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The integrals converge. Evaluate the integrals without using tables. $$\int_{-\infty}^{0} \theta e^{\theta} d \theta$$

Short Answer

Expert verified
The integral evaluates to \(-1\).

Step by step solution

01

Identify the Integral Type

The given integral is \( \int_{-\infty}^{0} \theta e^{\theta} d\theta \). This is a definite integral of an improper type because it involves integration over an infinite limit.
02

Use the Integration by Parts Formula

Integration by parts formula is given by \( \int u \, dv = uv - \int v \, du \). Here, choose \( u = \theta \) (hence \( du = d\theta \)) and \( dv = e^{\theta} d\theta \) (hence \( v = e^{\theta} \)).
03

Apply the Integration by Parts Formula

Using integration by parts, we have: \[\int \theta e^{\theta} d\theta = \theta e^{\theta} - \int e^{\theta} d\theta = \theta e^{\theta} - e^{\theta} + C.\]
04

Evaluate the Definite Integral

Now substitute the limits of integration from \(-\infty\) to \(0\):\[\left[ \theta e^{\theta} - e^{\theta} \right]_{-\infty}^{0} = \left( 0 \cdot e^{0} - e^{0} \right) - \lim_{a \to -\infty} ( a e^{a} - e^{a} ).\]
05

Evaluate at the Upper Limit

At \(\theta = 0\), the expression becomes:\[0 \cdot e^{0} - e^{0} = -1.\]
06

Evaluate at the Lower Limit

Find the limit as \(\theta\) approaches \(-\infty\):\[\lim_{a \to -\infty} (a e^{a} - e^{a}) = \lim_{a \to -\infty} (a - 1) e^{a}.\] Both \(a e^{a}\) and \(e^{a}\) approach zero as \(a \to -\infty\) when using L'Hospital's Rule or analyzing the exponential decay. Thus, the expression evaluates to 0 for the lower limit.
07

Calculate the Final Result

Combine the two results from handling the limits:\[-1 - 0 = -1.\]Therefore, the integral evaluates to \(-1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration by Parts
Integration by Parts is a useful technique in calculus for finding integrals of products of functions. It transforms a complex integral into simpler parts that are easier to evaluate. The principle is derived from the product rule of differentiation. The formula for integration by parts is:\[ \int u \, dv = uv - \int v \, du \]To apply this technique effectively, we must make strategic choices for our functions \( u \) and \( dv \). Typically, we choose \( u \) as the function that becomes simpler when differentiated, and \( dv \) as the function that remains manageable upon integration.
  • Choose \( u \) and \( dv \) appropriately. In this exercise, \( u = \theta \) and \( dv = e^{\theta} d\theta \).
  • Differentiate \( u \) to find \( du \), and integrate \( dv \) to find \( v \).
  • Substitute into the integration by parts formula and simplify.
By practicing and understanding this method, solving integrals involving products becomes more intuitive and less time-consuming.
Exponential Functions
Exponential functions are a category of mathematical functions that grow by rates proportional to their current value. The most common base for exponential functions in calculus is Euler's number \( e \). It provides a constant relative rate of growth, making it a powerful tool in both pure and applied mathematics.
  • Euler's number \( e \approx 2.71828 \) and is an irrational number.
  • Exponential functions are of the form \( f(x) = e^x \), which grows rapidly as \( x \) increases.
  • They exhibit a unique property: the derivative of \( e^x \) is \( e^x \) itself, making it incredibly straightforward to work with in differential and integral calculus.
In this example, we use \( e^{\theta} \) which demonstrates the advantages of exponential functions in calculus. These functions allow straightforward manipulation using differentiation and integration rules, simplifying the process of evaluating complex equations.
Definite Integrals
Definite integrals, represented by notation \( \int_a^b f(x) \, dx \), calculate the accumulated area under the curve of \( f(x) \) between the limits \( a \) and \( b \). They provide precise information about the total accumulation or net change of function values over an interval.
  • The lower limit of a definite integral is \( a \), and the upper limit is \( b \).
  • A definite integral gives a specific numerical value, contrasting with indefinite integrals which include a constant of integration \( C \).
  • Definite integrals can involve infinite limits, referred to as improper integrals. These require careful evaluation of limits at infinity.
In our exercise, the definite integral \( \int_{-\infty}^{0} \) is solved using integration by parts. We handle the improper nature of the integral by evaluating limits as \( \theta \) approaches infinity. By considering both upper and lower bounds carefully, especially with infinite limits, the evaluation yields a precise result.

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Most popular questions from this chapter

Sine-integral function The integral $$\operatorname{Si}(x)=\int_{0}^{x} \frac{\sin t}{t} d t,$$ called the sine-integral function, has important applications in optics. \(\begin{equation} \begin{array}{l}{\text { a. Plot the integrand }(\sin t) / t \text { for } t>0 . \text { Is the sine-integral }} \\ \quad {\text { function everywhere increasing or decreasing? Do you think }} \\ \quad {\text { Si }(x)=0 \text { for } x>0 ? \text { Check your answers by graphing the }} \\ \quad {\text { function Si }(x) \text { for } 0 \leq x \leq 25 .} \\ {\text { b. Explore the convergence of }}\end{array} \end{equation}\) $$\int_{0}^{\infty} \frac{\sin t}{t} d t.$$ If it converges, what is its value?

Evaluate $$\int_{3}^{\infty} \frac{d x}{x \sqrt{x^{2}-9}}.$$

Show that if \(f(x)\) is integrable on every interval of real numbers and \(a\) and \(b\) are real numbers with \(a < b\) , then \(\begin{equation} \begin{array}{l}{\text { a. } \int_{-\infty}^{a} f(x) d x \text { and } \int_{a}^{\infty} f(x) d x \text { both converge if and only if }} \\ \quad {\int_{-\infty}^{b} f(x) d x \text { and } \int_{b}^{\infty} f(x) d x \text { both converge. }} \\ {\text { b. } \int_{-\infty}^{a} f(x) d x+\int_{a}^{\infty} f(x) d x=\int_{-\infty}^{b} f(x) d x+\int_{b}^{\infty} f(x) d x} \\ {\quad \text { when the integrals involved converge. }}\end{array} \end{equation}\)

Your engineering firm is bidding for the contract to construct the tunnel shown here. The tunnel is 300 \(\mathrm{ft}\) long and 50 \(\mathrm{ft}\) wide at the base. The cross-section is shaped like one arch of the curve \(y=25 \cos (\pi x / 50) .\) Upon completion, the tunnel's inside surface (excluding the roadway) will be treated with a waterproof sealer that costs \(\$ 2.35\) per square foot to apply. How much will it cost to apply the sealer? (Hint: Use numerical integration to find the length of the cosine curve.)

Use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integrals for convergence. If more than one method applies, use whatever method you prefer. $$\int_{1}^{\infty} \frac{d x}{x^{3}+1}$$

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