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In Exercises \(13-16,\) find and sketch the level curves \(f(x, y)=c\) on the same set of coordinate axes for the given values of \(c .\) We refer to these level curves as a contour map. $$ f(x, y)=x y, \quad c=-9,-4,-1,0,1,4,9 $$

Short Answer

Expert verified
The level curves for \( f(x, y) = xy \) are hyperbolas (and the axes for \( c=0 \)) for varying positive and negative \( c \) values.

Step by step solution

01

Understanding the Level Curves

A level curve for a function \( f(x, y) = c \) represents the set of points \((x, y)\) for which the function value is constant, \( c \). We need to find and sketch these curves for various values of \( c \).
02

Setting Up the Equation

Given the function \( f(x, y) = xy \), each level curve is defined by the equation \( f(x, y) = c \Rightarrow xy = c \). Substitute each value of \( c \) into this equation.
03

Solve for Each Constant Value of c

For each given \( c \, (-9,-4,-1,0,1,4,9) \), solve the equation \( xy = c \):- For \( c = 0 \), the level curve is \( xy = 0 \), which corresponds to the x-axis and y-axis together.- For \( c = -9, -4, -1 \), we have \( xy = -9, -4, -1 \), resulting in hyperbolas opening in opposite quadrants.- For \( c = 1, 4, 9 \), we have \( xy = 1, 4, 9 \), resulting in hyperbolas opening in the first and third quadrants.
04

Sketch the Curves

To sketch each level curve, note:- Hyperbolas corresponding to positive \( c \) values appear in the first and third quadrants and are similar in shape but vary in steepness.- Hyperbolas for negative \( c \) values appear in the second and fourth quadrants.- The axes (x-axis and y-axis) define the level curve for \( c = 0 \).
05

Finalizing the Sketch

On the same set of coordinate axes, sketch the hyperbolas for each \( c \). This could be done by noting symmetry and the shape difference between curves. Use a clear notation to show positive and negative curves.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Contour Map
A contour map is a graphical representation where level curves of a function are plotted in one plane. These curves represent the set of points where the function has the same constant value, often referred to as "contours". In this exercise, the different contour plots correspond to the values the function, specifically the multiplication of two variables, can take. A contour map allows for an easy visualization of how a function behaves over a range of values.

For instance, if we consider the function of two variables, such as our function defined as \(f(x, y) = xy\), the different level curves are plotted for several values of \(c\). A contour map helps to quickly identify the different regions of the function corresponding to the different level sets. By sketching these curves on one set of axes, we can see all the curves simultaneously, making it easy to understand how the function behaves across its domain.
Hyperbolas
When plotting a function like \(f(x, y) = xy = c\), the resulting shapes for \(c eq 0\) are hyperbolas. Hyperbolas are types of conic sections that appear as opposite-facing curves on a coordinate plane. They typically occur when a function of two variables forms an expression like \(xy=c\).

In our exercise, the hyperbolas that form are distinguished by whether \(c\) is positive or negative. For negative values of \(c\), hyperbolas open towards the second and fourth quadrants. For positive values of \(c\), they appear in the first and third quadrants. These hyperbolas demonstrate symmetry around the origin, and the steepness depends on the absolute value of \(c\).

It's also notable that for \(c = 0\), the level curve is simply where \(xy=0\), which corresponds to the axes themselves, meaning the x-axis and y-axis.
Coordinate Axes
The coordinate axes, which consist of the x-axis and y-axis, play an essential role in the sketching of level curves. They serve as a reference frame in which the shapes, like our hyperbolas, can be drawn and understood. The axes also serve a specific function in our particular problem.

When \(c = 0\), the level curve for \(xy = c\) is coincident with the coordinate axes themselves, because the product \(xy = 0\) either needs \(x=0\) or \(y=0\). Hence, it leads to two lines on the plane — the x-axis and y-axis. This uniqueness stems from the fact that multiplying any number by zero yields zero, highlighting the importance of understanding the function in the context of its axes.

Understanding the orientation and the position of these axes helps in sketching and interpreting the curves correctly, noting where they intersect or align with the axes across the various values of \(c\).
Function of Two Variables
A function of two variables is an equation that takes two input values and produces a single output value. In mathematical terms, this type of function is expressed as \(f(x, y)\). Functions of two variables have a wide array of applications in fields such as physics, engineering, economics, and more.

