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Find parametric equations for the line tangent to the curve of intersection of the surfaces at the given point. $$ \begin{array}{l}{\text { Surfaces: } x^{3}+3 x^{2} y^{2}+y^{3}+4 x y-z^{2}=0} \\\ {x^{2}+y^{2}+z^{2}=11} \\ {\text { Point: } \quad(1,1,3)}\end{array} $$

Short Answer

Expert verified
The tangent line is given by the parametric equations: \(x = 1 + 96t\), \(y = 1 - 96t\), and \(z = 3\).

Step by step solution

01

Understand the Problem

We are tasked to find parametric equations for the line tangent to the curve of intersection of the two given surfaces at a specified point: \((1, 1, 3)\). Both surfaces are algebraic equations in three variables (\(x, y, z\)).
02

Define the Functions

Consider the given surfaces as function equations: \( F(x, y, z) = x^3 + 3x^2y^2 + y^3 + 4xy - z^2 = 0 \) and \( G(x, y, z) = x^2 + y^2 + z^2 = 11 \). We are interested in the curve of intersection.
03

Find Gradients of Surfaces

The gradient vectors \(abla F\) and \(abla G\) at any point give the directions perpendicular to the surfaces. Calculate \(abla F = (3x^2 + 6xy^2 + 4y, 6x^2y + 3y^2 + 4x, -2z)\) and \(abla G = (2x, 2y, 2z)\).
04

Evaluate Gradients at the Given Point

Compute \(abla F (1,1,3) = (13, 13, -6)\) and \(abla G (1,1,3) = (2, 2, 6)\). These vectors are normal to the surfaces at the point \((1, 1, 3)\).
05

Find Tangent Vector

The direction of the tangent line to the intersection curve can be found by taking the cross product of the gradients \(abla F\) and \(abla G\). Calculate this cross product: \((13, 13, -6) \times (2, 2, 6) = (96, -96, 0)\).
06

Write Parametric Equations

With point \((1, 1, 3)\) and direction vector \((96, -96, 0)\), the parametric equations are \(x = 1 + 96t\), \(y = 1 - 96t\), and \(z = 3\).
07

Verify Parametric Line

Ensure the direction vector \((96, -96, 0)\) satisfies both gradient constraints: it's orthogonal to both \(abla F\) and \(abla G\) at their respective points.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parametric Equations
Parametric equations are a powerful tool for describing lines and curves in mathematics. They allow us to express points on a line or curve as functions of a parameter, typically denoted as \( t \). For lines in three-dimensional space, parametric equations usually take the form:
  • \( x(t) = x_0 + at \)
  • \( y(t) = y_0 + bt \)
  • \( z(t) = z_0 + ct \)
where \((x_0, y_0, z_0)\) is a specific point on the line, and \((a, b, c)\) is the direction vector indicating how the line extends into space.
This approach simplifies the process of finding and examining tangent lines especially for curves defined by the intersection of surfaces. By using parametric equations, we can identify all points on the line by varying \( t \), which makes it easier to study the behavior of curves in 3D space.
Gradient Vectors
Gradient vectors are essential in understanding the directions in which a function changes most rapidly. When dealing with functions of several variables, the gradient vector \( abla F \) of a function \( F(x, y, z) \) is defined as:
  • \( abla F = \left( \frac{\partial F}{\partial x}, \frac{\partial F}{\partial y}, \frac{\partial F}{\partial z} \right) \)
The components of the gradient vector are the partial derivatives, representing the rates of change of the function along the \( x, y, \) and \( z \) directions, respectively.
In the context of 3D surfaces, this vector indicates the direction in which the surface rises most steeply. Hence, for any given point on a surface, its gradient vector is perpendicular to the surface at that point.
This property is utilized when finding tangent lines through the intersection of two surfaces, as the tangent direction is orthogonal to the normal vectors represented by the gradients.
Cross Product
The cross product is a mathematical operation in vector algebra particularly useful in three-dimensional space. Given two vectors \( \mathbf{A} = (a_1, a_2, a_3) \) and \( \mathbf{B} = (b_1, b_2, b_3) \), their cross product \( \mathbf{A} \times \mathbf{B} \) results in a new vector that is perpendicular to both \( \mathbf{A} \) and \( \mathbf{B} \):
  • \( \mathbf{A} \times \mathbf{B} = (a_2b_3 - a_3b_2, a_3b_1 - a_1b_3, a_1b_2 - a_2b_1) \)
This operation is crucial when dealing with the intersection of 3D surfaces.
To find the tangent line to the curve where two surfaces intersect, we calculate the cross product of their respective gradient vectors at a specific point. This resulting vector gives the direction of the tangent line, as it is perpendicular to the normal vectors of both surfaces.
Understanding the cross product allows us to determine how surfaces interact in 3D space.
3D Surfaces
3D surfaces are often described by equations in three variables, \( x, y, \) and \( z \). These define geometric shapes in three-dimensional space, like planes, spheres, or more complex structures.
When two surfaces intersect, they form a curve. Studying the properties, such as tangents, of these curves requires understanding the surfaces involved. Each surface can be thought of as a collection of points for which the defining equation holds true.
In exercises involving 3D surfaces, it is crucial to find how their interactions produce curves and where to look for important features like tangent lines. This often involves:
  • Identifying each surface's equation
  • Finding points of intersection
  • Using calculus tools like gradients
Masters of these concepts can analyze complex surfaces in engineering, physics, and graphics.

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