Chapter 14: Problem 41
Find the linearizations \(L(x, y, z)\) of the functions at the given points. $$ f(x, y, z)=\sqrt{x^{2}+y^{2}+z^{2}} \quad \text {at} $$ $$ \text { a. }(1,0,0) \quad \text { b. }(1,1,0) \quad \text { c. }(1,2,2) $$
Short Answer
Expert verified
The linearizations are: a. \( L(x, y, z) = x \), b. \( L(x, y, z) = \sqrt{2} + \frac{1}{\sqrt{2}}(x-1) + \frac{1}{\sqrt{2}}(y-1) \), c. \( L(x, y, z) = 3 + \frac{1}{3}(x-1) + \frac{2}{3}(y-2) + \frac{2}{3}(z-2) \).
Step by step solution
01
Understand the Function and Linearization
The function given is \( f(x,y,z) = \sqrt{x^2 + y^2 + z^2} \). Linearization is the approximation of a function around a point using the first-order Taylor expansion. For any function \( f(x, y, z) \), the linearization at a point \( (a, b, c) \) is given by \( L(x, y, z) = f(a, b, c) + f_x(a, b, c)(x-a) + f_y(a, b, c)(y-b) + f_z(a, b, c)(z-c) \). Here, \( f_x \), \( f_y \), and \( f_z \) are the partial derivatives of \( f \).
02
Compute Partial Derivatives
Compute the partial derivatives of \( f(x,y,z) \):- \( f_x = \frac{x}{\sqrt{x^2 + y^2 + z^2}} \)- \( f_y = \frac{y}{\sqrt{x^2 + y^2 + z^2}} \)- \( f_z = \frac{z}{\sqrt{x^2 + y^2 + z^2}} \)
03
Linearization at Point (1, 0, 0)
Calculate the value of \( f \) at point \((1, 0, 0)\):- \( f(1, 0, 0) = \sqrt{1^2 + 0^2 + 0^2} = 1 \)- \( f_x(1, 0, 0) = \frac{1}{1} = 1 \)- \( f_y(1, 0, 0) = \frac{0}{1} = 0 \)- \( f_z(1, 0, 0) = \frac{0}{1} = 0 \)Thus, the linearization is \( L(x,y,z) = 1 + 1(x-1) = x \).
04
Linearization at Point (1, 1, 0)
Calculate the value of \( f \) at point \((1, 1, 0)\):- \( f(1, 1, 0) = \sqrt{1^2 + 1^2 + 0^2} = \sqrt{2} \)- \( f_x(1, 1, 0) = \frac{1}{\sqrt{2}} \)- \( f_y(1, 1, 0) = \frac{1}{\sqrt{2}} \)- \( f_z(1, 1, 0) = 0 \)Thus, the linearization is \( L(x,y,z) = \sqrt{2} + \frac{1}{\sqrt{2}}(x-1) + \frac{1}{\sqrt{2}}(y-1) \).
05
Linearization at Point (1, 2, 2)
Calculate the value of \( f \) at point \((1, 2, 2)\):- \( f(1, 2, 2) = \sqrt{1^2 + 2^2 + 2^2} = 3 \)- \( f_x(1, 2, 2) = \frac{1}{3} \)- \( f_y(1, 2, 2) = \frac{2}{3} \)- \( f_z(1, 2, 2) = \frac{2}{3} \)Thus, the linearization is \( L(x,y,z) = 3 + \frac{1}{3}(x-1) + \frac{2}{3}(y-2) + \frac{2}{3}(z-2) \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Derivatives
Partial derivatives are a fundamental concept in calculus, particularly when dealing with functions of more than one variable. When we have a multivariable function like our example function, \( f(x, y, z) = \sqrt{x^2 + y^2 + z^2} \), we can look at how small changes in each variable affect the function's value. Partial derivatives are defined as the derivative of a function with respect to one of its variables while keeping the other variables constant. For instance:
- \( f_x \) is the derivative of \( f \) with respect to \( x \), treating \( y \) and \( z \) as constants.
- \( f_y \) is the derivative with respect to \( y \), treating \( x \) and \( z \) as constants.
- \( f_z \) is the derivative with respect to \( z \), treating \( x \) and \( y \) as constants.
First-Order Taylor Expansion
The first-order Taylor expansion is a mathematical technique used to approximate the value of a multivariable function near a given point. It is especially useful for linearizing functions. The essence of the technique is extending the idea of a tangent line to higher dimensions.For a given function \( f(x, y, z) \), its linearization around a point \((a, b, c)\) is expressed as:\[L(x, y, z) = f(a, b, c) + f_x(a, b, c)(x-a) + f_y(a, b, c)(y-b) + f_z(a, b, c)(z-c)\]Here:
- \( f(a, b, c) \) is the function's value at the point where we're linearizing.
- \( f_x(a, b, c) \), \( f_y(a, b, c) \), and \( f_z(a, b, c) \) are the partial derivatives of the function evaluated at \((a, b, c)\).
- The terms \((x-a)\), \((y-b)\), and \((z-c)\) represent small deviations from the point \((a, b, c)\).
Multivariable Calculus
Multivariable calculus extends the principles of calculus to functions of several variables. Unlike single-variable calculus, it deals with functions such as \( f(x, y, z) = \sqrt{x^2 + y^2 + z^2} \) that depend on more than one variable. This branch of calculus opens up new possibilities and tools such as:
- Partial Derivatives: They allow us to explore how a function changes along each variable independently.
- Gradients and Directional Derivatives: These provide deeper insights into the function's behavior, indicating directions of fastest increase.
- Linearization and Taylor Expansion: Used to approximate and simplify functions around specific points.