/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Display the values of the functi... [FREE SOLUTION] | 91Ó°ÊÓ

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Display the values of the functions in Exercises \(37-48\) in two ways: (a) by sketching the surface \(z=f(x, y)\) and \((b)\) by drawing an assortment of level curves in the function's domain. Label each level curve with its function value. $$ f(x, y)=1-|y| $$

Short Answer

Expert verified
The surface has a V-shape along \(y\) and horizontal lines for level curves within \(-1 \le y \le 1\).

Step by step solution

01

Sketch the Surface of the Function

We are given the function \( f(x, y) = 1 - |y| \). This function represents a surface in 3D space. To sketch it, observe that there is no \(x\) dependence; for any fixed \(x\), the surface is a V-shaped structure in the \(y-z\) plane, where the vertex of the V is at \((y, z) = (0, 1)\). The surface decreases linearly with increasing or decreasing \(y\) with a slope of -1, reaching zero at \(|y| = 1\), and becoming undefined for \(|y| > 1\). The surface is uniform along the \(x\)-axis.
02

Draw Level Curves

Level curves are the intersections of the surface with planes of constant \(z\). Let \(z = c\), then \(c = 1 - |y|\), solving for \(y\) gives \(|y| = 1 - c\). Therefore, \(y = \pm (1 - c)\). For \(-1 \le c \le 1\), plot these linear level curves in the \(xy\) plane.Each \(c\) corresponds to two parallel lines \(y = 1 - c\) and \(y = -(1 - c)\), spaced symmetrically about the x-axis and labeled with their respective \(c\) value. Example curves: - For \(z = 0.5\), level curves are \(y = 0.5\) and \(y = -0.5\). - For \(z = 1\), the level curve is \(y = 0\). - For \(z = 0\), level curves are \(y = 1\) and \(y = -1\).No level curves exist for \(z < 0\) or \(z > 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

3D surfaces
In multivariable calculus, 3D surfaces are a graphical representation of a function involving two independent variables. These surfaces exist in three-dimensional space and can be visualized as a vast tarp stretched over a landscape of peaks and valleys. For the function \( f(x, y) = 1 - |y| \), the surface is notably characterized by its V-shaped appearance. This shape arises because the function only depends on the variable \( y \) and not on \( x \).

The surface remains consistent along the \( x \)-axis, as there is no \( x \) component affecting the function's output. This means every cross-section parallel to the \( y-z \) plane looks identical, regardless of where along the \( x \)-axis it is taken. As you observe the function, you will notice that for any fixed \( x \), the surface forms a V structure symmetric about the \( z \)-axis. The vertex of this V is at \( (y, z) = (0, 1) \), where the function reaches its maximum value of 1.

Beyond the vertex, as \( y \) increases or decreases, the value of \( z \) descends equally until it reaches zero when \( |y| = 1 \). Past this point, the function does not exist as it becomes undefined, signaling the end of the surface's domain.
level curves
Level curves, sometimes referred to as contour lines, illustrate sections of a 3D surface at constant heights (or function values \( z \)). In our case, these curves give us a more manageable way to visualize the behavior of \( f(x, y) = 1 - |y| \). By setting \( z = c \), we find lines in the \( xy \)-plane that correspond to specific heights on the surface. This is done by solving \( c = 1 - |y| \), leading to the equation \( |y| = 1 - c \).

Each level \( c \) translates into two linear level curves described by \( y = 1 - c \) and \( y = -(1 - c) \). These are perfectly symmetric and locate themselves equidistant from the \( x \)-axis. For instance, if \( z \) is set to 0.5, then the corresponding lines are \( y = 0.5 \) and \( y = -0.5 \), making them easy to plot just by marking points in the \( xy \)-plane.

Level curves can help in understanding not just where the function's value changes, but also the rate at which these changes occur. Here, the spacing between level curves along the \( y \)-axis gives a clue about how the surface slopes downwards to cross exact \( z \) values like 0 or negative values, where no curves appear.
absolute value function
The absolute value function, denoted as \( |y| \), plays a crucial role in many mathematical expressions, including our function \( f(x, y) = 1 - |y| \). The absolute value of a number represents its distance from zero on the number line, stripping away any negative sign to turn all values non-negative.

This property is visible in our function’s behavior where it modifies \( y \) to always be positive or zero before performing any further calculation. Hence, regardless of whether we input a positive or negative \( y \), the output from \( |y| \) remains the same, defining the extensive symmetry we see in the V-shape of the surface and its level curves.

In this context, without the absolute value, we wouldn't achieve the same set restrictions within the boundaries \( |y| \leq 1 \). This inherent symmetry helps us predict and analyze results easily, seeing that any operations within the function apply uniformly to both positive and negative domains of \( y \). This steadies the visualization process, turning what could be a complex curve into a distinctly straightforward, symmetrical surface.

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