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Heating a plate When a circular plate of metal is heated in an oven, its radius increases at the rate of 0.01 \(\mathrm{cm} / \mathrm{min.}\) . At what rate is the plate's area increasing when the radius is 50 \(\mathrm{cm} ?\).

Short Answer

Expert verified
The rate of change of the area is approximately \( \pi \text{ cm}^2/\text{min} \).

Step by step solution

01

Identify the Given Information

We know that the rate of change of the radius is given by \( \frac{dr}{dt} = 0.01 \) \(\text{cm/min}\) and the radius of the plate at the given instance is \( r = 50 \text{ cm} \). We need to find \( \frac{dA}{dt} \), the rate at which the area of the plate is increasing.
02

Recall the Formula for the Area of a Circle

The area \( A \) of a circle with radius \( r \) is given by the formula \( A = \pi r^2 \).
03

Differentiate the Area with Respect to Time

To find how the area changes with time, differentiate \( A = \pi r^2 \) with respect to \( t \). Using the chain rule, we get \( \frac{dA}{dt} = \frac{d}{dt}(\pi r^2) = 2\pi r \frac{dr}{dt} \).
04

Substitute the Known Values into the Derivative

Substitute \( r = 50 \text{ cm} \) and \( \frac{dr}{dt} = 0.01 \text{ cm/min} \) into the differentiated expression: \( \frac{dA}{dt} = 2\pi(50)(0.01) \).
05

Calculate the Rate of Change of the Area

Perform the multiplication: \( \frac{dA}{dt} = 2\pi(50)(0.01) = \pi \text{ cm}^2/\text{min}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a fundamental concept in calculus that helps us find the rate at which one quantity changes with respect to another. In the context of this problem, we are looking at how the area of a circular plate changes as the radius changes over time.

When we differentiate a function, we are essentially finding its derivative. The derivative gives us the instantaneous rate of change and is symbolically represented as \(\frac{dy}{dx}\), where \(y\) is the function dependent on \(x\).

In our example, the function to consider is the area \(A\) in terms of the radius \(r\). We want to determine \(\frac{dA}{dt}\), meaning how the area \(A\) changes as time \(t\) progresses. This rate is crucial in problems where dimensions of shapes are expanding due to some external factor, like heating.
Area of a Circle
The area of a circle is a classic geometric formula, easily expressed as \(A = \pi r^2\). Here, \(A\) represents the area, and \(r\) is the radius of the circle.

This formula shows a direct relationship between the area and the square of the radius, meaning that if the radius increases, the area increases exponentially. In the case of our exercise, since the radius of the plate is changing over time, we are interested in how this change in the radius affects the area.

Understanding this relationship sets the foundation for further calculations in related rates problems. As the radius expands due to heating, it's essential to compute the updated area to determine the impact of the change.
Chain Rule
The chain rule is a powerful tool in calculus used to differentiate composite functions. It allows us to find the derivative of a function that is based on another function. In our scenario, the area of a circle, \(A = \pi r^2\), depends on the radius \(r\), which in turn is changing with respect to time \(t\).

The chain rule formula is expressed as \(\frac{dy}{dt} = \frac{dy}{dx} \cdot \frac{dx}{dt}\). In this context, \(\frac{dA}{dt} = 2\pi r \cdot \frac{dr}{dt}\) results from the derivative of the area with respect to the radius multiplied by the derivative of the radius with respect to time. This gives us a path to find \(\frac{dA}{dt}\), or how fast the area is changing, based on known rates like \(\frac{dr}{dt}\).

Remember, the chain rule is crucial anytime you have nested functions or situations where one variable affects another, and such linkage is common in problems involving related rates.

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