/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 81 In Exercises \(81-86,\) you will... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercises \(81-86,\) you will use a CAS to help find the absolute extrema of the given function over the specified closed interval. Perform the following steps. a. Plot the function over the interval to see its general behavior there. b. Find the interior points where \(f^{\prime}=0 .\) (In some exercises, you may have to use the numerical equation solver to approximate a solution.) You may want to plot \(f^{\prime}\) as well. c. Find the interior points where \(f^{\prime}\) does not exist. d. Evaluate the function at all points found in parts (b) and (c) and at the endpoints of the interval. e. Find the function's absolute extreme values on the interval and identify where they occur. $$ f(x)=x^{4}-8 x^{2}+4 x+2, \quad[-20 / 25,64 / 25] $$

Short Answer

Expert verified
The absolute extrema occur at the critical points and endpoints. Compare function values to identify them.

Step by step solution

01

Plot the Function

Using a computer algebra system (CAS) or graphing calculator, plot the function \( f(x) = x^4 - 8x^2 + 4x + 2 \) over the interval \( \left [-\frac{20}{25}, \frac{64}{25} \right ] \). This will help us visualize the behavior of the function and locate potential extrema.
02

Find Critical Points where \( f'(x) = 0 \)

First, find the derivative of \( f(x) \); \( f'(x) = 4x^3 - 16x + 4 \). Then solve \( 4x^3 - 16x + 4 = 0 \) within the interval \( \left [-\frac{20}{25}, \frac{64}{25} \right ] \). Utilize a CAS to find these solutions as they may be complex to solve analytically.
03

Determine Points where \( f'(x) \) Does Not Exist

Examine \( f'(x) = 4x^3 - 16x + 4 \). This is a polynomial, and thus defined for all real \( x \). Therefore, there are no points in the interval where \( f'(x) \) does not exist.
04

Evaluate \( f(x) \) at All Important Points

Evaluate \( f(x) \) at the critical points found in Step 2 and at the endpoints of the interval \( x = -\frac{20}{25} \) and \( x = \frac{64}{25} \). Calculate and compare these values to find potential extrema.
05

Identify Absolute Extrema

Compare the values obtained from evaluating \( f(x) \) at each of the important points. The largest value will be the absolute maximum and the smallest value will be the absolute minimum over the given interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Absolute Extrema
When you're trying to find absolute extrema of a function, you're essentially pinpointing the highest and lowest values the function takes on over a specified interval. These are known as the **absolute maximum** and **absolute minimum**, respectively. To effectively find these extrema, the process involves evaluating the function at certain key points:
  • Endpoints of the interval: These are the boundaries of the region you’re analyzing.
  • Critical points: These are points where the derivative is zero or does not exist (though in polynomial functions, the derivative generally exists everywhere).
By comparing the values of the function at these critical points and endpoints, you determine where the function reaches its peak and lowest trough within the interval. This is a crucial part of calculus that helps not only in pure math but also in many applied fields to ascertain optimal performance, cost, resource utilization, etc.
Identifying Critical Points
Critical points are vital in finding where a function changes its rate of increase or decrease. Understanding critical points begins with analyzing the derivative of the function. The derivative, denoted as \( f'(x) \), reveals how the function **slopes** or **changes**.
  • A critical point occurs where \( f'(x) = 0 \), meaning a horizontal tangent line, suggesting a potential peak or trough (the maximum or minimum).
  • It can also be where the derivative is undefined, although for polynomials like in this exercise, the derivative exists everywhere.
To locate these points, solve the equation \( f'(x) = 0 \). The solutions within your specified interval are your critical points. Once identified, these points are part of assessing the function's behavior within the interval, aiding in finding the absolute extrema.
Performing Derivative Analysis
Derivative analysis is an investigation into how a function behaves by examining its derivative. The derivative tells us the rate at which the function's value is changing. It helps in understanding:
  • The general trend of the function—whether it's increasing or decreasing.
  • Where the function has peaks, valleys, or flat spots, which correspond to critical points.
By taking the derivative, such as in the exercise where \( f'(x) = 4x^3 - 16x + 4 \), you gain insights into these behavior patterns. Solving \( f'(x) = 0 \) helps locate changes in this behavior. This is the cornerstone of calculus as it reveals changes in dynamics, critical for optimizing and understanding real-world scenarios. Derivative analysis, hence, provides a snapshot of how a system modeled by a function might evolve over time or space.

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Most popular questions from this chapter

The hammer and the feather When Apollo 15 astronaut David Scott dropped a hammer and a feather on the moon to demonstrate that in a vacuum all bodies fall with the same (constant) acceleration, he dropped them from about 4 ft above the ground. The television footage of the event shows the hammer and the feather falling more slowly than on Earth, where, in a vacuum, they would have taken only half a second to fall the 4 ft. How long did it take the hammer and feather to fall 4 ft on the moon? To find out, solve the following initial value problem for \(s\) as a function of \(t\) . Then find the value of \(t\) that makes \(s\) equal to 0 . \begin{equation} \begin{array}{ll}{\text { Differential equation: }} & {\frac{d^{2} s}{d t^{2}}=-5.2 \mathrm{ft} / \mathrm{sec}^{2}} \\ {\text { Initial conditions: }} & {\frac{d s}{d t}=0 \text { and } s=4 \text { when } t=0}\end{array} \end{equation}

Identify the coordinates of any local and absolute extreme points and inflection points. Graph the function. $$y=1-(x+1)^{3}$$

Find the inflection points (if any) on the graph of the function and the coordinates of the points on the graph where the function has a local maximum or local minimum value. Then graph the function in a region large enough to show all these points simultaneously. Add to your picture the graphs of the function's first and second derivatives. How are the values at which these graphs intersect the \(x\)-axis related to the graph of the function? In what other ways are the graphs of the derivatives related to the graph of the function? \(y=\frac{x^{4}}{4}-\frac{x^{3}}{3}-4 x^{2}+12 x+20\)

Find the inflection points (if any) on the graph of the function and the coordinates of the points on the graph where the function has a local maximum or local minimum value. Then graph the function in a region large enough to show all these points simultaneously. Add to your picture the graphs of the function's first and second derivatives. How are the values at which these graphs intersect the \(x\)-axis related to the graph of the function? In what other ways are the graphs of the derivatives related to the graph of the function? \(y=x^{3}-12 x^{2}\)

Identify the inflection points and local maxima and minima of the functions graphed. Identify the intervals on which the functions are concave up and concave down. $$y=\frac{x^{4}}{4}-2 x^{2}+4$$

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