/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 The integrals converge. Evaluate... [FREE SOLUTION] | 91Ó°ÊÓ

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The integrals converge. Evaluate the integrals without using tables. $$\int_{0}^{2} \frac{s+1}{\sqrt{4-s^{2}}} d s$$

Short Answer

Expert verified
The integral evaluates to \( 2 + \frac{\pi}{2} \).

Step by step solution

01

Identify the Integral Type

The integral \( \int_{0}^{2} \frac{s+1}{\sqrt{4-s^{2}}} \, ds \) involves the expression \( \frac{1}{\sqrt{4-s^{2}}} \). This expression hints at a trigonometric substitution because it resembles the derivative related to \( \sin^{-1}(x) \).
02

Choose the Trigonometric Substitution

Use the substitution \( s = 2\sin(\theta) \), hence \( ds = 2\cos(\theta) \, d\theta \). This substitution is suitable as \( 4 - s^2 = 4 - (2\sin(\theta))^2 = 4\cos^2(\theta) \).
03

Change the Integral Limits

When \( s = 0 \), \( \theta = 0 \) since \( 0 = 2\sin(0) \). When \( s = 2 \), \( \theta = \frac{\pi}{2} \) because \( 2 = 2\sin(\frac{\pi}{2}) \). The limits of integration change from \( 0 \) to \( \frac{\pi}{2} \).
04

Substitute and Simplify the Integral

Substitute \( s = 2\sin(\theta) \) into the integral to get:\[ \int_{0}^{\pi/2} \frac{2\sin(\theta) + 1}{\sqrt{4 - (2 \sin(\theta))^2}} \cdot 2\cos(\theta) \, d\theta = \int_{0}^{\pi/2} (2\sin(\theta) + 1) \, d\theta \]This simplifies to two integrals: \( 2\int_{0}^{\pi/2} \sin(\theta) \, d\theta + \int_{0}^{\pi/2} 1 \, d\theta \).
05

Evaluate the Integrals

The integral \( \int \sin(\theta) \, d\theta = -\cos(\theta) + C \). Therefore, \( \int_{0}^{\pi/2} \sin(\theta) \, d\theta = [-\cos(\theta)]_{0}^{\pi/2} = [-\cos(\frac{\pi}{2}) + \cos(0)] = 1 \).Also, the integral \( \int_{0}^{\pi/2} 1 \, d\theta = [\theta]_{0}^{\pi/2} = \frac{\pi}{2} \).
06

Add the Results of the Integrals

Combine the results: \[2 \times 1 + \frac{\pi}{2} = 2 + \frac{\pi}{2}\].
07

Write the Final Answer

The value of the integral \( \int_{0}^{2} \frac{s+1}{\sqrt{4-s^{2}}} \) is \( 2 + \frac{\pi}{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration Techniques
Integration techniques are essential tools for solving more complex integrals that cannot be approached directly using simple antidifferentiation. One common technique is **trigonometric substitution**, which is particularly useful when dealing with integrals that involve square roots of expressions resembling the Pythagorean identity.
Consider an integral with the form \(\sqrt{a^2 - x^2}\). This often suggests a trigonometric substitution such as \(x = a\sin(\theta)\), which simplifies the square root expression into something involving a single trigonometric function, because \(\sqrt{a^2 - a^2\sin^2(\theta)} = a\cos(\theta)\).
The process of substitution changes the variable and can simplify integration limits, making the integrand easier to manage. The essence of this technique is transforming a difficult integral into a familiar standard form that is straightforward to evaluate.
  • Recognize expressions that match trigonometric identities.
  • Make a suitable substitution to simplify the integral.
  • Transform the integration limits accordingly.
Mastering these techniques allows for tackling a broader range of mathematical problems effectively.
Definite Integrals
Definite integrals represent the signed area under a curve defined by a function between two limits. Unlike indefinite integrals, which include a constant of integration, definite integrals yield a specific number. This concept is crucial in determining quantities like area, displacement, and total accumulation over an interval.
For definite integrals, the computation process typically involves:
  • Identifying the limits of integration which signify the bounds.
  • Evaluating the integral over these bounds and applying the **Fundamental Theorem of Calculus**.
For instance, when we perform substitution on limits, like substituting \(s = 0\) and \(s = 2\) to \(\theta = 0\) and \(\theta = \frac{\pi}{2}\), it aligns the integrand with the new variable of integration. The result of evaluating the definite integral is a concise expression that conveys the combined area between the curve and the x-axis within the given limits.
Trigonometric Functions
Trigonometric functions, which include sine, cosine, and others, are foundational in mathematics, describing periodic phenomena and relationships in right triangles. In the context of integrals, they can simplify complex integrands, especially when square roots or quadratic expressions are involved.
Using trigonometric substitutions like \(s = 2\sin(\theta)\) is beneficial because it leverages the property of trigonometric identities, such as \(\sin^2(\theta) + \cos^2(\theta) = 1\), to simplify the integration process. These substitutions are particularly powerful when our integrand reflects the derivative of an inverse trigonometric function, as seen with \(\frac{1}{\sqrt{4-s^{2}}}\) resembling the derivative of \(\sin^{-1}(x)\).
  • The substitution aligns with standard identities, making the integrand more manageable.
  • Common choices involve manipulating \(\tan\), \(\sin\), and \(\cos\) substitutions.
  • Identifying when and how to use these substitutions is key to solving complex integrals effectively.
Understanding these functions and their properties underpins the ability to handle a variety of integration challenges.

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