Chapter 4: Problem 31
In Exercises \(31-36,\) find all possible functions with the given derivative. $$\text { a. } y^{\prime}=x \quad \text { b. } y^{\prime}=x^{2} \quad \text { c. } y^{\prime}=x^{3}$$
Short Answer
Expert verified
a. \( y = \frac{x^2}{2} + C \); b. \( y = \frac{x^3}{3} + C \); c. \( y = \frac{x^4}{4} + C \).
Step by step solution
01
Understand the Task
The task is to find functions that have the given derivatives. Each sub-problem provides a specific derivative, and we need to find a function whose derivative matches it. Generally, this involves anti-differentiation or finding the indefinite integral.
02
Solve Part (a)
Part (a) requires finding a function whose derivative is \( y' = x \). We need to integrate the function \( x \) with respect to \( x \). The integral is:\[ y = \int x \, dx = \frac{x^2}{2} + C \]where \( C \) is the constant of integration.
03
Solve Part (b)
Part (b) asks for a function whose derivative is \( y' = x^2 \). We integrate the function \( x^2 \) with respect to \( x \). The integral is:\[ y = \int x^2 \, dx = \frac{x^3}{3} + C \]where \( C \) is the constant of integration.
04
Solve Part (c)
Part (c) involves finding a function whose derivative is \( y' = x^3 \). We integrate \( x^3 \) with respect to \( x \). The integral is:\[ y = \int x^3 \, dx = \frac{x^4}{4} + C \]where \( C \) is the constant of integration.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Indefinite Integral
In calculus, the indefinite integral is a fundamental concept that involves finding the integral of a function without specific limits. In other words, it represents a class of functions whose derivative corresponds to the given integrand. The indefinite integral is denoted by the integral symbol followed by the function and the differential variable, such as \(\int x \, dx\). This process is essentially the inverse operation of differentiation.
The indefinite integral is helpful because it allows us to find a family of functions rather than a single solution. When you integrate a function, you gain insight into its entire behavior and its corresponding area under the curve, albeit in a non-specific, general sense.
The indefinite integral is helpful because it allows us to find a family of functions rather than a single solution. When you integrate a function, you gain insight into its entire behavior and its corresponding area under the curve, albeit in a non-specific, general sense.
- It generates a general solution applicable to numerous problems.
- Examples include \(\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\), where \(n\) is a constant not equal to -1.
Constant of Integration
When performing indefinite integrals, a constant of integration is always added to account for the fact that differentiating a constant yields zero. This constant, often represented by \(C\), is crucial to conveying the complete family of possible functions that could be solutions.
Consider the function \( y' = x\). The indefinite integral \(\int x \, dx = \frac{x^2}{2} + C\) implies that there are infinitely many functions with the derivative \(y' = x\), all differing by a constant.
Consider the function \( y' = x\). The indefinite integral \(\int x \, dx = \frac{x^2}{2} + C\) implies that there are infinitely many functions with the derivative \(y' = x\), all differing by a constant.
- It highlights that there are multiple valid antiderivatives.
- Its absence would result in an incorrect representation of the function space.
- Ensures completeness and accuracy in solving differential equations.
Antidifferentiation
Antidifferentiation, commonly known as integration, is the reverse process of differentiation. It requires finding a function whose derivative matches a given function. This process is fundamental when solving differential equations or determining the original function from its rate of change.
By antidifferentiating a function, you essentially "undo" the differentiation, revealing the original function before it was differentiated. For example, given \(y' = x^2\), the antidifferentiation process involves integrating to find \(y = \int x^2 \, dx = \frac{x^3}{3} + C\).
By antidifferentiating a function, you essentially "undo" the differentiation, revealing the original function before it was differentiated. For example, given \(y' = x^2\), the antidifferentiation process involves integrating to find \(y = \int x^2 \, dx = \frac{x^3}{3} + C\).
- Reverses the role of calculating derivative.
- Is key to formulating functions from their rates of change.
- Integral in understanding fundamental principles of calculus.