Chapter 8: Problem 25
Use the table of integrals at the back of the book to evaluate the integrals. \(\int \cos \frac{\theta}{3} \cos \frac{\theta}{4} d \theta\)
Short Answer
Expert verified
\( \frac{6}{7} \sin \frac{7\theta}{12} + 6\sin \frac{\theta}{12} + C \)
Step by step solution
01
Identify the Integral Form
The given integral is \( \int \cos \frac{\theta}{3} \cos \frac{\theta}{4} \, d\theta \). Look for an integral in the table that resembles the product of cosines. This typically involves using a product-to-sum formula.
02
Apply the Product-to-Sum Formula
The product-to-sum formula for \( \cos A \cos B \) is \( \cos A \cos B = \frac{1}{2}(\cos(A+B) + \cos(A-B)) \). Apply it here: \[ \cos \frac{\theta}{3} \cos \frac{\theta}{4} = \frac{1}{2} \left( \cos \left( \frac{\theta}{3} + \frac{\theta}{4} \right) + \cos \left( \frac{\theta}{3} - \frac{\theta}{4} \right) \right) \] This simplifies to: \[ \frac{1}{2} \left( \cos \frac{7\theta}{12} + \cos \frac{\theta}{12} \right) \]
03
Break Down the Integral
Using the result from Step 2, break down the integral as follows:\[ \int \cos \frac{\theta}{3} \cos \frac{\theta}{4} \, d\theta = \frac{1}{2} \int \cos \frac{7\theta}{12} \, d\theta + \frac{1}{2} \int \cos \frac{\theta}{12} \, d\theta \]
04
Evaluate the First Integral
Look up the integral of \( \cos(k \theta) \), which is \( \frac{1}{k} \sin(k \theta) \). For the first integral:\[ \int \cos \frac{7\theta}{12} \, d\theta = \frac{12}{7}\sin \frac{7\theta}{12} + C_1 \]
05
Evaluate the Second Integral
Similarly, evaluate the second integral:\[ \int \cos \frac{\theta}{12} \, d\theta = 12\sin \frac{\theta}{12} + C_2 \]
06
Combine the Results
Combine the results from the previous steps:\[ \int \cos \frac{\theta}{3} \cos \frac{\theta}{4} \, d\theta = \frac{1}{2} \left( \frac{12}{7} \sin \frac{7\theta}{12} + 12\sin \frac{\theta}{12} \right) + C \]Simplifying gives:\[ \int \cos \frac{\theta}{3} \cos \frac{\theta}{4} \, d\theta = \frac{6}{7} \sin \frac{7\theta}{12} + 6\sin \frac{\theta}{12} + C \]
07
Write Final Answer
The evaluated integral is: \[ \int \cos \frac{\theta}{3} \cos \frac{\theta}{4} \, d\theta = \frac{6}{7} \sin \frac{7\theta}{12} + 6\sin \frac{\theta}{12} + C \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Product-to-Sum Formula
The product-to-sum formula is a mathematical tool used to simplify the integration of products of trigonometric functions, like sines and cosines. It helps us convert the product of two trigonometric functions into a sum, which can make integration much easier. In this exercise, we dealt with a product of cosines:
- \( \cos A \cos B = \frac{1}{2}(\cos(A+B) + \cos(A-B)) \)
- Let \( A = \frac{\theta}{3} \) and \( B = \frac{\theta}{4} \)
Trigonometric Integrals
Trigonometric integrals involve the integration of expressions containing trigonometric functions, such as sine, cosine, tangent, etc. Techniques like the product-to-sum formula play a crucial role in simplifying these integrals.
In our example, by transforming \( \cos \frac{\theta}{3} \cos \frac{\theta}{4} \) using the product-to-sum formula, we ended up with two separate cosine terms. This leads to two simpler integrals:
In our example, by transforming \( \cos \frac{\theta}{3} \cos \frac{\theta}{4} \) using the product-to-sum formula, we ended up with two separate cosine terms. This leads to two simpler integrals:
- \( \int \cos \frac{7\theta}{12} \, d\theta \)
- \( \int \cos \frac{\theta}{12} \, d\theta \)
Table of Integrals
Tables of integrals are references in calculus that list common integrals of functions, allowing for quick lookup of common integral forms. These provide pre-solved antiderivatives for various functions, including trigonometric functions like cosine and sine.
In our exercise, once we converted the original trigonometric product into a sum using the product-to-sum formula, we could look up the individual integral forms in a standard table of integrals. The integral of \( \cos(k\theta) \) is given by:
In our exercise, once we converted the original trigonometric product into a sum using the product-to-sum formula, we could look up the individual integral forms in a standard table of integrals. The integral of \( \cos(k\theta) \) is given by:
- \( \int \cos(k\theta) \, d\theta = \frac{1}{k} \sin(k\theta) + C \)
- \( \int \cos \frac{7\theta}{12} \, d\theta = \frac{12}{7} \sin \frac{7\theta}{12} + C_1 \)
- \( \int \cos \frac{\theta}{12} \, d\theta = 12\sin \frac{\theta}{12} + C_2 \)