/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 For Exercises 55 and 56 evaluate... [FREE SOLUTION] | 91Ó°ÊÓ

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For Exercises 55 and 56 evaluate each limit by first converting each to a derivative at a particular x-value. $$\lim _{x \rightarrow 1} \frac{x^{50}-1}{x-1}$$

Short Answer

Expert verified
The limit is 50.

Step by step solution

01

Identify the function in the expression

The given limit is \( \lim _{x \rightarrow 1} \frac{x^{50}-1}{x-1} \). This expression is a standard candidate for conversion to a derivative due to the form \( \frac{f(x) - f(a)}{x-a} \), where \( f(x) = x^{50} \) and \( a = 1 \).
02

Express as a Derivative

Recognize that \( \lim_{x \to a} \frac{f(x) - f(a)}{x - a} \) is the definition of the derivative \( f'(a) \). Therefore, we re-write the given limit using the definition of derivative: find \( f'(1) \), where \( f(x) = x^{50} \).
03

Find the Derivative of the Function

Differentiate \( f(x) = x^{50} \) with respect to \( x \). Using the power rule, \( f'(x) = 50x^{49} \).
04

Evaluate the Derivative at the Specific x-value

Substitute \( x = 1 \) into the derivative \( f'(x) = 50x^{49} \): \( f'(1) = 50(1)^{49} = 50 \).
05

Conclude the Limit Evaluation

Since \( f'(1) = 50 \), the original limit \( \lim _{x \rightarrow 1} \frac{x^{50}-1}{x-1} \) equals 50.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative Calculation
Calculating derivatives is a key skill in calculus that helps us find the rate at which a function changes at any point. In essence, a derivative gives us the slope of the tangent line at any point on a curve. This concept is not only theoretical but also very practical in various fields like physics, engineering, and economics. Derivatives help us understand a function's behavior precisely.

To calculate a derivative, we often express a function in the form \(f(x)\) and use specific rules like the power rule, chain rule, and product rule.
  • The derivative notation can vary: for example, if the function is \(f(x)\), its derivative is often written as \(f'(x)\) or \(\frac{df}{dx}\).
  • Finding the derivative involves taking the limit of the difference quotient as the difference approaches zero. This is the foundational concept of calculus introduced by Newton and Leibniz.
By setting up a limit expression, such as \(\lim_{x \to a} \frac{f(x) - f(a)}{x - a}\), we essentially find a derivative if the limit is defined. This process is crucial in evaluating limits that have an indeterminate form like \(\frac{0}{0}\), which often occurs in calculus problems.
Power Rule in Calculus
The power rule is one of the simplest yet most powerful tools for finding the derivative of functions involving powers of \(x\). It makes the process of differentiation straightforward, especially for polynomial functions.

The power rule states that for a function of the form \(f(x) = x^n\), the derivative is \(f'(x) = nx^{n-1}\). This means:
  • You multiply the entire term by the power \(n\), and
  • You then reduce the power by one.
This rule significantly simplifies differentiation, allowing us to quickly find the rate of change of polynomial functions.

In the step-by-step solution above, using the power rule for \(f(x) = x^{50}\), we calculated its derivative as \(f'(x) = 50x^{49}\). This shows the efficiency and ease of using calculus rules to process even large exponents swiftly.
Evaluating Limits
Evaluating limits is a powerful technique in calculus to find the behavior of a function as it approaches a certain point. Limits help us to understand functions at critical points where direct substitution into the function is not possible due to undefined or indeterminate forms.

In practice, evaluating limits often involves:
  • Converting a problem into a form that facilitates finding the derivative.
  • Recognizing common patterns, such as fractions with a form \(\frac{f(x) - f(a)}{x - a}\), which indicate the presence of derivatives.
  • Using various rules and derivatives to avoid complications like division by zero.
The exercise you saw demonstrates the elegance of calculus where evaluating a limit boils down to calculating a derivative. By converting the limit expression into derivative form, we found the exact value by simply evaluating the derivative at the given point. Calculating limits through derivatives is an example of how calculus seamlessly connects algebraic expressions and geometric interpretations.

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