Chapter 16: Problem 33
a. Exact differential form How are the constants \(a, b,\) and \(c\) related if the following differential form is exact? $$\left(a y^{2}+2 c z x\right) d x+y(b x+c z) d y+\left(a y^{2}+c x^{2}\right) d z$$ b. Gradient field For what values of \(b\) and \(c\) will $$\mathbf{F}=\left(y^{2}+2 c z x\right) \mathbf{i}+y(b x+c z) \mathbf{j}+\left(y^{2}+c x^{2}\right) \mathbf{k}$$ be a gradient field?
Short Answer
Step by step solution
Understanding Exact Differential Forms
Applying the Conditions for Exactness
Conclusion for Exactness
Understanding Gradient Fields
Computing the Curl of \( \mathbf{F} \)
Conclusion for Gradient Field
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gradient Field
To determine if a vector field is a gradient field, the curl of the vector field, represented by \( abla \times \mathbf{F} \), must be zero. This is a key property of gradient fields. When \( abla \times \mathbf{F} = \vec{0} \), it implies that the vector field \( \mathbf{F} \) is irrotational, meaning it has no 'twists' or 'circulations.'
In the exercise, the vector field \( \mathbf{F} \) needs to meet certain conditions on its components to be a gradient field, specifically that \( b = 2a \) and \( c = 2a \). This ensures that each component of the curl is zero, confirming that \( \mathbf{F} \) is a gradient field.
Partial Derivatives
In exact differential forms, partial derivatives help verify exactness. Specifically, for exactness, the partial derivatives must satisfy the conditions:
- \( \frac{\partial M}{\partial y} = \frac{\partial N}{\partial x} \)
- \( \frac{\partial N}{\partial z} = \frac{\partial P}{\partial y} \)
- \( \frac{\partial P}{\partial x} = \frac{\partial M}{\partial z} \)
In the exercise, by using partial derivatives, relations between the constants \( a, b, \) and \( c \) were determined, ensuring the differential form is exact. The conditions led to the relationships \( 2a = b \) and \( c = 2a \), showing how partial derivatives are crucial in confirming exactness.
Vector Calculus
In vector calculus, an exact differential form is an equation that can be integrated perfectly to yield a scalar potential function. For example, to establish the exactness of a differential form, one must ensure certain conditions on the partial derivatives. This is a vital step linking it to the concept of a gradient field.
The vector field \( \mathbf{F} \) in the exercise is analyzed using vector calculus techniques, particularly the computation of the curl. The curl is a vector operation that helps determine if a field is conservative (like a gradient field) or not. When the curl is zero, it indicates the absence of rotation and the potential to be expressed as the gradient of a scalar function.
- Gradient: measures the slope of a scalar field.
- Curl: measures the rotation of a vector field.