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Find the linearization \(L(x, y)\) of the function at each point. $$ f(x, y)=x^{2}+y^{2}+1 \text { at } \quad \text { a. }(0,0), \quad \text { b. }(1,1) $$

Short Answer

Expert verified
At (0,0): \(L(x,y) = 1\); At (1,1): \(L(x,y) = 2x + 2y - 1\).

Step by step solution

01

Understand the Function

We need to find the linearization of the function \( f(x, y) = x^2 + y^2 + 1 \) at specific points. Linearization is the process of approximating a function near a given point using its tangent plane.
02

Calculate Partial Derivatives

Calculate the partial derivatives of \( f \) with respect to \( x \) and \( y \).\( f_x(x, y) = \frac{\partial}{\partial x}(x^2 + y^2 + 1) = 2x \)\( f_y(x, y) = \frac{\partial}{\partial y}(x^2 + y^2 + 1) = 2y \)
03

Linearization Formula

The linearization \( L(x, y) \) of \( f(x, y) \) at a point \((x_0, y_0)\) is given by:\[ L(x, y) = f(x_0, y_0) + f_x(x_0, y_0)(x - x_0) + f_y(x_0, y_0)(y - y_0) \]
04

Linearization at (0,0)

Plug the point \((0, 0)\) into the formula:- \( f(0, 0) = 0^2 + 0^2 + 1 = 1 \)- \( f_x(0, 0) = 2 \times 0 = 0 \)- \( f_y(0, 0) = 2 \times 0 = 0 \)Thus, the linearization \( L(x, y) = 1 + 0\cdot(x-0) + 0\cdot(y-0) = 1 \).
05

Linearization at (1,1)

Plug the point \((1, 1)\) into the formula:- \( f(1, 1) = 1^2 + 1^2 + 1 = 3 \)- \( f_x(1, 1) = 2 \times 1 = 2 \)- \( f_y(1, 1) = 2 \times 1 = 2 \)Thus, the linearization \( L(x, y) = 3 + 2(x-1) + 2(y-1) = 2x + 2y - 1 \).
06

Conclusion

The linearization of the function \( f(x, y) \) is \( L(x, y) = 1 \) at \((0,0)\) and \( L(x, y) = 2x + 2y - 1 \) at \((1,1)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Partial derivatives are crucial in understanding the behavior of multivariable functions like our given function, \( f(x, y) = x^2 + y^2 + 1 \). A partial derivative measures how a function changes as only one of the variables changes, while keeping the other variables constant.
In our function, we have two variables: \(x\) and \(y\). Therefore, we calculate two partial derivatives:
  • \( f_x(x, y) \) is the partial derivative with respect to \(x\):
    \( \frac{\partial}{\partial x}(x^2 + y^2 + 1) = 2x \)
  • \( f_y(x, y) \) is the partial derivative with respect to \(y\):
    \( \frac{\partial}{\partial y}(x^2 + y^2 + 1) = 2y \)
These derivatives represent the slope of the function in the \(x\) and \(y\) directions, respectively.
They help us understand how the function's value changes as we make small movements along the axes. This is essential for setting up the tangent plane, which serves as the function's linear approximation near a specific point.
Tangent Plane Approximation
The tangent plane approximation is a technique in multivariable calculus used to approximate a function near a given point. This is particularly useful in estimating function values without carrying out complex calculations.
The approximation can be expressed using the linearization formula:
  • \( L(x, y) = f(x_0, y_0) + f_x(x_0, y_0)(x - x_0) + f_y(x_0, y_0)(y - y_0) \)
This equation can be visualized as taking the change in function value at \((x_0, y_0)\) and adding suitable changes in the \(x\) and \(y\) directions based on partial derivatives.
For instance, at the point \((0, 0)\), \( f(x, y) = 1 \) and both derivatives are zero, meaning the plane is flat with \( L(x, y) = 1 \) for any small movements near \((0, 0)\).
In contrast, at \((1, 1)\), the function value \( f(x, y) = 3 \) and each change in \(x\) or \(y\) leads to increases in the function indicated by the positive slopes \(2x\) and \(2y\), giving \( L(x, y) = 2x + 2y - 1 \).
Multivariable Calculus
Multivariable calculus extends concepts from single-variable calculus to functions of several variables.
It is a broad branch which includes studying functions with more than one input like our function \( f(x, y) = x^2 + y^2 + 1 \).
Key topics include partial derivatives, as discussed earlier, as well as concepts like multiple integrals and vector calculus.
Working with multivariable functions can be challenging due to the complex interaction between variables.
  • Visualizing data: Often involves plotting in 3-D to see how the surface behaves.
  • Critical points: Finding max, min, or saddle points using gradients and Hessians.
Multivariable calculus is all about analyzing how these various factors come into play to influence the behavior of functions.
Understanding such relationships helps in fields ranging from physics and engineering to economics, where functions often depend on multiple variables.

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