Chapter 12: Problem 44
In Exercises \(41-46,\) find the distance between points \(P_{1}\) and \(P_{2}\) $$P_{1}(3,4,5), \quad P_{2}(2,3,4)$$
Short Answer
Expert verified
The distance is \( \sqrt{3} \).
Step by step solution
01
Understand the Problem
We need to find the distance between two points in a 3-dimensional space, given their coordinates. These points are \( P_1(3, 4, 5) \) and \( P_2(2, 3, 4) \).
02
Recall the Distance Formula
In 3D space, the distance \( d \) between two points \( (x_1, y_1, z_1) \) and \( (x_2, y_2, z_2) \) is given by the formula:\[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}\]
03
Substitute the Coordinates
Substitute the coordinates of \( P_1 \) and \( P_2 \) into the distance formula: \[d = \sqrt{(2 - 3)^2 + (3 - 4)^2 + (4 - 5)^2}\]
04
Calculate the Differences
Calculate the differences of each coordinate: - For \( x \): \( 2 - 3 = -1 \) - For \( y \): \( 3 - 4 = -1 \) - For \( z \): \( 4 - 5 = -1 \).
05
Square the Differences
Square each of the differences to eliminate negative signs:- \((-1)^2 = 1\)- \((-1)^2 = 1\)- \((-1)^2 = 1\).
06
Sum the Squares
Add the squared differences together: \[1 + 1 + 1 = 3\]
07
Find the Square Root
Take the square root of the sum from Step 6 to find the distance:\[d = \sqrt{3}\]
08
Conclusion
The distance between points \( P_1(3, 4, 5) \) and \( P_2(2, 3, 4) \) is \( \sqrt{3} \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
3D Geometry
Three-dimensional geometry is the branch of mathematics that deals with objects in 3-dimensional space. Unlike two-dimensional geometry, which we commonly encounter with shapes on a flat surface, 3D geometry involves objects that have depth in addition to height and width.
Imagine a room where you can move not just along the floor but also up and down. This extra dimension adds a level of complexity and fascination. For students, understanding 3D geometry introduces a new way to visualize space and how objects relate to each other in that space.
Some important characteristics of 3D space include:
Imagine a room where you can move not just along the floor but also up and down. This extra dimension adds a level of complexity and fascination. For students, understanding 3D geometry introduces a new way to visualize space and how objects relate to each other in that space.
Some important characteristics of 3D space include:
- Three coordinate axes: x, y, and z
- Geometric objects like points, lines, and planes
- Physical properties such as volume and surface area
Coordinate System
The coordinate system in 3D geometry allows us to locate any point in space using a set of three numbers. Each number corresponds to a point's position along one of the three-dimensional axes (x, y, and z). This system is fundamental to graphing and analyzing geometric problems in three dimensions.
In a typical 3D coordinate system:
- For \( P_1(3, 4, 5) \), 3 is the x-coordinate, 4 is the y-coordinate, and 5 is the z-coordinate.
- For \( P_2(2, 3, 4) \), 2, 3, and 4 are the x, y, and z coordinates respectively.
This method straightforwardly extends our understanding from 2D to 3D, and is essential for distance calculations and other geometric assessments in three-dimensional space.
In a typical 3D coordinate system:
- The x-axis runs left to right.
- The y-axis runs front to back.
- The z-axis runs up and down.
- For \( P_1(3, 4, 5) \), 3 is the x-coordinate, 4 is the y-coordinate, and 5 is the z-coordinate.
- For \( P_2(2, 3, 4) \), 2, 3, and 4 are the x, y, and z coordinates respectively.
This method straightforwardly extends our understanding from 2D to 3D, and is essential for distance calculations and other geometric assessments in three-dimensional space.
Distance Calculation
Finding the distance between two points in 3D space might first seem challenging, but it builds on concepts you might already know from 2D geometry. A well-known formula comes to our aid, enabling this calculation seamlessly by extending the Pythagorean Theorem into three dimensions.
To calculate the distance between two points, say \(P_1(x_1, y_1, z_1)\) and \(P_2(x_2, y_2, z_2)\), you can apply the 3D distance formula:\[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}\]
To calculate the distance between two points, say \(P_1(x_1, y_1, z_1)\) and \(P_2(x_2, y_2, z_2)\), you can apply the 3D distance formula:\[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}\]