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Find the velocity and acceleration vectors in terms of \(\mathbf{u}_{r}\) and \(\mathbf{u}_{\theta} .\) \begin{equation}r=e^{a \theta} \quad \text { and } \quad \frac{d \theta}{d t}=2\end{equation}

Short Answer

Expert verified
Velocity: \( 2ae^{a\theta} \mathbf{u}_r + 2e^{a\theta} \mathbf{u}_\theta \); Acceleration: \( 4a^2e^{a\theta} \mathbf{u}_r + 8ae^{a\theta} \mathbf{u}_\theta \).

Step by step solution

01

Differentiate to Find Velocity Components

We start by finding the radial velocity component \( v_r \). The radial position is given by \( r = e^{a\theta} \). The radial velocity is the derivative of \( r \) with respect to time \( t \):\[\frac{dr}{dt} = \frac{dr}{d\theta} \cdot \frac{d\theta}{dt}\]Using \( \frac{dr}{d\theta} = ae^{a\theta} \) and \( \frac{d\theta}{dt} = 2 \), we find:\[v_r = \frac{dr}{dt} = ae^{a\theta} \cdot 2 = 2ae^{a\theta}\]
02

Calculate Angular Velocity Component

The angular velocity component \( v_\theta \) can be found using the formula \( v_\theta = r\frac{d\theta}{dt} \). Substituting the given values:\[v_\theta = e^{a\theta} \cdot 2 = 2e^{a\theta}\]
03

Formulate the Velocity Vector

The velocity vector in terms of \( \mathbf{u}_r \) and \( \mathbf{u}_\theta \) is given by:\[\mathbf{v} = v_r \mathbf{u}_r + v_\theta \mathbf{u}_\theta = 2ae^{a\theta} \mathbf{u}_r + 2e^{a\theta} \mathbf{u}_\theta\]
04

Differentiate to Find Radial Acceleration Component

The radial acceleration component \( a_r \) can be found by differentiating \( v_r \):\[a_r = \frac{d}{dt}(2ae^{a\theta}) = 2a \cdot \frac{d}{dt}(e^{a\theta})\]Using \( \frac{d}{dt}(e^{a\theta}) = ae^{a\theta} \cdot 2 \), we get:\[a_r = 2a^2e^{a\theta}\cdot 2 = 4a^2e^{a\theta}\]
05

Calculate Angular Acceleration Component

The angular acceleration component \( a_\theta \) can be found using the formula \( a_\theta = r\frac{d^2\theta}{dt^2} + 2\frac{dr}{dt}\frac{d\theta}{dt} \). Since \( \frac{d^2\theta}{dt^2} = 0 \), we have:\[a_\theta = 2 \cdot 2ae^{a\theta} \cdot 2 = 8ae^{a\theta}\]
06

Formulate the Acceleration Vector

The acceleration vector in terms of \( \mathbf{u}_r \) and \( \mathbf{u}_\theta \) is:\[\mathbf{a} = a_r \mathbf{u}_r + a_\theta \mathbf{u}_\theta = 4a^2e^{a\theta} \mathbf{u}_r + 8ae^{a\theta} \mathbf{u}_\theta\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Vector in Polar Coordinates
In polar coordinates, the velocity vector describes how quickly an object moves and the direction it travels along the radial and angular axes. The velocity vector consists of two components: the radial velocity, denoted as \( v_r \), and the angular velocity, denoted as \( v_\theta \). The radial velocity \( v_r \) reflects how fast the object is moving towards or away from the origin, while the angular velocity \( v_\theta \) indicates how fast the object is going around the origin.

To find these components, we differentiate the radial position function \( r = e^{a\theta} \) with respect to time \( t \).
  • Radial Velocity: We use the chain rule, obtaining \( \frac{dr}{dt} = \frac{dr}{d\theta} \cdot \frac{d\theta}{dt} \), which simplifies to \( v_r = 2ae^{a\theta} \).
  • Angular Velocity: It is found by multiplying the radial position by the rate of change of \( \theta \), so \( v_\theta = r \cdot \frac{d\theta}{dt} = 2e^{a\theta} \).

Finally, the velocity vector \( \mathbf{v} \) is expressed in terms of the basis vectors \( \mathbf{u}_r \) and \( \mathbf{u}_\theta \) as \( \mathbf{v} = 2ae^{a\theta} \mathbf{u}_r + 2e^{a\theta} \mathbf{u}_\theta \). This defines the overall speed and movement direction in the polar coordinate system, combining how fast an object moves radially and angularly.
Acceleration Vector in Polar Coordinates
The acceleration vector in polar coordinates reveals how an object's velocity changes over time. Similar to velocity, acceleration comprises radial and angular components. The radial acceleration \( a_r \) shows the rate of change of the radial speed, while the angular acceleration \( a_\theta \) indicates the rate at which the angular speed changes.

To compute these components, we differentiate the velocity expressions obtained earlier.
  • Radial Acceleration: By differentiating the radial velocity \( v_r = 2ae^{a\theta} \), we find \( a_r = 4a^2e^{a\theta} \).'
  • Angular Acceleration: It is given by \( a_\theta = r \cdot \frac{d^2\theta}{dt^2} + 2 \cdot \frac{dr}{dt} \cdot \frac{d\theta}{dt} \). Since \( \frac{d^2\theta}{dt^2} = 0 \), the formula simplifies to \( a_\theta = 8ae^{a\theta} \).

The complete acceleration vector \( \mathbf{a} \) in polar coordinates is written as \( \mathbf{a} = 4a^2e^{a\theta} \mathbf{u}_r + 8ae^{a\theta} \mathbf{u}_\theta \). Understanding these components helps determine how an object's speed and direction evolve in time in the context of a polar reference frame.
Differentiation and Its Role
Differentiation plays a crucial role in calculating velocity and acceleration in polar coordinates. It is the mathematical process used to find the rate at which one quantity changes with respect to another, which is essential in dynamics to understand motion.

  • By differentiating the radial position \( r = e^{a\theta} \) with respect to \( t \), we determine how quickly the distance from the origin changes over time, giving us the radial velocity \( v_r \). This applies the chain rule: first differentiating \( r \) with respect to \( \theta \) and then multiplying by \( \frac{d\theta}{dt} \).
  • Similarly, differentiating the velocity components leads us to the acceleration components. This continues to use the chain rule, as seen in finding \( a_r \), and ensures all temporal dynamics are accurately captured.

This process of differentiation, particularly using the chain rule, demonstrates how calculus facilitates the transition from static functions to dynamic motions, making it foundational in the context of understanding vector calculus in polar coordinates.

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