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In Exercises \(1-16,\) find an antiderivative for each function. Do as many as you can mentally. Check your answers by differentiation. \begin{equation} \text { a. }\csc ^{2} x \quad \text { b. }-\frac{3}{2} \csc ^{2} \frac{3 x}{2} \quad \text { c. } 1-8 \csc ^{2} 2 x \end{equation}

Short Answer

Expert verified
Antiderivatives: a) \(-\cot x + C\), b) \(\cot \frac{3x}{2} + C\), c) \(x - 4 \cot(2x) + C\).

Step by step solution

01

Understanding an Antiderivative

An antiderivative of a function is a function whose derivative is the original function. To find an antiderivative, we need to know the derivative rules. For trigonometric functions, the derivative of \(-\cot(x)\) is \(\csc^2(x)\).
02

Antiderivative for \(\csc^2 x\)

The function \(\csc^2 x\) is the derivative of \(-\cot x\). Therefore, an antiderivative of \(\csc^2 x\) is \(-\cot x + C\), where \(C\) is a constant of integration.
03

Antiderivative for \(-\frac{3}{2} \csc^2 \frac{3x}{2}\)

Using the chain rule in reverse, the antiderivative of \(\csc^2 u\) is \(-\cot u\) and for \(\csc^2 \left(\frac{3x}{2}\right)\), where \(u = \frac{3x}{2}\), the derivative of \(u\) is \(\frac{3}{2}\). Thus, we multiply by the reciprocal, giving us an antiderivative: \(-\frac{3}{2} \times -\frac{2}{3}\cot\left(\frac{3x}{2}\right) + C = \cot \left(\frac{3x}{2}\right) + C\).
04

Antiderivative for \(1 - 8 \csc^2 2x\)

Break the function into two parts: a constant term and a trigonometric term. The antiderivative of \(1\) is \(x\). For \(-8 \csc^2 2x\), noting \(g(x) = 2x\) and derivative \(2\), the antiderivative is \(-8 \times \frac{1}{2} \cot (2x) = -4 \cot (2x)\). Thus, the antiderivative is \(x - 4 \cot(2x) + C\).
05

Checking by Differentiation

Differentiate each obtained antiderivative to verify correctness.- The derivative of \(-\cot x\) is \(\csc^2 x\).- The derivative of \(\cot \frac{3x}{2}\) using the chain rule is \(-\frac{3}{2} \csc^2 \frac{3x}{2}\).- Differentiating \(x - 4 \cot(2x)\) yields \(1 + 8 \csc^2 2x - 1\), verifying \(1 - 8 \csc^2 2x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus
Calculus is a branch of mathematics that focuses on how things change. At its core, calculus deals with derivatives and integrals. Derivatives measure how a function changes at a specific point, while integrals measure the total accumulation of quantities. In simple terms, if you think of a car driving, derivatives tell you the car's speed, whereas integrals tell you how far the car has traveled.

The process of finding antiderivatives, also known as indefinite integration, reverses differentiation. If you know the derivative of a function, you can find the original function by determining its antiderivative. The antiderivative of a function is not unique; it differs by a constant known as the constant of integration. This concept is foundational to solving many calculus problems, including those involving motion, area, and growth.
Trigonometric Functions
Trigonometric functions like sine, cosine, and cosecant (csc) are relationships among the angles and sides of a triangle. These functions are essential in describing wave patterns, circles, and oscillations.

In calculus, knowing the derivatives and antiderivatives of trigonometric functions is crucial for solving integration problems. For example, the derivative of \( \cot(x) \) is \( -\csc^2(x) \). Recognizing these relationships helps find antiderivatives, as shown in the example where \( \csc^2(x) \) leads us to the antiderivative \( -\cot(x) + C \).

Whenever you see a trigonometric derivative, try recalling the corresponding antiderivative from your calculus toolkit.
Integration Methods
Integration methods are techniques used to find antiderivatives of functions efficiently. These methods can range from simple techniques to more complex ones like substitution and integration by parts. Choosing the right method depends on the function you are trying to integrate.

- **Basic Integration**: This involves integrating basic functions using known rules, like integrating \( x^n \) to get \( \frac{x^{n+1}}{n+1} \, n eq -1 \).

- **Substitution**: Also known as the chain rule in reverse, this method handles more complex functions by simplifying them into basic functions. For example, to integrate \( \csc^2(\frac{3x}{2}) \,\) you first set \( u = \frac{3x}{2} \) and rewrite the integral in terms of \( u \), making it easier to solve.

By mastering these techniques, you can approach a wide range of integration problems with confidence.
Constant of Integration
In calculus, whenever you compute an antiderivative, you must add a constant of integration, often represented by \( C \.\) This constant is crucial because differentiation of a constant results in zero, meaning any constant added to your function will have no effect on its derivative.

For example, if \( F'(x) = f(x) \,\) then any antiderivative \( F(x) \) is \( F(x) = \,F(x) + C \.\) Without knowing additional conditions or constraints, we cannot determine the exact value of \( C \.\)

Ultimately, the constant of integration represents an infinite set of functions that differ only by this constant, highlighting the importance of initial conditions when solving real-world problems using calculus.

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