Chapter 16: Problem 29
Circulation and flux Find the circulation and flux of the fields $$ \mathbf{F}_{1}=x \mathbf{i}+y \mathbf{j} \quad \text { and } \quad \mathbf{F}_{2}=-y \mathbf{i}+x \mathbf{j} $$ around and across each of the following curves. a. The circle \(\mathbf{r}(t)=(\cos t) \mathbf{i}+(\sin t) \mathbf{j}, \quad 0 \leq t \leq 2 \pi\) b. The ellipse \(\mathbf{r}(t)=(\cos t) \mathbf{i}+(4 \sin t) \mathbf{j}, \quad 0 \leq t \leq 2 \pi\)
Short Answer
Step by step solution
Understanding Circulation
Calculate Circulation for Field \( \mathbf{F}_1 \) on Circle
Calculate Circulation for Field \( \mathbf{F}_2 \) on Circle
Calculate Circulation for Field \( \mathbf{F}_1 \) on Ellipse
Calculate Circulation for Field \( \mathbf{F}_2 \) on Ellipse
Understanding Flux
Calculate Flux for Field \( \mathbf{F}_1 \) across Circle
Calculate Flux for Field \( \mathbf{F}_2 \) across Circle
Calculate Flux for Field \( \mathbf{F}_1 \) across Ellipse
Calculate Flux for Field \( \mathbf{F}_2 \) across Ellipse
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Field
In this exercise, we look at two different vector fields:
- **\(\mathbf{F}_1 = x \mathbf{i} + y \mathbf{j}\):** This field points outward from the origin, as each vector is aligned with the coordinate pair \((x, y)\) it corresponds to.
- **\(\mathbf{F}_2 = -y \mathbf{i} + x \mathbf{j}\):** This field, on the other hand, produces vectors that are always perpendicular to those of \(\mathbf{F}_1\), swirling around the origin.
Line Integral
for flux, they describe the field's action across the path.
Mathematically, the line integral of a vector field \(\mathbf{F}\) over a curve \(C\) is expressed as \( \oint_C \mathbf{F} \cdot d\mathbf{r} \). Here, \(d\mathbf{r}\) is the differential element of the curve, resembling tiny vectors that run tangent to the curve.
In simpler terms, imagine walking along a path with a wind blowing in a particular direction. The line integral would provide the total wind experienced during this journey. If the path is closed, forming a loop, the line integral gives the circulation, indicating how strongly the field encourages motion around that loop.
Closed Curve
In our exercise, both the circle and the ellipse are closed curves:
- The **circle** is given by the parametric equations \(\mathbf{r}(t) = (\cos t) \mathbf{i} + (\sin t) \mathbf{j}\), with \(0 \leq t \leq 2\pi\) indicating a full revolution.
- The **ellipse**, on the other hand, has the parametric form \(\mathbf{r}(t) = (\cos t) \mathbf{i} + (4 \sin t) \mathbf{j}\), stretching the circle in the \(\mathbf{j}\) direction.
Studying these interactions on closed curves allows us to explore more complex geometric and physical properties of the fields involved.