), which is a standard integral:\[ \int \sec(u) \, du = \ln | \sec(u) + \tan(u) | + C \]
06

Substitute Back

Substituting back in terms of \( x \), we have \( u = e^x \) thus:\[ \int e^x \sec^3(e^x) \, dx = \sec(e^x) \tan(e^x) + \ln | \sec(e^x) + \tan(e^x) | + C \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration by Parts
Integration by parts is a fundamental technique in integral calculus. It's especially useful when you're dealing with the product of two functions. The core idea rests on transforming the original product into another form that's easier to integrate. It comes from the product rule of differentiation.

The formula for integration by parts is given by:
  • \( \int u \, dv = uv - \int v \, du \)
Where:
  • \( u \) and \( v \) are functions of \( x \)
  • \( du \) and \( dv \) are their respective derivatives

In the case of integrating powers of secant, like \( \int \sec^3(u) \, du \), this method can simplify integration by choosing parts so that the derivative simplifies the integral further. Remember, sometimes you might need to apply integration by parts more than once, or in combination with other methods, to fully solve an integral.
Substitution Method
The substitution method, also known as "u-substitution," is a powerful tool in calculus for simplifying integrals. It involves changing variables to transform difficult integrals into simpler ones. Typically, this method works by identifying a part of the integral that can be replaced by a single variable \( u \).

Here are the basic steps:
  • Select a substitution \( u = g(x) \)
  • Calculate \( du = g'(x) \, dx \)
  • Substitute \( u \) and \( du \) into the integral
  • Integrate with respect to \( u \)
  • Convert back to the original variable \( x \)
In our specific problem, we set \( u = e^x \) to simplify \( e^x \sec^3(e^x) \, dx \) to \( \int \sec^3(u) \, du \). This step transformed a potentially daunting integral into one that's more manageable, further allowing the use of other methods like integration by parts.
Trigonometric Integration
Trigonometric integration deals with integrals involving trigonometric functions such as sine, cosine, tangent and secant. These integrals often require special techniques or identities to solve.

In trigonometric integration, it's helpful to:
  • Use identities like \( \sin^2(u) + \cos^2(u) = 1 \)
  • Leverage double angle formulas, for example, \( \tan^2(u) = \sec^2(u) - 1 \)
In the case of \( \int \sec^3(u) \, du \), simplifying the integrals can utilize the identity for \( \tan^2(u) \), turning \( \int \sec(u) \tan^2(u) \, du \) into forms that are more straightforward to evaluate.

This approach not only simplifies calculations but also aids in systematically breaking down more complex expressions for integration, allowing us to proceed with further techniques or even direct computation when suitable.

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Most popular questions from this chapter

Suppose you toss a fair coin \(n\) times and record the number of heads that land. Assume that \(n\) is large and approximate the discrete random variable \(X\) with a continuous random variable that is normally distributed with \(\mu=n / 2\) and \(\sigma=\sqrt{n} / 2 .\) If \(n=400\) find the given probabilities. $$ \begin{array}{ll}{\text { a. } P(190 \leq X<210)} & {\text { b. } P(X<170)} \\\ {\text { c. } P(X>220)} & {\text { d. } P(X=300)}\end{array} $$

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