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Find $$y^{(4)}=d^{4} y / d x^{4}$$ if $$ \text { a. }y=-2 \sin x . \quad \text { b. } y=9 \cos x $$

Short Answer

Expert verified
a. \( y^{(4)} = -2 \sin x \); b. \( y^{(4)} = 9 \cos x \).

Step by step solution

01

Differentiate the First Function (y = -2 sin x)

Start by finding the first derivative of the function \( y = -2 \sin x \). Differentiate to get:\[ y' = \frac{d}{dx}(-2 \sin x) = -2 \cos x \]
02

Second Derivative of First Function

Find the second derivative by differentiating the first derivative:\[ y'' = \frac{d}{dx}(-2 \cos x) = 2 \sin x \]
03

Third Derivative of First Function

Differentiate the second derivative to find the third derivative:\[ y''' = \frac{d}{dx}(2 \sin x) = 2 \cos x \]
04

Fourth Derivative of First Function

Differentiate the third derivative to find the fourth derivative:\[ y^{(4)} = \frac{d}{dx}(2 \cos x) = -2 \sin x \]
05

Differentiate the Second Function (y = 9 cos x)

Find the first derivative of the function \( y = 9 \cos x \). Differentiate to get:\[ y' = \frac{d}{dx}(9 \cos x) = -9 \sin x \]
06

Second Derivative of Second Function

Find the second derivative by differentiating the first derivative:\[ y'' = \frac{d}{dx}(-9 \sin x) = -9 \cos x \]
07

Third Derivative of Second Function

Differentiate the second derivative to find the third derivative:\[ y''' = \frac{d}{dx}(-9 \cos x) = 9 \sin x \]
08

Fourth Derivative of Second Function

Differentiate the third derivative to find the fourth derivative:\[ y^{(4)} = \frac{d}{dx}(9 \sin x) = 9 \cos x \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Trigonometric Functions in Calculus
Trigonometric functions like sine and cosine play a crucial role in calculus, especially when dealing with differentiation. In essence, these are functions based on angles, often used to describe periodic phenomena such as waves. In calculus, their derivatives follow specific patterns that you'll frequently encounter.
  • The derivative of \(\sin x\) is \(\cos x\).
  • The derivative of \(\cos x\) is \(-\sin x\).
  • When close to cycles, \(\sin x\) and \(\cos x\) repeat after a period of \(2\pi\), meaning their derivatives also exhibit periodicity.
Grasping these fundamentals helps you tackle more complex problems, such as finding higher order derivatives or solving equations involving these functions. Differentiating trigonometric functions often involves recognizing and applying these patterns repeatedly.
Basics of Calculus Differentiation
Differentiation in calculus is a process that determines the rate at which a function is changing at any given point. This concept is incredibly important whether you are studying math, physics, engineering, or economics, as it helps in understanding how quantities vary over time or space.
The fundamental idea is to find the derivative, which is a new function describing the slope of the original function at every point. In practical terms, differentiation uses rules such as the power rule, product rule, and chain rule to find derivatives of various functions.
  • The power rule is used for functions involving power of x.
  • The product rule is applied when you have a product of two functions.
  • The chain rule helps in differentiating composite functions.
In our exercise, simple derivatives of trig functions follow straightforward rules but exemplify the broader principle of calculus differentiation.
Exploring the Fourth Derivative of Functions
Finding the fourth derivative, denoted as \( y^{(4)} \), involves taking the derivative of a function four times. This is often needed in problems involving motion, where higher derivatives give information about acceleration, jerk, and beyond.
For trigonometric functions, like \( y = -2 \sin x \) and \( y = 9 \cos x \), you often observe cyclical patterns. These functions revert to forms close to their initial ones after every four differentiations. Let's see what happens via the exercise's findings:
  • For \( y = -2 \sin x \), the cycle of derivatives is: \(-2 \cos x, 2 \sin x, 2 \cos x, -2 \sin x\). So, \( y^{(4)} = -2 \sin x \), the original function.
  • For \( y = 9 \cos x \), derivatives cycle through: \(-9 \sin x, -9 \cos x, 9 \sin x, 9 \cos x\), returning to the starting form: \( y^{(4)} = 9 \cos x \).
These cyclical properties of derivatives in trigonometric functions are powerful tools. They simplify computations in real-world applications and reinforce the beauty of mathematics in capturing natural patterns.

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