Chapter 2: Problem 18
Find the limits in Exercises \(11-18\) $$a. \lim _{x \rightarrow 1^{+}} \frac{\sqrt{2 x}(x-1)}{|x-1|} \quad b. \lim _{x \rightarrow 1} \frac{\sqrt{2 x}(x-1)}{|x-1|}$$
Short Answer
Expert verified
a) \( \sqrt{2} \); b) Does not exist.
Step by step solution
01
Analyze the expression for limit (a)
For the limit \( \lim_{x \rightarrow 1^{+}} \frac{\sqrt{2x}(x-1)}{|x-1|} \), realize that as \( x \) approaches 1 from the right, \( x-1 \) is positive. Therefore, \(|x-1| = x-1\). This simplifies the expression to \( \frac{\sqrt{2x}(x-1)}{x-1} \).
02
Simplify the expression for limit (a)
By simplifying \( \frac{\sqrt{2x}(x-1)}{x-1} = \sqrt{2x} \) because \( (x-1) \) in the numerator and denominator cancels out. As \( x \rightarrow 1^{+} \), \( \sqrt{2x} \rightarrow \sqrt{2} \cdot 1 = \sqrt{2} \).
03
Compute the limit (a)
The limit \( \lim_{x \rightarrow 1^{+}} \sqrt{2x} \) simplifies as \( x \rightarrow 1 \). Thus, the limit is \( \sqrt{2} \).
04
Analyze the expression for limit (b)
For \( \lim_{x \rightarrow 1} \frac{\sqrt{2x}(x-1)}{|x-1|} \), consider both the right and left limits since it involves an approaching point. When \( x \rightarrow 1^{+} \), we already know the simplification from previous steps is \( \sqrt{2} \).
05
Consider left-hand limit for (b)
For \( x \rightarrow 1^{-} \), \( x-1 \) is negative, thus \(|x-1| = -(x-1)\). Substituting this gives \( \frac{\sqrt{2x}(x-1)}{-(x-1)} = -\sqrt{2x} \).
06
Evaluate the left-hand limit for (b)
As \( x \rightarrow 1^{-} \), \( -\sqrt{2x} \rightarrow -\sqrt{2} \cdot 1 = -\sqrt{2} \).
07
Compute the bidirectional limit (b)
The right-hand and left-hand limits are \( \sqrt{2} \) and \( -\sqrt{2} \) respectively. These are not equal, indicating that \( \lim_{x \rightarrow 1} \frac{\sqrt{2x}(x-1)}{|x-1|} \) does not exist.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
One-sided limits
One-sided limits are a useful concept when exploring how a function behaves as it approaches a particular point from one direction. In the provided exercise, we examine the limit as \( x \rightarrow 1^{+} \) and \( x \rightarrow 1^{-} \).
* At \( x \rightarrow 1^{+} \), \( |x-1| = x-1 \) because values are positive, simplifying \( \frac{\sqrt{2x}(x-1)}{|x-1|} \) to \( \sqrt{2x} \).* At \( x \rightarrow 1^{-} \), \( |x-1| = -(x-1) \), making it different from the right direction and yielding \( -\sqrt{2x} \).
Understanding how limits change directionally helps in characterizing function continuity and analyzing points where limits might not exist.
- \( x \rightarrow 1^{+} \) means that \( x \) is approaching 1 from the right side, using very slightly larger values than 1.
- \( x \rightarrow 1^{-} \) indicates \( x \) is approaching 1 from the left, with very slightly smaller values than 1.
* At \( x \rightarrow 1^{+} \), \( |x-1| = x-1 \) because values are positive, simplifying \( \frac{\sqrt{2x}(x-1)}{|x-1|} \) to \( \sqrt{2x} \).* At \( x \rightarrow 1^{-} \), \( |x-1| = -(x-1) \), making it different from the right direction and yielding \( -\sqrt{2x} \).
Understanding how limits change directionally helps in characterizing function continuity and analyzing points where limits might not exist.
Limit expression analysis
Analyzing a limit involves breaking down the expression to determine its behavior as \( x \) approaches a specific value. For the exercise, the original expression is \( \frac{\sqrt{2x}(x-1)}{|x-1|} \).
Initially, it might appear complex, but here are the steps to analyze it simpler:
Initially, it might appear complex, but here are the steps to analyze it simpler:
- Identify the form of \( |x-1| \): realize the absolute value expression changes depending on whether \( x \) approaches from the right or left.
- Simplify when possible: once \( |x-1| \) is expressed correctly for a direction, cancel like terms.
- Determine the resultant expression behavior as \( x \) precisely approaches the given point, making it straightforward like \( \sqrt{2x} \) or \( -\sqrt{2x} \).
Indeterminate forms
Indeterminate forms often occur when evaluating limits and can be a sign that the limit is not straightforward. Common forms include \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \), where the result is not immediately clear.
In this exercise, the issue arises when trying to evaluate \( \lim_{x \rightarrow 1} \frac{\sqrt{2x}(x-1)}{|x-1|} \). As \( x \rightarrow 1 \), both the numerator and denominator tend towards zero:
In this exercise, the issue arises when trying to evaluate \( \lim_{x \rightarrow 1} \frac{\sqrt{2x}(x-1)}{|x-1|} \). As \( x \rightarrow 1 \), both the numerator and denominator tend towards zero:
- The numerator \( \sqrt{2x}(x-1) \) becomes 0 because \( x-1 \rightarrow 0 \).
- The denominator \( |x-1| \) also tends towards 0, depending on the direction \( x \) approaches 1.