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Use any method to evaluate the integrals. Most will require trigonometric substitutions, but some can be evaluated by other methods. $$\int \frac{x^{2} d x}{\left(x^{2}-1\right)^{5 / 2}}, \quad x>1$$

Short Answer

Expert verified
The integral evaluates to \(-\frac{x^2}{2(x^2-1)} + C, \; x > 1\).

Step by step solution

01

Identify the Substitution

Since the integral involves a term of the form \(x^2 - 1\), we will use the trigonometric substitution \(x = \sec(\theta)\), where \(dx = \sec(\theta) \tan(\theta) \, d\theta\). This substitution is appropriate because \(\sec^2(\theta) - 1 = \tan^2(\theta)\).
02

Substitute and Simplify

Substitute \(x = \sec(\theta)\) into the integral. We have:\[\int \frac{\sec^2(\theta) \cdot \sec(\theta) \tan(\theta) \, d\theta}{(\sec^2(\theta) - 1)^{5/2}}.\]Simplify the denominator to get \(\tan^2(\theta)^{5/2} = \tan^5(\theta)\). The integral becomes:\[\int \frac{\sec^3(\theta) \tan(\theta) \, d\theta}{\tan^5(\theta)} = \int \frac{\sec^3(\theta)}{\tan^4(\theta)} \, d\theta.\]
03

Simplify Further Using Trigonometric Identities

Recall that \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\) and \(\sec(\theta) = \frac{1}{\cos(\theta)}\). Thus, we have:\[\sec^3(\theta) = \frac{1}{\cos^3(\theta)} \quad \text{and} \quad \tan^4(\theta) = \frac{\sin^4(\theta)}{\cos^4(\theta)}.\]This simplifies our integral to:\[\int \frac{\cos^4(\theta)}{\cos^3(\theta) \sin^4(\theta)} \, d\theta = \int \frac{\cos(\theta)}{\sin^4(\theta)} \, d\theta = \int \frac{\cot(\theta)}{\sin^3(\theta)} \, d\theta.\]
04

Use Another Substitution

To solve the integral \(\int \frac{\cot(\theta)}{\sin^3(\theta)} \, d\theta\), use the substitution \(u = \sin(\theta)\), then \(du = \cos(\theta) \, d\theta\). The integral becomes:\[\int \frac{\cot(\theta)}{u^3} \cdot \frac{1}{\cos(\theta)} \, du = \int \frac{1}{u^3} \, du.\]
05

Integrate

The integral \(\int \frac{1}{u^3} \, du\) is straightforward:\[\int u^{-3} \, du = \frac{u^{-2}}{-2} = -\frac{1}{2u^2} + C.\]
06

Back Substitute

Replace \(u\) with \(\sin(\theta)\):\[-\frac{1}{2(\sin(\theta))^2} + C.\]Using the original substitution \(x = \sec(\theta)\), we know \(\sin(\theta) = \sqrt{1 - \frac{1}{x^2}} = \frac{\sqrt{x^2-1}}{x}\). Thus:\[-\frac{1}{2 \left(\frac{\sqrt{x^2-1}}{x}\right)^2} = -\frac{x^2}{2(x^2-1)} + C.\]
07

Finalize the Solution

Hence, the final answer is:\[-\frac{x^2}{2(x^2-1)} + C.\] This is the evaluated integral.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration Techniques
Integration is a core concept in calculus that involves finding the antiderivative or the area under a curve. Various techniques are employed to solve integrals, especially when they are not straightforward. For advanced problems, such as the one given in the original exercise, specific methods like trigonometric substitution are highly useful. This technique simplifies integrals containing square roots and quadratic expressions by transforming them into trigonometric functions, making them more manageable.
One starts by identifying a suitable substitution. This involves recognizing forms within the integral that resemble trigonometric identities, and then changing variables accordingly. Integrating such transformed expressions becomes much simpler, as trigonometric identities allow us to reduce complex powers and products to more tractable forms. Always remember, the effectiveness of an integration technique relies heavily on recognizing the pattern in the integrand.
Trigonometric Identities
Trigonometric identities are mathematical equations involving trigonometric functions that are universally valid for all values of the occurring variables. They play a crucial role in solving integrals, such as in the given exercise. The identities help transform the integrand into a simpler form suitable for integration.
In this exercise, using the identity \( \sec^2(\theta) - 1 = \tan^2(\theta) \), we simplify the expression under the square root. This substitution translates the integral into terms of \tan\(\theta\)\, making it more straightforward. Such identities are indispensable in breaking down and simplifying the integrand into more elementary functions. By employing identities correctly, tricky expressions turn into ones that are much easier to work with.
Change of Variables
The change of variables is a powerful technique in calculus that helps simplify integrals. By transforming the variable of integration, an integral that initially looks complex becomes easier to solve. In the exercise, we first substituted \( x = \sec(\theta) \), leading to a new variable and integrand that are more manageable.
Afterward, another substitution \( u = \sin(\theta) \) is used to reduce the integral further. This double substitution is often helpful when trigonometric identities are in play, and it allows the integral to be expressed in terms of basic functions. The goal is always to transform the integrand into a simple form, such as a power or polynomial, that we can integrate easily. Such methodologies highlight the importance of flexible thinking when handling integrals.
Definite Integrals
While the exercise at hand addresses an indefinite integral, understanding definite integrals is also crucial. Definite integrals calculate the exact area under a curve between two bounds. They provide not just an antiderivative, but a specific numerical value representing this area.
To handle definite integrals, one must apply integration techniques similarly, with the additional step of evaluating the resulting antiderivative using the upper and lower bounds. The transformations we discussed using trigonometric substitutions and variable changes are equally applicable here. For definite integrals, these transformations are particularly useful as they streamline calculations between boundaries, ensuring accuracy in the ultimate value derived from the integral.

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