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The integrals in Exercises \(1-40\) are in no particular order. Evaluate each integral using any algebraic method or trigonometric identity you think is appropriate, and then use a substitution to reduce it to a standard form. $$ \int \frac{x^{2}}{x^{2}+1} d x $$

Short Answer

Expert verified
The integral evaluates to \( x - \tan^{-1}(x) + C \).

Step by step solution

01

Analyzing the Integral

We need to evaluate the integral \( \int \frac{x^2}{x^2+1} \, dx \). It is a rational function where the numerator's degree is equal to the denominator's degree.
02

Algebraic Manipulation

Divide the numerator by the denominator: \( \frac{x^2}{x^2+1} = 1 - \frac{1}{x^2+1} \). This simplifies the integral to two separate integrals: \( \int 1 \, dx - \int \frac{1}{x^2+1} \, dx \).
03

Evaluating Each Part Separately

First, solve \( \int 1 \, dx = x + C_1 \), where \(C_1\) is the constant of integration. Next, solve \( \int \frac{1}{x^2+1} \, dx = \tan^{-1}(x) + C_2 \), where \(C_2\) is another constant of integration. Both results use standard integral formulas.
04

Combining the Results

Combine the two results to express the solution of the original integral: \( x - \tan^{-1}(x) + C \). Here, \(C\) is the constant of integration that combines \(C_1\) and \(C_2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Functions
A rational function is a fraction where both the numerator and the denominator are polynomials. These types of functions often appear in calculus problems, particularly in integrals and derivatives. For our specific problem, the rational function is \( \frac{x^2}{x^2+1} \).
  • The degree of the polynomial in the numerator is 2, which is the same as the degree of the polynomial in the denominator.
  • This characteristic makes the function perfect for division because the degrees match up.
In the solution, we tackled this by dividing the expressions, resulting in a simpler form: \( 1 - \frac{1}{x^2+1} \). Therefore, much like simplifying fractions in arithmetic, dividing polynomials helps to break down the integral into more manageable pieces. This process is essential in solving complex rational functions in integration.
Trigonometric Identities
Trigonometric identities are equations that involve trigonometric functions like sine, cosine, and tangent. These identities hold true for all values of the variables where the functions are defined. In calculus, they can simplify integrals by transforming them into forms that are easier to evaluate.
  • For instance, the identity \( \int \frac{1}{x^2+1} \, dx = \tan^{-1}(x) + C_2 \) is quite handy here.
This particular identity relates the inverse tangent (arctan) function to a simple rational function. Using it allows us to solve integrals more efficiently. When you see \( \frac{1}{x^2+1} \) in an integral, it’s a clear signal to use the inverse tangent function, effectively reducing the problem to a standard form. This transformation streamlines the calculus process and is a critical tool in your mathematical toolkit.
Substitution Method
The substitution method, also known as "u-substitution," is a technique used to simplify the process of integration by making a change of variables. It works by replacing a complex or awkward expression with a single variable.
  • The goal is to transform the integral into a standard form, which is easier to solve.
  • In our problem, however, the simplification steps made substitution unnecessary because the integral was already broken down into manageable pieces, \( 1 \) and \( \frac{1}{x^2+1} \).
However, understanding substitution is crucial for more complicated integrals where direct techniques are not applicable. Always be ready to identify parts of an integral that might benefit from substitution. It's an extremely potent method to have in your calculus arsenal, often making what seems daunting manageable through clever use of transformation.

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Most popular questions from this chapter

Cholesterol levels The serum cholesterol levels of children aged 12 to 14 years follows a normal distribution with mean \(\mu=162\) mg/dl and standard deviation \(\sigma=28 \mathrm{mg} / \mathrm{dl} .\) In a population of 1000 of these children, how many would you expect to have serum cholesterol levels between 165 and 193\(?\) between 148 and 167\(?\)

Use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integrals for convergence. If more than one method applies, use whatever method you prefer. $$\int_{4}^{\infty} \frac{d x}{\sqrt{x}-1}$$

Suppose you toss a fair coin \(n\) times and record the number of heads that land. Assume that \(n\) is large and approximate the discrete random variable \(X\) with a continuous random variable that is normally distributed with \(\mu=n / 2\) and \(\sigma=\sqrt{n} / 2 .\) If \(n=400\) find the given probabilities. $$ \begin{array}{ll}{\text { a. } P(190 \leq X<210)} & {\text { b. } P(X<170)} \\\ {\text { c. } P(X>220)} & {\text { d. } P(X=300)}\end{array} $$

Use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integrals for convergence. If more than one method applies, use whatever method you prefer. $$\int_{0}^{1} \frac{d t}{t-\sin t}(\operatorname{Hint} : t \geq \sin t \text { for } t \geq 0)$$

Normal probability distribution The function $$f(x)=\frac{1}{\sigma \sqrt{2 \pi}} e^{-\frac{1}{2}\left(\frac{x-\mu}{\sigma}\right)^{2}}$$ is called the normal probability density function with mean \(\mu\) and standard deviation \(\sigma .\) The number \(\mu\) tells where the distribution is centered, and \(\sigma\) measures the "scatter" around the mean. (See Section 8.9. $$\begin{array}{c}{\text { From the theory of probability, it is known that }} \\\ {\int_{-\infty}^{\infty} f(x) d x=1}\end{array}$$ In what follows, let \(\mu=0\) and \(\sigma=1.\) a. Draw the graph of \(f .\) Find the intervals on which \(f\) is increasing, the intervals on which \(f\) is decreasing, and any local extreme values and where they occur. b. Evaluate $$\int_{-n}^{n} f(x) d x$$ for \(n=1,2,\) and 3. c. Give a convincing argument that $$\int_{-\infty}^{\infty} f(x) d x=1.$$ (Hint: Show that \(0 < f(x) < e^{-x / 2}\) for \(x > 1,\) and for \(b >1,\) $$\int_{b}^{\infty} e^{-x / 2} d x \rightarrow 0 \quad \text { as } \quad b \rightarrow \infty_{ .} )$$

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