Chapter 16: Problem 32
Evaluate the integral $$\oint_{C}-y^{3} d y+x^{3} d x$$ for any closed path \(C\)
Short Answer
Expert verified
The integral evaluates to zero by Green's Theorem.
Step by step solution
01
Recognize the integral as a line integral
The integral is a line integral of the form \( \oint_{C} M \, dx + N \, dy \) where \( M = x^3 \) and \( N = -y^3 \). The path \( C \) is a closed curve.
02
Check if the vector field is conservative
A vector field \( \mathbf{F} = (M, N) = (x^3, -y^3) \) is conservative if \( \frac{\partial N}{\partial x} = \frac{\partial M}{\partial y} \). Here, \( \frac{\partial N}{\partial x} = 0 \) and \( \frac{\partial M}{\partial y} = 0 \), which are equal. Hence, the field is conservative.
03
Apply Green's Theorem
Green's Theorem relates the line integral around a simple closed curve \( C \) to a double integral over the plane region \( D \) bounded by \( C \). It states \( \oint_{C} M \, dx + N \, dy = \iint_{D} \left( \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} \right) \, dA \). We have previously found both partial derivatives to be 0.
04
Evaluate the double integral
Since both partial derivatives from Green's Theorem are zero, the double integral becomes \( \iint_{D} 0 \, dA = 0 \), regardless of the path \( C \).
05
Conclude the result
Therefore, the line integral around any closed path \( C \) is zero.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Green's Theorem
Green's Theorem provides a powerful connection between a line integral around a closed path and a double integral over the region it encloses. This theorem states that, for a continuously differentiable vector field \( \mathbf{F} = (M, N) \), the line integral around a simple closed curve \( C \) is equal to the double integral of the difference in partial derivatives over the region \( D \) inside \( C \). Namely, \[ \oint_{C} M \, dx + N \, dy = \iint_{D} \left( \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} \right) \, dA \] Key applications of Green's Theorem:
- Transforming line integrals into area integrals, which are often easier to calculate.
- Confirming the circulation and flux of vector fields over a region.
Conservative Vector Fields
A vector field is considered conservative if it is the gradient of some scalar field. This means that for a vector field \( \mathbf{F} = (M, N) \), there exists a potential function \( f \) such that \( \mathbf{F} = abla f \). To check whether a given vector field is conservative, we use specific conditions:
- The curl of the vector field must be zero in two dimensions. This translates mathematically to \( \frac{\partial N}{\partial x} = \frac{\partial M}{\partial y} \).
- The domain of the vector field must be simply connected, meaning it has no holes.
Closed Paths
A closed path in calculus is a path where the start and end points are the same. When dealing with line integrals, the closed path plays a crucial role, especially if the vector field is conservative. For a conservative vector field:
- The line integral over any closed path is independent of the path and depends only on the endpoints. Since the endpoints coincide in a closed path, the integral evaluates to zero.