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In Exercises \(65-70,\) find the value of \((f \circ g)^{\prime}\) at the given value of \(x .\) $$f(u)=\cot \frac{\pi u}{10}, \quad u=g(x)=5 \sqrt{x}, \quad x=1$$

Short Answer

Expert verified
The value of \((f \circ g)'(1)\) is \(-\frac{\pi}{4}\).

Step by step solution

01

Find g'(x)

Start by differentiating the function \( g(x) = 5\sqrt{x} \) with respect to \( x \).Using the chain rule, we have:\[ g'(x) = \frac{d}{dx}[5\sqrt{x}] = 5 \cdot \frac{1}{2}x^{-1/2} = \frac{5}{2\sqrt{x}} \]Thus, \( g'(x) = \frac{5}{2\sqrt{x}} \).
02

Evaluate g'(x) at x = 1

Substitute \( x = 1 \) into \( g'(x) \) to find its value at \( x = 1 \).\[ g'(1) = \frac{5}{2\sqrt{1}} = \frac{5}{2} \]
03

Find f'(u)

Use the function \( f(u) = \cot \left(\frac{\pi u}{10}\right) \) and differentiate it with respect to \( u \) using the chain rule.The derivative of \( \cot(u) \) is \( -\csc^2(u) \), so:\[ f'(u) = \frac{d}{du}\left(\cot \left(\frac{\pi u}{10}\right)\right) = -\csc^2 \left(\frac{\pi u}{10}\right) \cdot \frac{\pi}{10} \]Thus, \( f'(u) = -\frac{\pi}{10} \csc^2 \left(\frac{\pi u}{10}\right) \).
04

Substitute u = g(1)

Calculate \( u = g(1) = 5\sqrt{1} = 5 \).Now, substitute \( u = 5 \) into \( f'(u) \).\[ f'(5) = -\frac{\pi}{10} \csc^2 \left(\frac{\pi \cdot 5}{10}\right) = -\frac{\pi}{10} \csc^2\left(\frac{\pi}{2}\right) \]
05

Evaluate csc(Ï€/2)

Since \( \csc(x) = \frac{1}{\sin(x)} \), we have:\( \sin\left(\frac{\pi}{2}\right) = 1 \), thus \( \csc\left(\frac{\pi}{2}\right) = \frac{1}{1} = 1 \).Substitute back:\[ f'(5) = -\frac{\pi}{10} \cdot 1^2 = -\frac{\pi}{10} \]
06

Apply chain rule for (f ∘ g)'(x)

The derivative of the composition \( (f \circ g)'(x) \) is given by:\[ (f \circ g)'(x) = f'(g(x)) \cdot g'(x) \]Substitute \( f'(5) \) and \( g'(1) \) into the formula:\[(f \circ g)'(1) = -\frac{\pi}{10} \times \frac{5}{2} \]
07

Final Calculation

Simplify the expression:\[ (f \circ g)'(1) = -\frac{\pi}{10} \times \frac{5}{2} = -\frac{5\pi}{20} = -\frac{\pi}{4} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is an essential technique in calculus used for finding the derivative of a composite function. A composite function involves one function nested inside another. In simpler terms, if you have two functions, say a function inside another function, you need the chain rule to differentiate them together.
Here's how it works:
  • The chain rule basically states: If you have a function y = f(g(x)), then the derivative of y with respect to x is given by \( \frac{dy}{dx} = f'(g(x)) \cdot g'(x) \).
  • You differentiate the outer function, \( f \), with respect to the inner function, \( g(x) \), and then multiply that by the derivative of the inner function, \( g(x) \).
In our exercise, we need to differentiate the combined function \( (f \circ g)(x) = f(g(x)) \). We found \( g'(x) \) first and then \( f'(u) \), substituting the variable accordingly. Through steps like these, we transform complex differentiation problems into manageable tasks.
Trigonometric Derivatives
Trigonometric derivatives are basic derivatives involving trigonometric functions like sine, cosine, tangent, and others. When finding derivatives of trigonometric functions, we often apply standard formulas.
In this exercise, we're working with the function \( f(u) = \cot \left(\frac{\pi u}{10}\right) \). For differentiating \( \cot(x) \), remember:
  • The derivative of \( \cot(x) \) is \( -\csc^2(x) \).
Applying the chain rule, we found the derivative of \( f(u) \) by multiplying \( -\csc^2 \left(\frac{\pi u}{10}\right) \) by \( \frac{\pi}{10} \), the derivative of the inner function \( \frac{\pi u}{10} \).
Using trigonometric identities, like transforming \( \csc(x) = \frac{1}{\sin(x)} \), helped us simplify \( f'(u) \) for the composite derivative calculation.
Mathematical Problem Solving
Mathematical problem solving is about approaching a problem methodically by understanding the requirements and systematically applying mathematical concepts. It's not just about finding the result but thoroughly understanding the "why" and "how."
  • Begin by dissecting the problem into manageable parts. Identify the functions involved and understand their roles.
  • Apply relevant mathematical rules, like the chain rule or trigonometric identities, appropriately according to the steps you've planned.
  • Substitute known values to simplify your calculations, as was done here by substituting \( x = 1 \) and simplifying the trigonometric expressions.
  • Continue through the logical steps, verifying each calculation, and finally arrive at a clear and precise result, as seen in simplifying the final expression \( -\frac{\pi}{4} \).
Problem solving in calculus enhances critical thinking, enabling you to tackle complex scenarios by breaking them into simpler, solvable parts.

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