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In Exercises \(41-58,\) find \(d y / d t\) $$y=\left(1+\tan ^{4}\left(\frac{t}{12}\right)\right)^{3}$$

Short Answer

Expert verified
The derivative is \(\frac{dy}{dt} = \frac{1}{3} \big(1 + \tan^4\left(\frac{t}{12}\right)\big)^2 \cdot \tan^3\left(\frac{t}{12}\right) \cdot \sec^2\left(\frac{t}{12}\right)\).

Step by step solution

01

Identify the Expression

The given function is a composite function: \(y = ig(1 + \tan^4\left(\frac{t}{12}\right)\big)^3\). We need to find \(\frac{dy}{dt}\).
02

Apply the Chain Rule

The outer function here is \(u^3\) where \(u = 1 + \tan^4\left(\frac{t}{12}\right)\). According to the chain rule, the derivative of \(y\) with respect to \(t\), denoted by \(\frac{dy}{dt}\), can be found using \(\frac{dy}{dt} = 3u^2 \cdot \frac{du}{dt}\).
03

Differentiate the Inner Function

Now, we focus on differentiating the inner function \(u = 1 + \tan^4\left(\frac{t}{12}\right)\). The derivative \(\frac{du}{dt}\) involves two steps: first, differentiating \(\tan^4(x)\) and then the argument of the tangent function itself, where \(x = \frac{t}{12}\).
04

Differentiate \(\tan^4(x)\)

\(\tan^4(x)\) can be differentiated using the chain rule: \(\frac{d}{dx}\tan^4(x) = 4\tan^3(x) \cdot \sec^2(x)\).
05

Differentiate the Argument \(x\)

Since \(x = \frac{t}{12}\), its derivative is \(\frac{dx}{dt} = \frac{1}{12}\). Consequently, the derivative of \(\tan^4\left(\frac{t}{12}\right)\) with respect to \(t\) is \(4 \cdot \tan^3\left(\frac{t}{12}\right) \cdot \sec^2\left(\frac{t}{12}\right) \cdot \frac{1}{12}\).
06

Assemble the Derivative

Combine the derivatives calculated in previous steps. We already have \(\frac{dy}{dt} = 3\big(1 + \tan^4\left(\frac{t}{12}\right)\big)^2 \cdot \left(4 \cdot \tan^3\left(\frac{t}{12}\right) \cdot \sec^2\left(\frac{t}{12}\right) \cdot \frac{1}{12}\right)\). Simplifying this gives \(\frac{dy}{dt} = \frac{1}{3} \big(1 + \tan^4\left(\frac{t}{12}\right)\big)^2 \cdot \tan^3\left(\frac{t}{12}\right) \cdot \sec^2\left(\frac{t}{12}\right)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a fundamental concept in calculus used for finding the derivative of composite functions. A composite function is essentially a function nested inside another function, like peeling an onion layer by layer. The rule states that to differentiate such a function, you first find the derivative of the outer function and multiply it by the derivative of the inner function. This step-by-step approach allows us to break complex problems down into simpler parts.

To apply the chain rule, identify the layers of the function. In our example, the outer function is \(u^3\), where \(u = 1 + \tan^4\left( \frac{t}{12} \right)\). After differentiating the outer layer, multiply it by the derivative of the inner function, \(u\), which involves using the chain rule again for the nested trigonometric function. By mastering the chain rule, you're able to handle any level of function complexity with ease.
Trigonometric Functions
Trigonometric functions are central to calculus and many fields such as engineering and physics. In our exercise, the function \(\tan(x)\) is used. When dealing with derivatives of trigonometric functions, it is important to remember the specific derivative rules:
  • The derivative of \(\tan(x)\) is \(\sec^2(x)\), a fact we rely on heavily.
  • We also utilize the power rule in conjunction with trigonometric rules, such as differentiating \(\tan^4(x)\) by treating it as \(\big(\tan(x)\big)^4\).
In our solution, we first differentiate \(\tan^4(x)\) using these rules, resulting in \(4\tan^3(x) \cdot \sec^2(x)\). This showcases the combination of trigonometric differentiation and other calculus rules to solve problems efficiently. Understanding these foundational derivatives assists in tackling more advanced trigonometric-related calculus problems.
Composite Function Differentiation
Differentiating composite functions involves multiple layers of differentiation, often requiring the use of different differentiation techniques together. Composite function differentiation is one of the key applications of the chain rule, allowing us to break down a complex, nested structure into manageable parts.

The given function \(y = \big(1 + \tan^4\left(\frac{t}{12}\right)\big)^3\) is a perfect example. Here, the outermost function to differentiate is \(\big(...\big)^3\), and inside this is the trigonometric function \(\tan\), operating on the argument \(\frac{t}{12}\). This layered structure means applying the chain rule iteratively:
  • First, differentiate the outermost layer (the cube), resulting in \(3u^2\).
  • Then, differentiate the next layer for \(u = 1 + \tan^4\left(\frac{t}{12}\right)\).
  • For \(\tan^4(x)\), another application of the chain rule is needed.
By systematically applying these steps, any composite function’s derivative can be unraveled and understood, providing a robust framework for more complex calculus challenges.

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Most popular questions from this chapter

If \(L=\sqrt{x^{2}+y^{2}}, d x / d t=-1,\) and \(d y / d t=3,\) find \(d L / d t\) when \(x=5\) and \(y=12 .\)

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Volume The radius \(r\) and height \(h\) of a right circular cone are related to the cone's volume \(V\) by the equation \(V=(1 / 3) \pi r^{2} h .\) a. How is \(d V / d t\) related to \(d h / d t\) if \(r\) is constant? b. How is \(d V / d t\) related to \(d r / d t\) if \(h\) is constant? c. How is \(d V / d t\) related to \(d r / d t\) and \(d h / d t\) if neither \(r\) nor \(h\) is constant?

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