Chapter 16: Problem 23
Calculate the net outward flux of the vector field $$\mathbf{F}=x y \mathbf{i}+\left(\sin x z+y^{2}\right) \mathbf{j}+\left(e^{r y^{2}}+x\right) \mathbf{k}$$ over the surface \(S\) surrounding the region \(D\) bounded by the planes \(y=0, z=0, z=2-y\) and the parabolic cylinder \(z=1-x^{2}\) .
Short Answer
Expert verified
The net outward flux is the result of the volume integral with \(\nabla \cdot \mathbf{F} = 3y\) over \(D\).
Step by step solution
01
Understand the Region and its Boundary
We first need to understand the region of integration. The planes given are \(y=0\) (a plane parallel to the xz-plane), \(z=0\) (the xy-plane), and \(z=2-y\) (a plane that intersects along a line). Additionally, the parabolic cylinder \(z=1-x^2\) implies the region is below the parabola. These constraints define a bounded region \(D\).
02
Apply Divergence Theorem
To calculate net outward flux using Gauss's divergence theorem, calculate the volume integral of the divergence of \(\mathbf{F}\) over the region \(D\). The divergence theorem relates this volume integral to the net outward flux across the surface \(S\) enclosing \(D\). It states: \[ \iint_S \mathbf{F} \cdot d\mathbf{S} = \iiint_D abla \cdot \mathbf{F} \, dV \]
03
Compute Divergence of \(\mathbf{F}\)
Calculate the divergence \(abla \cdot \mathbf{F}\) of the vector field \(\mathbf{F}\). By taking the partial derivatives: \(\frac{\partial (xy)}{\partial x} + \frac{\partial (\sin xz + y^2)}{\partial y} + \frac{\partial (e^{y^2} + x)}{\partial z}\). Therefore, \(abla \cdot \mathbf{F} = y + 2y + 0 = 3y\).
04
Set Up the Boundary $ abla \cdot \mathbf{F}$ Integral
With \(abla \cdot \mathbf{F} = 3y\), compute the triple integral over \(D\). The integral bounds are derived from the intersection of the planes and the parabolic cylinder: \(0 \leq y \leq 2\), solving for \(x\) in \(-1 \leq x \leq 1\), and \(0 \leq z \leq \min{(2-y, 1-x^2)}\).
05
Execute the Triple Integral
Calculate: \[ \iiint_D 3y \, dV = \int_0^2 \int_{-1}^{1} \int_0^{\min{(2-y,1-x^2)}} 3y \, dz \, dx \, dy. \] First integrate with respect to \(z\), then \(x\), and finally \(y\), simplifying the expression as needed.
06
Solve the Integral
Carry out the integration step-by-step:\[\int_0^2 \int_{-1}^{1} [3y(z)]_0^{\min{(2-y,1-x^2)}} \, dx \, dy\]. This simplifies to \(\int_0^2 \int_{-1}^{1} 3y \min{(2-y,1-x^2)} \, dx \, dy\). Execute the required integrals over respective ranges and calculate the numerical values.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Field
A vector field is a mathematical construct where each point in space is associated with a vector. These vectors can represent different physical quantities, such as force, velocity, or magnetic fields. In the context of the given problem, we have the vector field \( \mathbf{F} = x y \mathbf{i} + (\sin x z + y^{2}) \mathbf{j} + (e^{y^2} + x) \mathbf{k} \).
Each component of the vector field is a function that depends on the variables \( x, y, \) and \( z \).
Each component of the vector field is a function that depends on the variables \( x, y, \) and \( z \).
- \( x y \mathbf{i} \): This part indicates that the \( i \)-component (or \( x \)-direction) varies with the product of \( x \) and \( y \).
- \( \sin x z + y^2 \mathbf{j} \): Here, the \( j \)-component (or \( y \)-direction) depends on the sine of the product \( xz \) combined with \( y^2 \).
- \( e^{y^2} + x \mathbf{k} \): For the \( k \)-component (or \( z \)-direction), it is influenced by an exponential function \( e^{y^2} \) and the variable \( x \).
Net Outward Flux
The net outward flux is a measure of how much of the vector field passes out through a closed surface. It often relates to the physical concept of how much of a field, like a fluid or gas, leaves a given volume space. Using the Divergence Theorem allows us to convert a challenging surface integral into a simpler volume integral.
The Divergence Theorem states that the net outward flux of a vector field across a closed surface \( S \) is equal to the triple integral of the divergence of the field over the volume \( D \) enclosed by \( S \).
The Divergence Theorem states that the net outward flux of a vector field across a closed surface \( S \) is equal to the triple integral of the divergence of the field over the volume \( D \) enclosed by \( S \).
- Mathematically, this is represented as: \[ \iint_S \mathbf{F} \cdot d\mathbf{S} = \iiint_D abla \cdot \mathbf{F} \, dV. \]
- The theorem simplifies computations by allowing evaluation over volume rather than dealing with complex surface integrals directly.
- This holds valid under conditions where the vector field and the boundary share specific continuity properties.
Triple Integral
The triple integral is a powerful tool used to evaluate volumes and other properties in three-dimensional spaces. It is essential for finding the volume of region \( D \) when evaluating questions involving spatial regions and vector fields.
In our exercise, the region \( D \) is defined by several boundaries, and the divergence of the vector field is integrated over this region. The expression to consider is:
In our exercise, the region \( D \) is defined by several boundaries, and the divergence of the vector field is integrated over this region. The expression to consider is:
- \[ \iiint_D 3y \, dV = \int_0^2 \int_{-1}^{1} \int_0^{\min{(2-y,1-x^2)}} 3y \, dz \, dx \, dy. \]
- First, establish the bounds for each variable.
For example, \( y \) ranges from 0 to 2, \( x \) spans from -1 to 1, and \( z \) will vary based on the imposed conditions. - Integrate in the order of the nested integrals, usually starting with the innermost integral and moving outward.
- Simplify the expression after each integration step to ease subsequent calculations.
Parabolic Cylinder
A parabolic cylinder is a type of surface that extends infinitely in one direction while having a curved parabolic cross-section in the other two dimensions. The equation \( z = 1 - x^2 \) represents such a structure within our problem context.
- In three-dimensional space, this implies that for a fixed \( z \) level, the cross-section of this surface is a parabola in the \( xz \)-plane.
- The parabolic cylinder divides space, acting as one of the bounds for the region \( D \), defined together with other planes like \( z = 0 \) and \( z = 2 - y \).
- The volume under the surface occupies the space where the parabola lies above \( x \) within the specified limits, influenced further by the constraint \( 0 \leq z \leq \min{(2 - y, 1 - x^2)} \).