In this context, our function is \(f(x, y) = xy\). Such a function implies that for any pair \((x, y)\), the product \(xy\) yields a particular value. The level curve aspect of this function illustrates how different constant outputs (\(c\) values) shape the geometry of the level curves.

Working with functions of two variables requires comfort with graphical analysis because they often cannot be simplified to a graph of just one variable. Visualizing these functions means dropping down one dimension to produce contour maps, which can represent complex 3D surfaces as 2D visuals. The key aspect is to understand how these two variables interact to form these surfaces, as observed in their level curves.

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Most popular questions from this chapter

Maximizing a utility function: an example from economics In economics, the usefulness or utility of amounts \(x\) and \(y\) of two capital goods \(G_{1}\) and \(G_{2}\) is sometimes measured by a function \(U(x, y) .\) For example, \(G_{1}\) and \(G_{2}\) might be two chemicals a pharmaceutical company needs to have on hand and \(U(x, y)\) the gain from manufacturing a product whose synthesis requires different amounts of the chemicals depending on the process used. If \(G_{1}\) costs \(a\) dollars per kilogram, \(G_{2}\) costs \(b\) dollars per kilogram, and the total amount allocated for the purchase of \(G_{1}\) and \(G_{2}\) together is \(c\) dollars, then the company's managers want to maximize \(U(x, y)\) given that \(a x+b y=c .\) Thus, they need to solve a typical Lagrange multiplier problem. Suppose that $$U(x, y)=x y+2 x$$ and that the equation \(a x+b y=c\) simplifies to $$2 x+y=30.$$ Find the maximum value of \(U\) and the corresponding values of \(x\) and \(y\) subject to this latter constraint.

Locating a radio telescope You are in charge of erecting a radio telescope on a newly discovered planet. To minimize interference, you want to place it where the magnetic field of the planet is weakest. The planet is spherical, with a radius of 6 units. Based on a coordinate system whose origin is at the center of the planet, the strength of the magnetic field is given by \(M(x, y, z)=6 x-\) \(y^{2}+x z+60 .\) Where should you locate the radio telescope?

Estimating maximum error Suppose that \(T\) is to be found from the formula \(T=x\left(e^{y}+e^{-y}\right),\) where \(x\) and \(y\) are found to be 2 and \(\ln 2\) with maximum possible errors of \(|d x|=0.1\) and \(|d y|=0.02 .\) Estimate the maximum possible error in the computed value of \(T .\)

You will explore functions to identify their local extrema. Use a CAS to perform the following steps: a. Plot the function over the given rectangle. b. Plot some level curves in the rectangle. c. Calculate the function's first partial derivatives and use the CAS equation solver to find the critical points. How do the critical points relate to the level curves plotted in part (b)? Which critical points, if any, appear to give a saddle point? Give reasons for your answer. d. Calculate the function's second partial derivatives and find the discriminant \(f_{x x} f_{y y}-f_{x y}^{2}\) . e. Using the max-min tests, classify the critical points found in part (c). Are your findings consistent with your discussion in part (c)? $$f(x, y)=x^{2}+y^{3}-3 x y, \quad-5 \leq x \leq 5, \quad-5 \leq y \leq 5$$

Use a CAS to perform the following steps implementing the method of Lagrange multipliers for finding constrained extrema: a. Form the function \(h=f-\lambda_{1} g_{1}-\lambda_{2} g_{2},\) where \(f\) is the function to optimize subject to the constraints \(g_{1}=0\) and \(g_{2}=0\) . b. Determine all the first partial derivatives of \(h\) , including the partials with respect to \(\lambda_{1}\) and \(\lambda_{2},\) and set them equal to \(0 .\) c. Solve the system of equations found in part (b) for all the unknowns, including \(\lambda_{1}\) and \(\lambda_{2}\) . d. Evaluate \(f\) at each of the solution points found in part (c) and select the extreme value subject to the constraints asked for in the exercise. Determine the distance from the line \(y=x+1\) to the parabola \(y^{2}=x .\) (Hint: Let \((x, y)\) be a point on the line and \((w, z)\) a point on the parabola. You want to minimize \((x-w)^{2}+(y-z)^{2}.)\)

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