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Find the derivatives of the functions in Exercises \(19-40\) $$r=6(\sec \theta-\tan \theta)^{3 / 2}$$

Short Answer

Expert verified
\( \frac{dr}{d\theta} = 9(\sec \theta - \tan \theta)^{1/2} (\sec \theta \tan \theta - \sec^2 \theta) \).

Step by step solution

01

Understand the Function

We have the function \( r = 6(\sec \theta - \tan \theta)^{3/2} \). Our task is to find its derivative with respect to \( \theta \). This means we need \( \frac{dr}{d\theta} \).
02

Apply the Chain Rule

Using the chain rule, we need to differentiate \( r = 6(u)^{3/2} \), where \( u = \sec \theta - \tan \theta \). The derivative of \( r \) with respect to \( u \) is \( \frac{d}{du}[6u^{3/2}] = 9u^{1/2} \).
03

Differentiate the Inner Function

Find the derivative of \( u = \sec \theta - \tan \theta \). The derivative is \( \frac{du}{d\theta} = \sec \theta \tan \theta - \sec^2 \theta \).
04

Combine Using the Chain Rule

Now apply the chain rule: \[ \frac{dr}{d\theta} = \frac{dr}{du} \cdot \frac{du}{d\theta} = 9(\sec \theta - \tan \theta)^{1/2} \cdot (\sec \theta \tan \theta - \sec^2 \theta) \].
05

Simplify the Expression

Substitute back the expression for \( u \) and simplify accordingly if necessary. The final expression for \( \frac{dr}{d\theta} \) is the product of the results from steps 2 and 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The Chain Rule is a critical tool in calculus for differentiating composite functions. A composite function is one where you have a function inside another function, like our example with a function of the form \( r = 6(u)^{3/2} \). To find the derivative, the Chain Rule helps us by allowing differentiation in steps.
First, we differentiate the outer function: if \( r = 6u^{3/2} \), we find the derivative with respect to \( u \) as \( \frac{d}{du}[6u^{3/2}] = 9u^{1/2} \).
Next, we differentiate the inner function \( u = \sec \theta - \tan \theta \) with respect to \( \theta \). This step-by-step approach simplifies the process of finding derivatives of more complicated functions.
In our example, after finding these individual derivatives, we multiply them to find the derivative of the composite function with respect to \( \theta \). This two-step differentiation is what the Chain Rule helps to manage efficiently.
Trigonometric Functions
Trigonometric functions are fundamental in calculus, especially when dealing with differentiation. In the problem, we encounter \( \sec \theta \) and \( \tan \theta \), which are lesser-known compared to sine and cosine but equally crucial.
Here's a quick rundown on them:
  • \( \sec \theta = \frac{1}{\cos \theta} \)
  • \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
These definitions are key in knowing how these functions behave and change.
For differentiation:
  • The derivative of \( \sec \theta \) is \( \sec \theta \tan \theta \)
  • The derivative of \( \tan \theta \) is \( \sec^2 \theta \)
When you put these formulas together, you can successfully differentiate the composite trigonometric function we had, \( \sec \theta - \tan \theta \), in the exercise.
Derivative of Composite Functions
Finding the derivative of composite functions involves combining the derivative of the outer function with the derivative of the inner function.
In our example, we first saw \( r = 6(\sec \theta - \tan \theta)^{3/2} \), which required us to handle dependencies in the functions inside the parentheses.
We performed the following:
  • Differentiate the outside: \( \frac{d}{du}[6u^{3/2}] = 9u^{1/2} \), where \( u = \sec \theta - \tan \theta \)
  • Differentiate the inside: \( \frac{du}{d\theta} = \sec \theta \tan \theta - \sec^2 \theta \)
Finally, we applied the Chain Rule to combine these:
\[ \frac{dr}{d\theta} = 9(\sec \theta - \tan \theta)^{1/2} \cdot (\sec \theta \tan \theta - \sec^2 \theta) \]
This is a powerful method for dealing with complex functions because it systematically breaks down the function into manageable parts before taking the derivative.

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