Chapter 7: Problem 43
Evaluate the integrals in Exercises 37-54. $$\int_{1}^{2} \frac{2 \ln x}{x} d x$$
Short Answer
Expert verified
The integral evaluates to \((\ln 2)^2\).
Step by step solution
01
Identify the Integral and Method
The integral given is \( \int_{1}^{2} \frac{2 \ln x}{x} \, dx \). It is a typical integration problem suitable for substitution. We notice that the integrand involves \( \ln x \), and its derivative \( \frac{1}{x} \) appears in the denominator, suggesting substitution might simplify the integral.
02
Choose a Suitable Substitution
To simplify the integration process, we choose the substitution \( u = \ln x \). Then, differentiate with respect to \( x \) to find \( du \): \( \frac{du}{dx} = \frac{1}{x} \), implying \( du = \frac{1}{x} \, dx \). This allows us to rewrite the integral as \( \int 2u \, du \).
03
Change the Limits of Integration
Since we are switching from \( x \) to \( u \), we must also change our limits of integration. For \( x = 1 \), \( u = \ln 1 = 0 \). For \( x = 2 \), \( u = \ln 2 \). The new limits of integration for \( u \) are from 0 to \( \ln 2 \).
04
Integrate with Respect to \( u \)
Now, integrate the function in terms of \( u \): \( \int 2u \, du = 2 \int u \, du = 2 \left( \frac{u^2}{2} \right) = u^2 \).
05
Evaluate the Indefinite Integral at the New Limits
With the antiderivative \( u^2 \), evaluate from 0 to \( \ln 2 \): \[ u^2 \Bigg|_{0}^{\ln 2} = (\ln 2)^2 - (0)^2 = (\ln 2)^2. \]
06
Conclusion
The integral \( \int_{1}^{2} \frac{2 \ln x}{x} \, dx \) evaluates to \( (\ln 2)^2 \). This completes the evaluation of the definite integral.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integral
A definite integral represents the accumulation of quantities, such as area under a curve, over a specific interval. In simpler terms, it's about finding the signed area between the graph of a function and the x-axis, from one point to another.
Here's a breakdown of the components involved in a definite integral:
Definite integrals can give us a wealth of information beyond just area, such as average values and total change, making them versatile tools in calculus.
Here's a breakdown of the components involved in a definite integral:
- The integral sign \( \int \) indicates a summation process, adding up infinitely small quantities.
- The function inside the integral, known as the integrand, is the expression being integrated. Here, the integrand is \( \frac{2 \ln x}{x} \).
- The limits of integration, noted at the bottom and top of the integral sign \( [1, 2] \), specify the interval over which the integration occurs.
- The differential \( dx \) indicates that the integration is with respect to \( x \).
Definite integrals can give us a wealth of information beyond just area, such as average values and total change, making them versatile tools in calculus.
Substitution Method
The substitution method, also referred to as \( u \)-substitution, is a powerful technique in solving integrals. It transforms a complex integrand into a much simpler form. Imagine working on a puzzle; substitution provides a key piece that can make everything fall into place.
To use this method, follow these essential steps:
To use this method, follow these essential steps:
- Choose a substitution variable \( u \). Identify part of the integrand that, when substituted, simplifies the integral. In this case, \( u = \ln x \).
- Differentiate \( u \) with respect to \( x \). For \( u = \ln x \), we have \( du = \frac{1}{x} \, dx \).
- Rewrite the integral in terms of \( u \). This involves replacing all \( x \)-dependent parts with \( u \): \( \int 2 \ln x \frac{1}{x} \, dx = \int 2u \, du \).
- Adjust the limits of integration. Convert the original limits in terms of \( x \) to \( u \): when \( x=1 \), \( u = \ln 1 = 0 \), and when \( x=2 \), \( u = \ln 2 \).
- Integrate and back-substitute if needed. Perform the integration in terms of \( u \) and, if it's an indefinite integral, replace \( u \) back with \( x \).
Logarithmic Functions
Logarithmic functions, particularly natural logarithms, are essential in many aspects of calculus. The natural logarithm, denoted as \( \ln x \), is the inverse of the exponential function and is defined only for \( x > 0 \).
Understanding logarithms is key for grasping their integral properties.
Not only are logarithms handy analytically, but they also frequently arise in real-world applications, enhancing their importance in calculus.
Understanding logarithms is key for grasping their integral properties.
- The derivative of \( \ln x \) is \( \frac{1}{x} \), which plays a crucial role in integration processes.
- When integrating functions involving \( \ln x \), substitution often comes into play because the derivative \( \frac{1}{x} \) can simplify complex expressions.
- Natural logarithms simplify calculations involving growth processes, like in population studies or finance.
Not only are logarithms handy analytically, but they also frequently arise in real-world applications, enhancing their importance in calculus.