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Find a parametrization of the surface. (There are many correct ways to do these, so your answers may not be the same as those in the back of the book.) Parabolic cylinder between planes The surface cut from the parabolic cylinder \(z=4-y^{2}\) by the planes \(x=0, x=2,\) and \(z=0\)

Short Answer

Expert verified
The parametrization is \(\vec{r}(u, v) = (u, v, 4 - v^2)\), with \(0 \leq u \leq 2\) and \(-2 \leq v \leq 2\).

Step by step solution

01

Identify the surface and its constraints

We are asked to find a parametrization of the given surface. The surface described is a section of a parabolic cylinder defined by the equation \(z = 4 - y^2\). It is bounded by the planes \(x = 0\), \(x = 2\), and \(z = 0\).
02

Determine variable ranges

Given the constraints, the variable \(x\) ranges from \(0\) to \(2\). The variable \(z\) is non-negative and satisfies \(0 \leq z \leq 4 - y^2\). For \(z = 0\), we get \(y^2 = 4\), hence \(y\) ranges from \(-2\) to \(2\).
03

Set up the parametrization

Since the bounds for \(x\) are up to \(2\), and the parabolic shape \(z = 4 - y^2\) gives restrictions for \(y\) and \(z\), we can set up the parametrization by choosing parameters: - Let \(x = u\), where \(0 \leq u \leq 2\), - Let \(y = v\), where \(-2 \leq v \leq 2\), - Then \(z = 4 - v^2\).
04

Write the parametrization

The parametrization of the surface based on the ranges determined is:\[ \vec{r}(u, v) = \begin{pmatrix} u \ v \ 4 - v^2 \end{pmatrix} \]where \(0 \leq u \leq 2\), and \(-2 \leq v \leq 2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parabolic Cylinder
A parabolic cylinder is a surface generated by sliding a parabola along a line. In this case, the line is parallel to one of the coordinate axes, not rotating or changing shape. The defining equation of a parabolic cylinder is typically of the form \(z = ax^2\) or \(z = ay^2\). Here, we see it as \(z = 4 - y^2\).
This type of surface gets its name because each cross-section parallel to the cylinder axis looks like a parabola. For our equation \(z = 4 - y^2\), every slice perpendicular to the \(x\)-axis and horizontal to the \(y-z\) plane displays a parabolic shape.
The '4' in the equation pushes the entire parabola up by four units along the \(z\)-axis, and the \(-y^2\) means it opens downward. This orientation plays an important role when we consider boundary conditions or constraints.
Boundary Planes
Boundary planes are flat surfaces that limit or confine a solid object or surface in certain directions. In this case, we have three boundary planes: two vertical planes and one horizontal plane.
  • The plane \(x = 0\) marks the starting edge on the \(x\)-axis.
  • The plane \(x = 2\) signifies the end edge on the \(x\)-axis. Together, these planes create a vertical restriction, confining the surface within these two limits.
  • The plane \(z = 0\) lays horizontally, marking the lowest point of the surface, ensuring that the surface doesn’t dip below the \(xy\)-plane. It's crucial for keeping \(z\) non-negative.
Understanding these boundary planes helps visualize where the parabolic cylinder is sliced and how it is constrained in space.
3D Parametric Equations
Parametrization is a technique to describe surfaces or curves in terms of parameters. By using parameterized equations, we can control the points on a surface with simple variables. For a 3D surface, these equations take the form \(\vec{r}(u,v) = (x(u,v), y(u,v), z(u,v))\).
In our specific problem, we've selected:
  • \(x = u\) as a linear parameter controlling the horizontal limit from \(0\) to \(2\).
  • \(y = v\) as managing the vertical span from \(-2\) to \(2\).
  • Lastly, \(z = 4 - v^2\), reflecting the vertical height constraint imposed by the parabolic nature of the cylinder.
The full parametric form of the surface is \(\vec{r}(u, v) = (u, v, 4 - v^2)\).
This approach makes it easier to calculate anything from surface area to further geometry properties of the structure, as each point can be uniquely defined by the parameters \(u\) and \(v\). Parametric representations simplify many computational problems in both theoretical and applied mathematics.

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Most popular questions from this chapter

Let \(C\) be the smooth curve \(\mathbf{r}(t)=(2 \cos t) \mathbf{i}+(2 \sin t) \mathbf{j}+\) \(\left(3-2 \cos ^{3} t\right) \mathbf{k},\) oriented to be traversed counterclockwise around the \(z\) -axis when viewed from above. Let \(S\) be the piecewise smooth cylindrical surface \(x^{2}+y^{2}=4,\) below the curve for \(z \geq 0,\) together with the base disk in the \(x y\) -plane. Note that \(C\) lies on the cylinder \(S\) and above the \(x y\) -plane (see the accompanying figure). Verify Equation \((4)\) in Stokes' Theorem for the vector field \(\mathbf{F}=y \mathbf{i}-x \mathbf{j}+x^{2} \mathbf{k}.\)

a. A torus of revolution (doughnut) is obtained by rotating a circle \(C\) in the \(x z\) -plane about the \(z\) -axis in space. (See the accompanying figure.) If \(C\) has radius \(r>0\) and center \((R, 0,0),\) show that a parametrization of the torus is $$\begin{aligned} \mathbf{r}(u, v)=&((R+r \cos u) \cos v) \mathbf{i} \\\ &+((R+r \cos u) \sin v) \mathbf{j}+(r \sin u) \mathbf{k} \end{aligned}$$ where \(0 \leq u \leq 2 \pi\) and \(0 \leq v \leq 2 \pi\) are the angles in the figure. b. Show that the surface area of the torus is \(A=4 \pi^{2} R r\)

Use a parametrization to express the area of the surface as a double integral. Then evaluate the integral. (There are many correct ways to set up the integrals, so your integrals may not be the same as those in the back of the book. They should have the same values, however.) Circular cylinder band The portion of the cylinder \(x^{2}+z^{2}=\) 10 between the planes \(y=-1\) and \(y=1\)

Hyperboloid of two sheets Find a parametrization of the hyperboloid of two sheets \(\left(z^{2} / c^{2}\right)-\left(x^{2} / a^{2}\right)-\left(y^{2} / b^{2}\right)=1\).

Use a parametrization to express the area of the surface as a double integral. Then evaluate the integral. (There are many correct ways to set up the integrals, so your integrals may not be the same as those in the back of the book. They should have the same values, however.) Tilted plane inside cylinder The portion of the plane \(y+2 z=2\) inside the cylinder \(x^{2}+y^{2}=1\)

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