/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Evaluate the integrals in Exerci... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate the integrals in Exercises \(17-50\) $$ \int(x+5)(x-5)^{1 / 3} d x $$

Short Answer

Expert verified
\(\frac{3}{7}(x-5)^{7/3} + \frac{15}{4}(x-5)^{4/3} + C\)

Step by step solution

01

Expand the Product

First, distribute the term \((x-5)^{1/3}\) with \(x+5\). This gives:\[(x+5)(x-5)^{1/3} = x(x-5)^{1/3} + 5(x-5)^{1/3}\]
02

Integrate Separately

Now, integrate each term separately:For the first term, \(\int x(x-5)^{1/3} \, dx\), use the substitution method. Let \(u = x-5\), which gives \(du = dx\) and \(x = u + 5\). The integral becomes:\[\int (u + 5) u^{1/3} \, du = \int (u^{4/3} + 5u^{1/3}) \, du\]For the second term, \(\int 5(x-5)^{1/3} \, dx\), again substitute \(u = x-5\):\[\int 5u^{1/3} \, du\]
03

Evaluate the Integrals

Integrate each term:For \(\int u^{4/3} \, du\), the integral is:\[\frac{3}{7} u^{7/3} + C_1\]For \(\int 5u^{1/3} \, du\), the integral is:\[\frac{5 imes 3}{4} u^{4/3} + C_2 = \frac{15}{4} u^{4/3}\]Finally, for \(\int 5u^{1/3} \, du\):\[5 \times \frac{3}{4}u^{4/3} = \frac{15}{4}u^{4/3} + C_3\]
04

Combine and Substitute Back

Combine the results from Step 3, and substitute \(u = x-5\) back into the expression:\[\frac{3}{7}(x-5)^{7/3} + \frac{15}{4}(x-5)^{4/3} + C\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substitution Method
The Substitution Method is a powerful technique used in calculus to simplify complex integrals. It involves changing variables in the integral to make the integration process easier. Essentially, you replace a part of the integral with a new variable, often denoted as \( u \), and find a corresponding \( du \). This method transforms the original integral into a simpler form.
For example, consider the integral from the exercise: \( \int(x+5)(x-5)^{1/3} \, dx \). To simplify, you can let \( u = x-5 \). Thus, \( du = dx \) and \( x = u + 5 \). When you substitute these into the integral, it becomes:
  • \( \int (u + 5) u^{1/3} \, du = \int (u^{4/3} + 5u^{1/3}) \, du \)
This transformation makes the integral much easier to handle, as you can integrate term by term. Once integrated, you substitute back in the original expression for \( u \) to get the final result.
Polynomial Expansion
Polynomial Expansion is a process used to multiply expressions that involve binomials or polynomials. By expanding the polynomial, we rewrite it in a form that is easier to manipulate for further operations like integration or differentiation.
In this exercise, the phrase \( (x+5)(x-5)^{1/3} \) represents the multiplication of a binomial and a term involving a fractional exponent. To expand, you multiply each part of \( x+5 \) by \( (x-5)^{1/3} \):
  • First, \( x(x-5)^{1/3} \) which remains as it is but prepares for integration.
  • Second, \( 5(x-5)^{1/3} \), which also sets the stage for independent integration.
This expansion simplifies the process of finding the integral by allowing each term to be integrated separately.
Definite and Indefinite Integrals
Integrals are a fundamental part of calculus, categorized mainly into definite and indefinite integrals. An indefinite integral, like the one in this exercise, provides a general form of the anti-derivative of a function, plus a constant \( C \).
The exercise involves finding an indefinite integral for expressions such as \( \int u^{4/3} \, du \) and \( \int 5u^{1/3} \, du \). The result is a general solution involving a constant \( C \) since the limits of integration are not specified.
For indefinite integrals, always remember:
  • They represent a family of functions since the constant \( C \) can be any real number.
  • The power rule for integration, \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \), is commonly used.
If the problem were a definite integral, you'd have limits of integration and you'd find the exact area under the curve by computing the difference \( F(b) - F(a) \) after integration.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises \(75-78\) , let \(F(x)=\int_{a}^{x} f(t) d t\) for the specified function \(f\) and interval \([a, b] .\) Use a CAS to perform the following steps and answer the questions posed. \begin{equation} \begin{array}{l}{\text { a. Plot the functions } f \text { and } F \text { together over }[a, b] \text { . }} \\ {\text { b. Solve the equation } F^{\prime}(x)=0 . \text { What can you see to be true about }} \\ {\text { the graphs of } f \text { and } F \text { at points where } F^{\prime}(x)=0 \text { . Is your observation }} \\ {\text { borne out by Part } 1 \text { of the Fundamental Theorem coupled }} \\ {\text { with information provided by the first derivative? Explain your }} \\ {\text { answer. }}\\\\{\text { c. Over what intervals (approximately) is the function } F \text { increasing }} \\\ {\text { and decreasing? What is true about } f \text { over those intervals? }}\end{array} \end{equation} \begin{equation} \begin{array}{l}{\text { d. Calculate the derivative } f^{\prime} \text { and plot it together with } F . \text { What can }} \\ {\text { you see to be true about the graph of } F \text { at points where } f^{\prime}(x)=0 ?} \\\ {\text { Is your observation borne out by Part } 1 \text { of the Fundamental Theorem? }} \\ {\text { Explain your answer. }}\end{array} \end{equation} $$f(x)=x \cos \pi x, \quad[0,2 \pi]$$

Find the areas of the regions enclosed by the lines and curves in Exercises \(63-70\) . $$ y=2 \sin x \quad \text { and } \quad y=\sin 2 x, \quad 0 \leq x \leq \pi $$

Find the area of the propeller-shaped region enclosed by the curves \(x-y^{1 / 3}=0\) and \(x-y^{1 / 5}=0\)

In Exercises \(33-36,\) graph each function \(f(x)\) over the given interval.Partition the interval into four sub intervals of equal length. Then add to your sketch the rectangles associated with the Riemann sum\(\Sigma_{k=1}^{4} f\left(c_{k}\right) \Delta x_{k},\) given that \(c_{k}\) is the (a) left-hand endpoint, (b) right-hand endpoint, (c) midpoint of the \(k\) the sub interval. (Make a separate sketch for each set of rectangles.) Find the norm of the partition \(P=\\{-2,-1.6,-0.5,0,0.8,1\\}\) $$f(x)=3 x^{2} over the interval [0,1]$$

In Exercises \(55-62,\) graph the function and find its average value over the given interval. $$ g(x)=|x|-1 \quad \text { on } \quad \text { a. }[-1,1], \text { b. }[1,3], \text { and } c .[-1,3] $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.