Chapter 2: Problem 23
At what points are the functions in Exercises 13-30 continuous? $$y=\frac{x \tan x}{x^{2}+1}$$
Short Answer
Expert verified
The function is continuous everywhere except at \( x = \frac{(2k+1)\pi}{2} \), where \( k \) is an integer.
Step by step solution
01
Definition of Continuity
A function is continuous at a point if it is defined at that point, and its limit as it approaches that point equals its value at that point. That is, for a function \( f(x) \) to be continuous at \( x = a \), the following must hold: \( \lim_{x \to a} f(x) = f(a) \).
02
Function Analysis
Given the function \( y = \frac{x \tan x}{x^2 + 1} \), this function is a rational function, which means it is generally continuous except where the denominator is zero. However, in this case, the denominator \( x^2 + 1 \) is never zero for real numbers. Thus, potential points of discontinuity must come from the \( \tan x \) function.
03
Trigonometric Function Considerations
The tangent function \( \tan x \) is discontinuous at points where it is undefined. Specifically, \( \tan x \) is not defined at \( x = \frac{(2k+1)\pi}{2} \), where \( k \) is any integer, because the tangent becomes infinite (vertical asymptotes occur).
04
Conclusion of Continuity
The given function \( y = \frac{x \tan x}{x^2 + 1} \) is continuous everywhere except at points where \( \tan x \) is undefined. Therefore, \( y \) is continuous for all \( x \) except at \( x = \frac{(2k+1)\pi}{2} \), where \( k \) is any integer.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trigonometric Functions
Trigonometric functions are a core part of mathematics, especially important in analyzing periodic phenomena. One such function is the tangent function, denoted as \( \tan x \). It is derived from sine and cosine functions with the relation \( \tan x = \frac{\sin x}{\cos x} \). Because of this ratio, the tangent function exhibits unique behavior:
- It is periodic with a period of \( \pi \).
- It has vertical asymptotes where the cosine function equals zero, as dividing by zero is undefined.
Rational Functions
Rational functions are defined as the quotient of two polynomials. In general, a rational function \( f(x) = \frac{p(x)}{q(x)} \) is continuous everywhere except where the denominator \( q(x) \) equals zero. At these points, the function becomes undefined.In the exercise example, the rational component is \( \frac{x \tan x}{x^2 + 1} \). Here:
- The numerator is \( x \tan x \), a product of linear and trigonometric expressions.
- The denominator is \( x^2 + 1 \), which is polynomial.
- The denominator does not become zero for any real number \( x \), indicating it is continuous as \( x^2 + 1 > 0 \) for all real \( x \).
Points of Discontinuity
Points of discontinuity in a function are values of \( x \) where the function is not continuous. For rational functions containing trigonometric components like \( \frac{x \tan x}{x^2 + 1} \), these discontinuities often arise from the trigonometric part.As mentioned, the points where \( \tan x \) is undefined determine the discontinuities in this function. These occur at:
- \( x = \frac{(2k+1)\pi}{2} \) for any integer \( k \). This results in vertical asymptotes.