Chapter 14: Problem 31
Zero directional derivative of \(f(x, y)=x y+y^{2}\) at \(P(3,2)\) equal to zero?
Short Answer
Expert verified
The directional vector \((-7, 2)\) makes the directional derivative zero at \(P(3, 2)\).
Step by step solution
01
Calculate the Gradient
To find the gradient of the function \( f(x, y) = xy + y^2 \), compute the partial derivatives with respect to \( x \) and \( y \). We have: \( f_x = y \) and \( f_y = x + 2y \). Therefore, the gradient is \( abla f = (y, x + 2y) \).
02
Evaluate the Gradient at P(3, 2)
Substitute \( x = 3 \) and \( y = 2 \) into the gradient: \( abla f(3, 2) = (2, 3 + 2(2)) = (2, 7) \).
03
Understand Zero Directional Derivative Condition
The directional derivative is zero when the gradient is orthogonal to the direction vector \( \mathbf{v} \). This is true when the dot product \( abla f \cdot \mathbf{v} = 0 \).
04
Determine the Direction Vector
Let the direction vector be \( \mathbf{v} = (a, b) \). The directional derivative formula gives \( abla f \cdot \mathbf{v} = 2a + 7b = 0 \).
05
Solve for the Direction Vector
From \( 2a + 7b = 0 \), solve for one variable: \( a = -\frac{7}{2}b \). This gives the family of vectors orthogonal to the gradient, such as \( (a, b) = (-7, 2) \).
06
Verify the Solution
Verify that \( (-7, 2) \) makes the directional derivative zero by checking \( abla f \cdot (-7, 2) = 2(-7) + 7(2) = 0 \). This confirms orthogonality.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gradient Vector
In calculus, the gradient vector is a crucial concept used to understand how a function changes at each point in space. For a function of two variables, such as \( f(x, y) = xy + y^2 \), the gradient vector \( abla f \) is constructed using the partial derivatives. These partial derivatives are the rates of change of the function concerning each of its variables. In our example:
- \( f_x \), the partial derivative with respect to \( x \), is \( y \).
- \( f_y \), the partial derivative with respect to \( y \), is \( x + 2y \).
Orthogonality
Orthogonality is a concept used to determine if two vectors are perpendicular to each other. Two vectors are orthogonal if their dot product is zero. In the context of directional derivatives, orthogonality plays a crucial role because if the gradient vector \( abla f \) is orthogonal to a direction vector \( \mathbf{v} \), it means that moving in the direction of \( \mathbf{v} \) does not increase or decrease the function value. This results in the directional derivative being zero.To determine orthogonality between the gradient vector and the direction vector \( \mathbf{v} = (a, b) \) at point \( P(3, 2) \), we compute the dot product:
- \( abla f(3, 2) = (2, 7) \).
- The dot product with the direction vector is \( 2a + 7b = 0 \).
Partial Derivatives
Partial derivatives are a fundamental part of studying multivariable functions. They capture how a function changes with respect to one variable while keeping the other variables constant. For the function \( f(x, y) = xy + y^2 \),
- The partial derivative \( f_x = y \) implies that when you change \( x \) slightly, the function's change is directly proportional to \( y \).
- Similarly, \( f_y = x + 2y \) indicates that the change in the function as \( y \) changes depends on both \( x \) and \( y \).