Chapter 5: Problem 81
If av(f) really is a typical value of the integrable function \(f(x)\) on \([a, b],\) then the constant function av(f) should have the same integral over \([a, b]\) as \(f .\) Does it? That is, does $$ \int_{a}^{b} \operatorname{av}(f) d x=\int_{a}^{b} f(x) d x ? $$ Give reasons for your answer.
Short Answer
Step by step solution
Understanding the Problem
Defining the Average of Function
Setting Up the Equation
Calculating the Integral of the Constant Function
Equating and Simplifying
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integral
Key characteristics include:
- The limits \(a\) and \(b\) specify the starting and ending points on the function's x-axis.
- The outcome of a definite integral is a number, which represents the total area.
The definite integral is fundamental in finding the average value of a function over a given interval. It translates to asking, "What is the appropriate measure of this function’s overall behavior between \(a\) and \(b\)?" With this concept, problems like the one in our exercise find clarity as it ensures the link between constants and variable functions over specific intervals.
Constant Function
In the context of definite integrals, the integral of a constant function over an interval \([a, b]\) can be easily calculated. The formula shows that it's simply the product of the constant \(c\) and the length of the interval \((b-a)\). This is written as:
- \( \int_{a}^{b} c \, dx = c(b-a) \)
Applying this to our exercise, if the average value \( \text{av}(f) \) of a function over \([a, b]\) behaves as a constant function, its integral should ideally give us the same result as the integral of the function \(f(x)\) itself over the same interval.
Integrable Function
Main characteristics include:
- The function must be well-behaved, meaning it should not exhibit undefined behavior like discontinuities across the interval.
- Its definite integral \( \int_{a}^{b} f(x) \, dx \) produces a finite result.