Chapter 7: Problem 60
Find the derivative of \(y\) with respect to the given independent variable. $$y=t^{1-e}$$
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Chapter 7: Problem 60
Find the derivative of \(y\) with respect to the given independent variable. $$y=t^{1-e}$$
These are the key concepts you need to understand to accurately answer the question.
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In Exercises \(25-36,\) find the derivative of \(y\) with respect to the appropriate variable. \(y=\cos ^{-1} x-x \operatorname{sech}^{-1} x\)
Use the identity $$\csc ^{-1} u=\frac{\pi}{2}-\sec ^{-1} u$$ to derive the formula for the derivative of \(\csc ^{-1} u\) in Table 7.3 from the formula for the derivative of \(\sec ^{-1} u .\)
Evaluate the integrals in Exercises \(67-74\) in terms of a. inverse hyperbolic functions. b. natural logarithms. $$\int_{1}^{e} \frac{d x}{x \sqrt{1+(\ln x)^{2}}}$$
Solve the initial value problems in Exercises \(103-106\) $$ \frac{d y}{d x}=\frac{1}{x \sqrt{x^{2}-1}}, \quad x>1 ; \quad y(2)=\pi $$
Find the limits in Exercises \(91-98\) $$ \lim _{x \rightarrow \infty} x \tan ^{-1} \frac{2}{x} $$
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