Chapter 15: Problem 26
Find the volumes of the regions. The wedge cut from the cylinder \(x^{2}+y^{2}=1\) by the planes \(z=-y\) and \(z=0\)
Short Answer
Expert verified
The volume of the wedge is \(\frac{2}{3}\) cubic units.
Step by step solution
01
Understand the Region of Integration
The region is a wedge formed by a cylinder and bounded by two planes. The cylinder is described by the equation \(x^2 + y^2 = 1\), which indicates a circle of radius 1 in the \(xy\)-plane centered at the origin. The volume is cut by the planes \(z = -y\) and \(z = 0\). The plane \(z = 0\) is the \(xy\)-plane itself, and \(z = -y\) is a slanted plane.
02
Set Up the Integral
The integration will be done in cylindrical coordinates which simplifies the process. In cylindrical coordinates, the cylinder is described by \(r = 1\), and we integrate over \(r, \theta, z\). The limits for \(z\) will be from \(z = 0\) to \(z = -r\sin\theta\) (i.e., \(-y\) in cylindrical coordinates). The limits for \(\theta\) need to cover the wedge, which is symmetric about the \(y\)-axis. This gives the limits \(\theta = 0\) to \(\theta = \pi\). Lastly, \(r\) ranges from 0 to 1. The volume integral becomes:\[\int_{0}^{\pi} \int_{0}^{1} \int_{0}^{-r\sin \theta} r \, dz \, dr \, d\theta\]
03
Evaluate the Integral with Respect to \(z\)
Perform the integration with respect to \(z\) first. Since the limits for \(z\) are from 0 to \(-r\sin \theta\), the integration becomes:\[\int_{0}^{-r\sin \theta} r \, dz = r \left[ z \right]_{0}^{-r\sin \theta} = r (-r\sin \theta) = -r^2 \sin \theta\]
04
Integrate with Respect to \(r\)
Now integrate the result of the \(z\)-integration with respect to \(r\) over the interval from 0 to 1:\[\int_{0}^{1} -r^2 \sin \theta \, dr = \sin \theta \left[ -\frac{r^3}{3} \right]_{0}^{1} = \sin \theta \left( -\frac{1}{3} \right)\]
05
Integrate with Respect to \(\theta\)
Finally, integrate with respect to \(\theta\) from 0 to \(\pi\):\[\int_{0}^{\pi} -\frac{1}{3} \sin \theta \, d\theta = -\frac{1}{3} \left[ -\cos \theta \right]_{0}^{\pi} = -\frac{1}{3} \left( 1 + 1 \right) = -\frac{1}{3} \times 2 = -\frac{2}{3}\]
06
Interpret the Negative Sign
The negative sign in the result means we should consider the absolute volume displaced. Thus, the volume of the region between the specified planes is \(\frac{2}{3}\) units cubed.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cylindrical Coordinates
The concept of cylindrical coordinates is a valuable tool for solving problems involving symmetric shapes such as cylinders, cones, or spheres. These coordinates are similar to polar coordinates, adding the third dimension to describe locations in three-dimensional space. Cylindrical coordinates use three values:
- \( r \): the radial distance from the origin.
- \( \theta \): the angle measured from the positive x-axis.
- \( z \): the height above the xy-plane.
Triple Integration
Triple integration, in this context, is a method to calculate volumes of three-dimensional objects. In this exercise, the integral setup uses cylindrical coordinates. We calculate volume by integrating the height of small volume elements over a region. The region of integration determines the bounds of our integral. The process involves
- Identifying the innermost integral, which corresponds to the variable with the smallest range, in this case, \(z\), followed by
- The next integral for \(r\), and finally
- The outermost integral for \(\theta\).
Bounded Regions
Understanding the concept of bounded regions is crucial for accurately calculating volumes in multivariable calculus. A bounded region is an enclosed area by certain surfaces or planes within a space. For this exercise, the region is defined where the cylinder intersects with two planes, forming a wedge shape. The surfaces comprise:
- A cylindrical surface defined by \(x^2 + y^2 = 1\) or \(r = 1\), forming a round wall.
- The plane \(z = 0\), representing the base of the wedge.
- The slanted plane \(z = -y\), which translates to \(z = -r \sin \theta\) in cylindrical coordinates, creating an inclined top.