/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Display the values of the functi... [FREE SOLUTION] | 91Ó°ÊÓ

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Display the values of the functions in Exercises \(37-48\) in two ways: (a) by sketching the surface \(z=f(x, y)\) and \((b)\) by drawing an assortment of level curves in the function's domain. Label each level curve with its function value. $$ f(x, y)=\sqrt{x^{2}+y^{2}+4} $$

Short Answer

Expert verified
The surface is an upward opening paraboloid-like shape, and the level curves are concentric circles centered at the origin, with increasing radius as function values increase.

Step by step solution

01

Understand the Function

The given function is \(f(x, y) = \sqrt{x^2 + y^2 + 4}\). This represents a surface in three-dimensional space. The equation consists of a square root of a sum that includes \(x^2\), \(y^2\), and 4.
02

Sketch the Surface

To sketch the surface \(z = f(x, y)\), visualize it as a 3D shape. It is similar to a paraboloid but offset along the z-axis due to the constant 4 under the square root. The surface opens upwards with its lowest point at \((0, 0, 2)\), given \(f(0, 0) = 2\). You can picture it gradually increasing in height as \(x\) or \(y\) moves away from zero.
03

Determine Level Curves

Level curves are cross-sections of the surface at constant z-values. Substitute \(z = c\) in the function to form \(c = \sqrt{x^2 + y^2 + 4}\). Squaring both sides, \(c^2 = x^2 + y^2 + 4\). Rearranging gives \(x^2 + y^2 = c^2 - 4\).
04

Draw Level Curves I

For various \(c\) values, you can calculate the radius of each level curve. For example, if \(c = 2\), \(x^2 + y^2 = 0\) represents the origin. For \(c = 3\), \(x^2 + y^2 = 5\), a circle of radius \(\sqrt{5}\). The level curves are circles centered at the origin with increasing radius as \(c\) increases.
05

Draw and Label Level Curves II

Continue drawing level curves for other values such as \(c = 4, 5, 6, \dots\). The respective radii are \(\sqrt{12}, \sqrt{21},\) and so on. Label each curve with its corresponding \(c\) value, noting that each circle is an intersection of the plane \(z = c\) with the surface.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Level Curves
Level curves are an engaging way to understand multivariable functions in 3D space. They are essentially slices of a surface where the function value remains constant. For the function \(f(x, y) = \sqrt{x^2 + y^2 + 4}\), these curves tell us what the cross-section of the surface looks like at a fixed height \(z\).
To find level curves, we set \(z = c\), leading to the equation \(c^2 = x^2 + y^2 + 4\). By rearranging, we derive \(x^2 + y^2 = c^2 - 4\). This represents a circle's equation with its center at the origin.
Each value of \(c\) gives us a different circle, with the radius \(\sqrt{c^2 - 4}\). The higher the value of \(c\), the larger the circle. Thus, these level curves elegantly illustrate how the surface expands as we move up along the \(z\)-axis.
Visualizing Functions
Visualizing functions in three dimensions can initially feel challenging, but it's crucial for understanding complex multivariable functions. The function \(f(x, y) = \sqrt{x^2 + y^2 + 4}\) can be pictured as a 3D shape, resembling a paraboloid. However, this shape is unique due to its elevation by the constant 4 in the square root, giving it a lifted appearance above the xy-plane.
Imagine standing at point \((0, 0, 2)\) on the surface. This is the lowest elevation as \(z = 2\) when both \(x\) and \(y\) are zero. As you move away from the origin, whether in the direction of increasing \(x\) or \(y\), the surface slopes upward.
Using graphs or computer simulations can greatly aid in visualizing this function. They provide a dynamic view of how the surface stretches and curves, giving a better grasp of how variables interact to influence function values in 3D space.
Multivariable Functions
Multivariable functions involve two or more variables, making them versatile and applicable in many real-world contexts. For instance, the function \(f(x, y) = \sqrt{x^2 + y^2 + 4}\) depends on both \(x\) and \(y\), showing how changes in these variables affect the overall function value \(z\).
In practical applications, such functions can represent diverse phenomena, such as temperature variations across a region or changes in elevation on a landscape. They are integral to fields like physics, engineering, and economics.
At a basic level, each input pair \((x, y)\) on a multivariable function outputs a specific value \(z\), delivering insight into relationships among variables. This concept is extended by considering gradients or partial derivatives, further enriching our understanding and allowing us to study how small changes in \(x\) or \(y\) locally affect \(z\).
Ultimately, understanding multivariable functions expands one's ability to model and solve complex problems where two or more factors are in play, highlighting their importance in advanced mathematical studies.

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Most popular questions from this chapter

In Exercises \(61-64,\) find an equation for the level surface of the function through the given point. $$ g(x, y, z)=\sqrt{x^{2}+y^{2}+z^{2}}, \quad(1,-1, \sqrt{2}) $$

You will explore functions to identify their local extrema. Use a CAS to perform the following steps: a. Plot the function over the given rectangle. b. Plot some level curves in the rectangle. c. Calculate the function's first partial derivatives and use the CAS equation solver to find the critical points. How do the critical points relate to the level curves plotted in part (b)? Which critical points, if any, appear to give a saddle point? Give reasons for your answer. d. Calculate the function's second partial derivatives and find the discriminant \(f_{x x} f_{y y}-f_{x y}^{2}\) . e. Using the max-min tests, classify the critical points found in part (c). Are your findings consistent with your discussion in part (c)? $$f(x, y)=x^{2}+y^{3}-3 x y, \quad-5 \leq x \leq 5, \quad-5 \leq y \leq 5$$

Estimating maximum error Suppose that \(T\) is to be found from the formula \(T=x\left(e^{y}+e^{-y}\right),\) where \(x\) and \(y\) are found to be 2 and \(\ln 2\) with maximum possible errors of \(|d x|=0.1\) and \(|d y|=0.02 .\) Estimate the maximum possible error in the computed value of \(T .\)

Find the linearization \(L(x, y, z)\) of the function \(f(x, y, z)\) at \(P_{0} .\) Then find an upper bound for the magnitude of the error \(E\) in the approximation \(f(x, y, z) \approx L(x, y, z)\) over the region \(R\) $$ \begin{array}{l}{f(x, y, z)=x^{2}+x y+y z+(1 / 4) z^{2} \quad \text { at } \quad P_{0}(1,1,2)} \\ {R :|x-1| \leq 0.01, \quad|y-1| \leq 0.01, \quad|z-2| \leq 0.08}\end{array} $$

Cobb-Douglas production function During the 1920 s, Charles Cobb and Paul Douglas modeled total production output \(P\) (of a firm, industry, or entire economy) as a function of labor hours involved \(x\) and capital invested \(y\) (which includes the monetary worth of all buildings and equipment). The Cobb- Douglas production function is given by $$P(x, y)=k x^{\alpha} y^{1-\alpha},$$ where \(k\) and \(\alpha\) are constants representative of a particular firm or economy. a. Show that a doubling of both labor and capital results in a doubling of production \(P .\) b. Suppose a particular firm has the production function for \(k=\) 120 and \(\alpha=3 / 4 .\) Assume that each unit of labor costs \(\$ 250\) and each unit of capital costs \(\$ 400,\) and that the total expenses for all costs cannot exceed \(\$ 100,000 .\) Find the maximum production level for the firm.

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