Chapter 7: Problem 126
Find the values of the following. $$ \text { a. } \sec ^{-1}(-3) \quad \text { b. } \csc ^{-1} 1.7 \quad \text { c. } \cot ^{-1}(-2) $$
Short Answer
Expert verified
\( \sec^{-1}(-3) = \cos^{-1}(-1/3) \), \( \csc^{-1}(1.7) = \sin^{-1}(1/1.7) \), \( \cot^{-1}(-2) = \pi - \tan^{-1}(1/2) \).
Step by step solution
01
Understanding Secant Inverse
The function \( \sec^{-1}(x) \) gives the angle \( \theta \) such that \( \sec(\theta) = x \). The range of \( \sec^{-1}(x) \) is \([0, \pi] \) except \( \frac{\pi}{2} \). For \( \sec^{-1}(-3) \), we want an angle in the range where \( \sec(\theta) = -3 \). This angle is in the second quadrant because secant is negative there.
02
Calculate \( \theta \) for Secant
\( \sec(\theta) = -3 \) implies \( \cos(\theta) = -\frac{1}{3} \). The angle in the second quadrant where \( \cos(\theta) = -\frac{1}{3} \) is \( \theta = \cos^{-1}(-\frac{1}{3}) \). Thus, \( \sec^{-1}(-3) = \cos^{-1}(-\frac{1}{3}) \).
03
Understanding Cosecant Inverse
The function \( \csc^{-1}(x) \) gives the angle \( \theta \) such that \( \csc(\theta) = x \). The range for \( \csc^{-1}(x) \) is \([-\frac{\pi}{2}, 0) \cup (0, \frac{\pi}{2}] \). For \( \csc^{-1}(1.7) \), we need \( \theta \) in the first quadrant as \( 1.7 > 1 \).
04
Calculate \( \theta \) for Cosecant
\( \csc(\theta) = 1.7 \) implies \( \sin(\theta) = \frac{1}{1.7} \). The angle in the first quadrant where \( \sin(\theta) = \frac{1}{1.7} \) can be found using \( \theta = \sin^{-1}(\frac{1}{1.7}) \). Thus, \( \csc^{-1}(1.7) = \sin^{-1}(\frac{1}{1.7}) \).
05
Understanding Cotangent Inverse
The function \( \cot^{-1}(x) \) gives the angle \( \theta \) such that \( \cot(\theta) = x \). The range of \( \cot^{-1}(x) \) is \((0, \pi) \). For \( \cot^{-1}(-2) \), we need an angle where cotangent is negative, which is in the second quadrant.
06
Calculate \( \theta \) for Cotangent
\( \cot(\theta) = -2 \) implies \( \tan(\theta) = -\frac{1}{2} \). The angle in the second quadrant where \( \tan(\theta) = -\frac{1}{2} \) can be found using \( \theta = \pi - \tan^{-1}(\frac{1}{2}) \). Thus, \( \cot^{-1}(-2) = \pi - \tan^{-1}(\frac{1}{2}) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Secant Inverse
The secant inverse, denoted as \( \sec^{-1}(x) \), is a function that finds an angle whose secant value is \( x \). Understanding this requires knowing that secant is the reciprocal of cosine: \( \sec(\theta) = \frac{1}{\cos(\theta)} \). The range for \( \sec^{-1}(x) \) is \([0, \pi] \), excluding \( \frac{\pi}{2} \), because \( \sec(\theta) \) can never be zero or undefined in this range. Let's evaluate \( \sec^{-1}(-3) \):- We look for an angle \( \theta \) such that \( \sec(\theta) = -3 \).- This implies \( \cos(\theta) = -\frac{1}{3} \), and \( \theta \) should be in the second quadrant where cosine values are negative.- Therefore, \( \sec^{-1}(-3) \) can be given as \( \cos^{-1}(-\frac{1}{3}) \), which yields the angle whose cosine is \(-\frac{1}{3}\) in the valid range.
Cosecant Inverse
The cosecant inverse function, \( \csc^{-1}(x) \), finds an angle for which the cosecant is \( x \). Cosecant is the reciprocal of sine, meaning \( \csc(\theta) = \frac{1}{\sin(\theta)} \). The range for \( \csc^{-1}(x) \) is \([-\frac{\pi}{2}, 0) \cup (0, \frac{\pi}{2}] \), which helps to determine if the angle lies in the first or the fourth quadrants. To find \( \csc^{-1}(1.7) \):- Since \( 1.7 > 1 \), \( \theta \) should be in the first quadrant, where both sine and cosecant are positive.- We calculate \( \sin(\theta) = \frac{1}{1.7} \), which means \( \theta = \sin^{-1}(\frac{1}{1.7}) \).- Thus, \( \csc^{-1}(1.7) \) results in the angle whose sine is \( \frac{1}{1.7} \), fitting in the specified range.
Cotangent Inverse
The cotangent inverse, expressed as \( \cot^{-1}(x) \), provides an angle whose cotangent value is \( x \). Cotangent relates to tangent as \( \cot(\theta) = \frac{1}{\tan(\theta)} \). The function's range is \((0, \pi) \), helping identify the correct quadrant for the angle's position.For \( \cot^{-1}(-2) \):- We need an angle \( \theta \) where \( \cot(\theta) = -2 \), meaning \( \tan(\theta) = -\frac{1}{2} \).- This places \( \theta \) in the second quadrant, where tangent is negative and cotangent follows suit.- Computation gives \( \theta = \pi - \tan^{-1}(\frac{1}{2}) \), representing \( \cot^{-1}(-2) \), where the angle resolves to balancing \( -\frac{1}{2} \) in the allowed range.