Chapter 4: Problem 17
In Exercises \(15-20,\) sketch the graph of each function and determine whether the function has any absolute extreme values on its domain. Explain how your answer is consistent with Theorem 1 . $$ g(x)=\left\\{\begin{array}{ll}{-x,} & {0 \leq x<1} \\ {x-1,} & {1 \leq x \leq 2}\end{array}\right. $$
Short Answer
Step by step solution
Understand the Function
Sketch the Graph
Check Function Values
Identify Absolute Extreme Values
Consistency with Theorem 1
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Extreme Values in Piecewise Functions
This indicates that the function reaches its lowest and highest values at the specified points, even though the function is not continuous throughout the domain.
To determine these extrema:
- Evaluate the function at key points such as endpoints and where the function switches its definition.
- Check points close to boundaries for parts of the piecewise function.
- Take note of changes in function behavior within the defined intervals.
Graph Sketching of Piecewise Functions
Here's how you can sketch the graph step by step:
- Identify the equations that define each piece for specific intervals. For \( g(x) \), these are \( -x \) for \( 0 \leq x < 1 \) and \( x-1 \) for \( 1 \leq x \leq 2 \).
- Draw each segment on a separate layer. Start with \( -x \) as it covers \( 0 \leq x < 1 \), resulting in a line with a negative slope passing from (0,0) to just before (1,-1).
- Next, graph \( x-1 \), which starts from (1,0) to (2,1), creating a positive slope.
- Ensure the piecewise segments connect smoothly if they meet at any point in their domain, indicating their transitional behavior.
Continuity and Discontinuity in Piecewise Functions
The function \( g(x) \) experiences a change at \( x = 1 \):
- As you approach \( x = 1 \) from the left (denoted as \( 1^- \)), the function value tends to \(-1\).
- However, directly at \( x = 1 \), the value is defined as \( 0 \) by the second piece of the function.
Although \( g(x) \) is not continuous throughout \([0, 2]\), it still conforms to the basic principles surrounding extrema in closed intervals. Evaluating the value at, and around, each critical point provides the information needed to deal with discontinuities.
Understanding and highlighting these changes are key to analyzing and interpreting piecewise functions effectively in broader mathematical contexts.