/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Use a substitution to change the... [FREE SOLUTION] | 91Ó°ÊÓ

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Use a substitution to change the integral into one you can find in the table. Then evaluate the integral. \(\int \frac{\sqrt{x}}{\sqrt{1-x}} d x\)

Short Answer

Expert verified
\( \arcsin(\sqrt{x}) - \sqrt{x(1-x)} + C \)

Step by step solution

01

Introduction to the Problem

We need to evaluate the integral \( \int \frac{\sqrt{x}}{\sqrt{1-x}} \, dx \). The strategy is to use substitution to simplify the integral into a form that can be evaluated using standard integral tables.
02

Choose a Substitution

Let's set \( x = \sin^2(u) \). This substitution is often useful when the integral has expressions involving square roots in terms of \(1-x\). Then \( dx = 2\sin(u)\cos(u) \, du = \sin(2u) \, du \).
03

Substitute into the Integral

Substitute \( x = \sin^2(u) \) and \( dx = \sin(2u) \, du \) into the integral. This gives us:\[ \int \frac{\sqrt{\sin^2(u)}}{\sqrt{1-\sin^2(u)}} \cdot \sin(2u) \, du. \]Since \( \sqrt{\sin^2(u)} = |\sin(u)| \) and \( \sqrt{1-\sin^2(u)} = \cos(u) \), the integral becomes:\[ \int \frac{|\sin(u)|}{\cos(u)} \cdot \sin(2u) \, du. \]
04

Simplify the Integral

Since \( \sin(2u) = 2\sin(u)\cos(u) \), the integral simplifies to:\[ \int 2|\sin(u)| \, \sin(u) \, du. \]As \( |\sin(u)| \sin(u) = \sin^2(u) \), the integral becomes:\[ 2 \int \sin^2(u) \, du. \]
05

Use an Identity to Simplify Further

Using the trigonometric identity \( \sin^2(u) = \frac{1 - \cos(2u)}{2} \), the integral becomes:\[ 2 \int \frac{1 - \cos(2u)}{2} \, du = \int (1 - \cos(2u)) \, du. \]This can be split into two separate integrals:\[ \int 1 \, du - \int \cos(2u) \, du. \]
06

Evaluate the Separate Integrals

The first integral, \( \int 1 \, du = u \).For the second integral, use \( \int \cos(2u) \, du = \frac{1}{2}\sin(2u) + C \).Thus, the integral simplifies to:\[ u - \frac{1}{2} \sin(2u) + C. \]
07

Back-Substitute for x

Recall the substitution \( x = \sin^2(u) \), so \( u = \arcsin(\sqrt{x}) \).Finally, back-substitute to the expression:\[ \arcsin(\sqrt{x}) - \frac{1}{2} \cdot 2\sqrt{x(1-x)} + C. \]Thus:\[ \arcsin(\sqrt{x}) - \sqrt{x(1-x)} + C. \]
08

Conclusion

The evaluated integral of the given function using substitution is:\[ \arcsin(\sqrt{x}) - \sqrt{x(1-x)} + C. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integral
A definite integral is a fundamental concept in calculus. It represents the area under a curve between two points on the x-axis. The integral is defined as the limit of a sum of areas of rectangles, as the width of the rectangles approaches zero. When dealing with definite integrals, you calculate an exact numerical value rather than an indefinite integral, which results in a function plus a constant of integration (C).
The bounds of integration are expressed as the limits of the integral; for example, the integral from 0 to 1 of a function f(x) is written as \[ \int_{0}^{1} f(x) \, dx. \] In our context, we converted our definite integral problem into one that could be easily integrated after substitution, although the original exercise was an indefinite integral.
Trigonometric Substitution
Trigonometric substitution is a technique used to simplify integrals that involve square roots. This method involves substituting trigonometric identities in place of algebraic expressions to transform the integral into a more manageable form.
In the exercise at hand, the substitution \( x = \sin^2(u) \) was used. This particular substitution is effective when the integral has expressions like \( 1 - x \) under square roots, as it transforms \( \sqrt{1-x} \) into \( \cos(u) \), which is easier to handle.
This technique exploits the range and properties of trigonometric functions to simplify the expression. Integrating these transformed functions is usually straightforward if you use the right trigonometric identities or techniques.
Trigonometric Identities
Trigonometric identities are relationships that involve trigonometric functions and are true for every value of the occurring variables. These identities are powerful tools in transforming expressions, especially in integral calculus.
In our exercise, one such identity used is \( \sin^2(u) = \frac{1 - \cos(2u)}{2} \). This identity simplified the integral by transforming \( \sin^2(u) \) into a difference expression, making it easier to split the integral into parts that are simpler to evaluate.
  • Pythagorean identity: \( \sin^2(u) + \cos^2(u) = 1 \)
  • Double angle formulas: \( \sin(2u) = 2\sin(u)\cos(u) \)
These identities help unravel complex trigonometric expressions into forms that are straightforward to work with.
Integration Techniques
Integration techniques are methods used to solve calculus integrals, which can often be complex or difficult in their original form. The goal is to simplify the integral into a form that is easy to evaluate.
Common techniques include:
  • Substitution: Involves changing variables to simplify the integral, as seen with \( x = \sin^2(u) \) in our example.
  • Integration by parts: Useful when the integrand is a product of two functions.
  • Partial fraction decomposition: Decompensating rational functions into simpler, fraction-like terms.
By using substitution, trigonometric identities, and sometimes integration by parts or trigonometric substitutions like in the exercise, students can tackle difficult integration problems with ease.

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