Chapter 2: Problem 60
Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form $$\lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}$$ occur frequently in calculus. In Exercises \(57-62,\) evaluate this limit for the given value of \(x\) and function \(f\) . $$f(x)=1 / x, \quad x=-2$$
Short Answer
Step by step solution
Identify the variables and function
Calculate \( f(x+h) \) and \( f(x) \)
Substitute into the limit expression
Simplify the numerator
Simplify the entire expression
Evaluate the limit as \( h \rightarrow 0 \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits
In the given exercise, the limit we examined is \( \lim_{h \rightarrow 0 } \frac{f(x+h)-f(x)}{h} \). This expression is common because it forms the foundation of the derivative, representing the slope of the tangent line at a point.
To understand this better, imagine trying to find how steep a hill is at a particular spot. The limit helps us figure out the exact steepness by honing in on that spot as closely as possible without actually standing on it.
Differentiation
The derivative, symbolized as \( f'(x) \), at a point is the primary tool differentiation provides. It's essentially the limit described earlier. In the exercise, finding the derivative at \( x = -2 \) involved evaluating \( \lim_{h o 0} \frac{f(x+h) - f(x)}{h} \), which helps us understand the immediate rate of change of the function \( f(x) = \frac{1}{x} \).
This derivation shows how finding derivatives with differentiation is almost like unwrapping a gift; it reveals the function's behavior at a more precise level. Differentiation allows us to see beyond the graph's curves and into the specifics of its progression. With this exercise, we saw that the derivative at \( x = -2 \) is \( \frac{1}{4} \), reflecting the curve's direction and steepness.
Secant Lines
In the context of our problem, the expression \( \frac{f(x+h) - f(x)}{h} \) originally represents the slope of the secant line connecting the points \((x, f(x))\) and \((x+h, f(x+h))\).
As \( h \rightarrow 0 \), this secant line's slope approaches the slope of the tangent line, representing the derivative. The derivative is effectively the limit of secant line slopes as the two points merge into one.
Visualize a secant line as a rope pulled taut across two pegs on a curve. As you move the pegs closer together, the rope's angle tells you how the curve is bending at that spot. This tangible representation aids in understanding how important secant lines are in approaching the concept of instantaneous speed and rate of change.