Chapter 2: Problem 57
Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form $$\lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}$$ occur frequently in calculus. In Exercises \(57-62,\) evaluate this limit for the given value of \(x\) and function \(f\) . $$f(x)=x^{2}, \quad x=1$$
Short Answer
Step by step solution
Identifying the Function and Derivative Definition
Substitute into the Derivative Definition
Expand the Numerator
Simplify the Expression
Cancel the Common Factor
Evaluate the Limit
Substitute the Value of x
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits
- \( \lim_{h \rightarrow 0} \frac{f(x+h) - f(x)}{h} \)
When a function approaches a certain value as the inputs get closer to a specific number, the limit can often determine the function's slope at that exact point. In our exercise, we worked with a function \( f(x) = x^2 \) and found the limit as \( h \) approaches 0 to get the derivative at a particular point. This illustrates the essence of limits in calculus, providing a foundational tool for understanding changes in mathematical functions.
Instantaneous Rate of Change
In the derivative formula,
- \( \frac{f(x+h) - f(x)}{h} \),
For our function \( f(x) = x^2 \), the derivative results in \( 2x \), showing that this quadratic function steepens linearly as \( x \) increases. At \( x = 1 \), the rate of change is 2, indicating the slope of the tangent to the curve at that point. Thus, understanding instantaneous rate not only helps us know how fast or slow a function is changing but also better predicts the function's behavior at precise moments.
Function Evaluation
A key step in understanding derivatives and rates of change is effectively evaluating functions at particular points. Once the function is placed into our derivative formula, evaluating it means carefully substituting numbers to reveal how a function behaves.
- First, we substitute \( x = 1 \) into the expression \( 2x \), find our derivative at this point.
- Thus, \( 2 \times 1 = 2 \) shows the function changes at a rate of 2 when \( x = 1 \).