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In Exercises \(1-8,\) determine which are probability density functions and justify your answer. $$ f(x)=2^{x} \text { over }\left[0, \frac{\ln (1+\ln 2)}{\ln 2}\right] $$

Short Answer

Expert verified
Yes, \( f(x) = 2^x \) is a probability density function over the given interval.

Step by step solution

01

Define the Interval

For the given function \( f(x) = 2^x \), we must determine if it is a probability density function over the interval \([0, \frac{\ln(1+\ln 2)}{\ln 2}]\).
02

Check Non-Negativity

We first need to check if the function \( f(x) = 2^x \) is non-negative over the interval \([0, \frac{\ln(1+\ln 2)}{\ln 2}]\). For any valid input \( x \), \( 2^x \) is always positive since \( 2^x > 0 \) for all \( x \). Thus, \( f(x) \) is non-negative over the interval.
03

Integrate the Function

To confirm that \( f(x) \) is a probability density function, compute the integral of \( f(x) \) over the given interval:\[\int_0^{\frac{\ln(1+\ln 2)}{\ln 2}} 2^x \, dx\]The indefinite integral of \( 2^x \) is \( \frac{2^x}{\ln 2} \).
04

Evaluate the Definite Integral

Substitute the limits into the indefinite integral:\[\int_0^{\frac{\ln(1+\ln 2)}{\ln 2}} 2^x \, dx = \left[ \frac{2^x}{\ln 2} \right]_0^{\frac{\ln(1+\ln 2)}{\ln 2}}\]Evaluating this, we get:\[\frac{2^{\frac{\ln(1+\ln 2)}{\ln 2}}}{\ln 2} - \frac{2^0}{\ln 2} = \frac{1+\ln 2}{\ln 2} - \frac{1}{\ln 2} = 1\]
05

Conclusion

Since the integral of \( f(x) \) over the interval \([0, \frac{\ln(1+\ln 2)}{\ln 2}]\) equals 1, \( f(x) \) meets all the criteria to be a probability density function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Non-Negativity of Functions
In probability theory, it's important for a probability density function (PDF) to be non-negative over its domain. This means that the function must return values that are zero or greater for every possible input. For the function given in the exercise, \( f(x) = 2^x \), this requirement is satisfied. How do we know? Because the exponential function \( 2^x \) is always positive. No matter the value of \( x \), as long as it's real, \( 2^x \) will result in a positive number. This non-negativity is a key feature of exponential functions, ensuring they can potentially serve as probability density functions. For instance:
  • \( 2^0 = 1 \), which is positive
  • \( 2^1 = 2 \), which is positive
  • Even \( 2^{-1} = \frac{1}{2} \), which remains positive
This characteristic ensures that \( f(x) = 2^x \) is a candidate for a PDF over any interval where we're examining it.
Definite Integral as a Measure of Total Probability
A fundamental property of probability density functions is that their definite integral, over the entire space in which they are defined, must equal exactly 1. This total of "1" represents the certainty that some outcome within that space will occur. In our exercise, we compute the definite integral of the function \( f(x) = 2^x \) over the interval \( \left[0, \frac{\ln(1+\ln 2)}{\ln 2}\right] \). Performing this integral involves finding the antiderivative of \( 2^x \), which is \( \frac{2^x}{\ln 2} \). Once you've found the antiderivative, you evaluate it between the limits:
  • Plug in the upper limit \( \frac{\ln(1+\ln 2)}{\ln 2} \)
  • Then plug in the lower limit 0
  • Subtract these results to find the definite integral's total
When calculated, this integral evaluates to 1, confirming that \( f(x) \), when integrated over its specified range, satisfies the main requirement of a probability density function.
Understanding the Exponential Function
The exponential function \( 2^x \) is a captivating and vital mathematical function with distinctive properties, especially useful in probability and statistics. Exponential functions are characterized by their constant rate of growth. The graph of an exponential function like \( 2^x \) is always curving upwards for positive \( x \), indicating increasing growth, and it reflects symmetry over the y-axis for negative \( x \). Some key features of the exponential function:
  • Rapid growth: As \( x \) increases, \( 2^x \) rises sharply.
  • Decay when \( x \) is negative: It approaches zero but never actually gets there.
  • Non-zero for all \( x \): The function never touches the x-axis.
These characteristics make exponential functions an excellent choice for modelling real-world scenarios involving growth, decay, and distributions, such as populations or radioactive decay. Knowing how the exponential function behaves is crucial for understanding why \( 2^x \) can be utilitarian as a probability density function over certain intervals.

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