/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 Find the value of \(\partial x /... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the value of \(\partial x / \partial z\) at the point \((1,-1,-3)\) if the equation $$x z+y \ln x-x^{2}+4=0$$ defines \(x\) as a function of the two independent variables \(y\) and \(z\) and the partial derivative exists.

Short Answer

Expert verified
The value of \( \frac{\partial x}{\partial z} \) at \((1,-1,-3)\) is \( \frac{1}{5} \).

Step by step solution

01

Differentiate the equation with respect to z

Given the function \( xz + y \ln x - x^2 + 4 = 0 \), differentiate implicitly with respect to \( z \). The derivative of \( xz \) is \( x + z \frac{\partial x}{\partial z} \) because \( x \) is a function of \( z \). \( y \ln x \) and \( 4 \) have no \( z \) terms, so their derivative is zero. Differentiate \( -x^2 \) with respect to \( z \), which gives \(-2x \frac{\partial x}{\partial z} \). Set up the equation: \[ x + z \frac{\partial x}{\partial z} - 2x \frac{\partial x}{\partial z} = 0. \]
02

Solve for \( \frac{\partial x}{\partial z} \)

Isolate \( \frac{\partial x}{\partial z} \) in the equation from Step 1. Rearrange to: \[ z \frac{\partial x}{\partial z} - 2x \frac{\partial x}{\partial z} = -x. \] Factor out \( \frac{\partial x}{\partial z} \): \[ \frac{\partial x}{\partial z} (z - 2x) = -x. \] Solve for \( \frac{\partial x}{\partial z} \): \[ \frac{\partial x}{\partial z} = \frac{-x}{z - 2x}. \]
03

Substitute the point \((1, -1, -3)\) into the equation

Substitute \( x = 1 \), \( y = -1 \), and \( z = -3 \) into the expression for \( \frac{\partial x}{\partial z} \). Since we found \( \frac{\partial x}{\partial z} = \frac{-x}{z - 2x} \), substitute these values to find: \[ \frac{\partial x}{\partial z} = \frac{-1}{-3 - 2(1)} = \frac{-1}{-3 - 2} = \frac{-1}{-5} = \frac{1}{5}. \]
04

Verify the computation

Ensure that the differentiation and substitution were completed accurately. Verify by checking initial expressions and substituting back into the equation with given values. The point satisfies the original equation, and computations align, confirming that \( \frac{\partial x}{\partial z} = \frac{1}{5} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Implicit Differentiation
Implicit differentiation is a powerful technique used when dealing with complex equations that involve several variables. Instead of isolating one variable before taking a derivative, we differentiate every term directly, assuming the presence of implicit relationships between the variables. This comes in handy for equations like the given one, where isolating a single variable algebraically may be difficult or impossible.

To use this technique effectively, perform the following steps:
  • Identify which variable you are differentiating with respect to, in this case, it's variable \( z \).
  • Treat other variables, such as \( x \) and \( y \), as implicit functions of \( z \). This means, when dividing mixed terms, don't forget to apply chain rule derivatives.
  • Combine the derivatives to form an equation that implicitly defines the derivative of interest.
For our function \( xz + y \ln x - x^2 + 4 = 0 \), taking the derivative with respect to \( z \) involves applying these principles. Each term is differentiated, keeping track of where \( x \) itself depends on \( z \). The process leads to an equation that allows you to solve for \( \frac{\partial x}{\partial z} \), which represents the implicit change of \( x \) when \( z \) changes.
Multivariable Calculus
Multivariable calculus extends traditional calculus to functions of more than one variable. It is essential when studying systems where several components influence each other, like in the function provided where \( x, y, \) and \( z \) all intertwine.

In this context, partial derivatives help us understand how a multivariable function changes as one specific variable changes. Crucially, it enables us to model real-world phenomena more accurately, as systems rarely depend on a single factor.

When approaching multivariable calculus problems:
  • Consider the function's dependency on each variable. A change in one may not be completely independent of the others.
  • Use tools like partial derivatives to isolate how changes in a single variable influence the whole function.
  • In problems involving implicit differentiation, apply derivatives across the function while maintaining a multivariable perspective.
The given equation uses multivariable calculus to resolve the dynamics between \( x \), \( y \), and \( z \). By treating \( x \) as a function of both \( y \) and \( z \), we apply calculus principles across multiple dimensions while solving for \( \frac{\partial x}{\partial z} \).
Functions of Several Variables
Functions of several variables represent relationships where output values depend on more than one input variable. They are foundational in multivariable calculus, enabling us to describe and manipulate complex systems mathematically.

These functions may look like \( f(x, y, z) \), indicating each of \( x, y, \) and \( z \) contribute to the output. Understanding these functions is crucial in disciplines like physics, engineering, economics, and any field requiring sophisticated modeling.

Here are some key ideas when working with such functions:
  • Recognize the dependent relationships among variables. For instance, "How does a small change in \( z \) affect \( x \)?"
  • Use partial derivatives to isolate and quantify these dependencies.
  • Visualize these changes using geometric tools, like graphs representing surfaces and lines.
In the exercise, recognizing \( x \) as a function of not just one, but two variables (\( y \) and \( z \)), exemplifies these concepts. By analyzing how changes in \( z \) could potentially alter \( x \), we apply the theory of functions of several variables, making use of their intricate dependencies to address real-world questions.

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